1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* * * **      ** *  ** ****   
 *** **   ***  **  **  *    *  ** * *****  ****    
    {
  ***  *    * ****** **** *  ** ***   ** * *    * * ** (i=0; i<=strlen(string2)-1;i++)
 ******   *   **** *****    ***  ** *  ** ***  *  *  **   * 
**  ***  ***    ** * * **** *  * ** ***   * *       ***  *   ** *  *   *  *  *    *  *      * (string2[i]==string1[i])
  ***   *  *  * ***  *** ** *  *   * *  * * ***    ***       * ***  * * * ***  ** *  
   *  ** **  ******   *****   * *      ******** **  **   *   ** *** *   *    *   ** **  ** ******   * * *
**    *    * * ****    ** * *   **    ** **  **   ** ** *      *** *  ** ******
****  **   * ***  *******  *  ****  ** ***  * * ***   
  **  * ***  ***         * * * *** *****   *** ** *   
* ***** **     * **  *  * ******  *** **  ****   ***   * 
 *******     ** * *** **  ***  * ** ****  ***********    *  *     ***  *      *****  * **** is a prefix of %s", string2, string1);
      *  *   * *   **    ** **  ** **   **   ***  *
** ***  *  * *** * *   * * ****   * *  * **
 *  * * * * * *********    * ***  **  ** ** **   *  *  * *  * 
  * **  ** * *   **** ** * *   * **** * *  ** *** * ** *** *   *  ** *  *** *  ***  ** * ** is not a prefix of %s", string2, string1);
  *  *    *         ***   *** * *** * **  * ****  *  *   *
    }
** * *****  * * **  **  *  * ****      * *  *  *   *   *   *      * 
    {
** ***  *  * ***  *    *  *  *** *** **   *   *  (i=0; i<=strlen(string1)-1;i++)
** *   ** * *  **   * *  *****  * *** * **     *     *  * 
* *   ****  * ******** * ** ** * * *  **** ** **** ****** *   ** * ** *  *  *   (string2[i]==string1[i])
 *   * * *   ***  ****      *   ** *  **         * * ** ** **  * **  ***      
***  **  ** *  * * * * **** *******  ** *  ***    **    *   *** *    *  *  *** *    *  **  *   *  *    ****     **  
*** *   **  *           *****  * * *** *  **     ** *    *   ****   *        **   ** 
 ** *  ** *** ***   *  **  * * *****  *** ** *** *** *
 * * *  * ***      *  *** *   * *   ** *  ******    *** *
 ** **  ****** ***    *  *  * * * ***  * * ***   ****
 **  * *   * *  *  **   *** ***** *** ***  **** * ** *** **   ***** ** * * *  ** *  ** *  * is a prefix of %s", string1, string2);
  ** **    ***   * *  *   *** * *  ** **  *     ***   **
   ** * ****  **   ** ***      *    * * *** **  **  ******
  ****  * **   *     *    ******    *   * *****  
 **      * ****  ** * **** *  **    **  ***  * ** *     **   * *** ** ** * **   ****  * *     ** * is not a prefix of %s", string1, string2);
 * * * *  ***** **** * *  *   *    *** **   ** ******
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
****   *  * **  *** ****    * * * *    %s", chaine1,chaine2);
** * *  * **    *  **  *** *  *   *  ***   
 **   * * *  * ****  **   0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
     *  ** *** **  ****      lenght1,lenght2,c;
** *    *   **         ******   * b[100];
*** *  *   *  * **     * *  ** ** *** * a[100];
 * *** **     ** *  *  *   ** d[100];
**   **    * ** ** ** * ******  *   *  ***** ** **
  *  ****    * * ** **     *   * * **** * ** *
**** * ** *    *   ** *  **** ***  * *
  * *******  * *  *****    **   *   ** ****** 
*   ** * *   ** * * *  ** * *****  ******
 **   *      * *    **  **    
  ***   **  * *** * ** * *****   *****  **  *  is a prefix of %s",a,b);
** *  *** *     * **    **
**** * *    *  * * **  *   
  * *  *  * * **    *    *
  * ***  ** *     **  * **** ** * * **** ****     **        **   is not a prefix of %s",a,b);
 * ** *** *  **   * *******
  ** * ** **   *  * *****   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *    *    * 
#include  * *** **    ** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
********* *  * ** * i;
**  **  *** *       * ** *   *
  {
*** * *    * ** ******          *  * *    A[i]!='\0' && A[i]!=B[i]   )
***    * * * ** *** **** **  ** *** * **   * *   **   *     ******* ** 0;
*** **    * *   ** * * * **** *    *   **   *  **  *   
  ** ** *  * *   * **     * **  *    **  **     **** **** ******   **   *  ** **
  }
* *   ** * *** **   1;
}


int main()
{
 ***  ** * ** *   **  * *** * *** a[n],b[n],c[n];
**** * * ****** **    *   i;
** ** * * **  *  *** * * * *  * **  *    *  *  **
 *****    *      **** *       * *   *  * *  *    ***   ** * *
    * * ** * * ********   *    * (aa(a,b)){
  *   **   ****  *   ***  ****  ** * **  * * ****  **  * *** 
*      *   ****   * *   * **  ** ** * *  ****** *       **   * * *   *      *    *****  
******* *    ** * *       * * *    **** **  *    *     *  *  *  ***  *****  ** *    * ****   *   * * *****  *  
   *  *   *  **  *   *  *  *  ********  *  ** * ***  * * *******  *   * **    *** *

*** *    ** ***    **   *  * ** *   *   * ** *** ***   **
 *  *** *****  **  *****   *****   * *  ***  *** *** **  ****  *  is a prefix of %s",c,b);
  * **** ****   ** *** * 
* ***  *  ****   **   ** ****
**** *  **  * * *** **  **  **  * **** ****  * * *  * **  ***  *     ** is not a prefix of %s",a,b);
**  **   ***  * *    *    * * * *  ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** * *  ***
 * **   *       *   **
int main (){
char        
char   **** **
*   **  *  * * * string1: *  ** *  
 * **** ****  *  ******
  **    * **   string2: *  ** **
** ** **  ****  ***   ** 
* *    ** * *  * *  *
*   *** * * * * *** *  *  * ** * **   **  * is * ***  *** of  *   **** *  * ** ***
else
  * ** ****    *    * *    **   **** *    is not prefix of *    ***  *    ****

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  **    *
#include    *  ** *    
#include ** * * ** ** * 
#include ** *  **    *** 
int prefix(char p[],char s[])
{
 * ** ***   **     *  * * * *   ** * 
 * *    *    *  * *   ****   ****** 0;
      * *   *     ** * * if  **   *  *    * * 
*  *** *  *    *  *   ** *  *** ***  1;
*    *   *      * **      * 
 *  *** * * ** * ****   *   ** 0;
}

int main()
{
* *  *   * *  * * **    * p[999],s[999];
*** *   * ** *  * ***  * ****  **** **     ** 
 *** *  * ***   *** ******* **  ****  *  *

* *** **** * ***********    
   ****  *  ****  ** *    * * **** ** *** * is a prefix of %s",p,s);
   ***   ***** * ** *  
   ** ** **  *** * * * * *    * **  *** * is not a prefix of * *  *    

* ****  *** *   * *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *  *   *  *** 
int main()
{
*** **  *  * *   ** *    * * * length1,length2,c;
  * *** ****  ****  ** **** *   a[100];
*  **** * *** * ** **** *   *   * b[100];
  **    * *  *  *  *  *    * d[100];
 ** * *****  ** **  *  *  *   *  * ** **  *  *   
  ******    * *** *   ***  * *   * * * ****   ** ** *
*   *  *** *  ** **  * ** ***** *** ** *
**   *** *   *  * *   * ***   **** ** *
if (strcmp(a,d)==0)
*** *  *** *   ** **     ** ***
*    *  * *   ******* **** ** *     **  ** ** *  **** * *      *  * **  is a prefix of %s",a,b);
  ** * ** ** ****   ***       *
*** *  **** *  *   * * ***  *  
*   * * ******* * **   * 
*  * **  * * ***  ***  *    ***         *  *     *   ***  *** *  is not a prefix of %s",a,b);
  *     * **   ** *    *  *
   * *   * * *   ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *   ** * * ****
#include * *** ** * **  * 

int prefix (char  ***** * str2[])
{
 ** ** ***       *** * *    length=0,  ** *
   *  *    *   ***
  * * **  ** ******   * *   ** =     *****  * *
    *   *  *  ***  **  ***
*  * **** *    * * * *  * * ** **  *  ***
*  **       * * * *    *  *   ** *****  
** **** * ** ***  ** * **  *  ** * if   * ** ***  
*  ***         *   *  ** *       *  ** ** ** * *** ** * ****   
       * * ** **** * *    *** * **** *    }
* *****          **  *    *    *  *
 ** *  ****  **          (count == length)
*  *** *  **  * *   *  * ** **  *      1;
 * * ***   * * *** ** else  * ** *  **  0; ** * *  ** **  * *
***    ***     ** ****   * *   
}
int main(void)
{
  ** *  ****  ***** **  ** ** ** **** ***** **
*  * *** ****  ** * **   ***   
  **** * **** *****  * *** * * ** **  * **   *      str1, str2);

*** *   ** *  * **  * *** ****    *  
 *****    * * * * {
  *    *   **   ****    ** *    ** ****      * ** * *** *   * is a prefix of * * **  str1, str2);
  **     * ****  ** ** *  *
 *** **   ** ** * * ****  ***  
  ***   **     **  ***** * **********  ***** ****    ****   * ** *  is not a prefix of  *  ** * str1, str2);

   * * *  ** *  * *** *      *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** **  * **  *
#include   **  ***   
#include    ** *  *   **

int main()
{
 *   *  **  *  **  * ***     prefix[100];
  *  **   ** *** *    *******    word[100];
** * * ***   *** * **  * * ***    *  * %s", prefix, word);
  ** * * ** * *   **  * * *    i;
  ** *** * ** * *****  *****  = 0; i< strlen(prefix); ++i)
* *   *  ***** *    * *** 
*****  * ** *******   * ***     * ** * **   *   *   * *  *   *** 
 ****** **  *  ****  * *  * *****  ****  * *  **  
    * * **  *  **** * *** *** **  * * * *   *   * ** *  ******   * ***   **   * ** *** ** ***    *  is not a prefix of %s", prefix, word);
  * ** **  *   ****  ** ***** **** *** ***  *  ****    * *     *    * ***  * ***** *   * *  * 0;
* ***  *   ** ****  *** *   ***** * ****     ***     *  *** ** * **  
** * * * ** *  * * *   ****  *
***    *  * ** ** *   * * **        is a prefix of %s", prefix, word);
    * ***  ** ** ***** ** *** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *   **  **  *
#include * *  **   *****
#include * ** * * ******

int main()
{
     ** *  * ****         *  prefix[100];
* ** **** **  **   *** * ****  word[100];
  ** ***  *   *  **  *  ** ***  %s", prefix, word);
*** ***   ***    * * ** *  i;
**** *  ** *  **  *** * *  **  = 0; i< strlen(prefix); ++i)
 * **** *  **  *   *  **   *   *
   * *  *         *   * **   ****  *     *  ****  * *  * * ***  * *  ***
**  ************  *  *     ** ** * * * *** * **   ******
   * ** *** * * **  **    *     *  ****  ** *    ** **   ***     * **    *  **  *******  * *    is not a prefix of %s", prefix, word);
 *  *** **** ****    ****     *   ** *   **  * ** ** **      **  *   *** *** ****  **  * ***  *** 0;
  * *  * * *   * * * ***    * ** *****  * *   *   * * **
* *   *  **   *   *  * * *** *
  * * **      *  *** *   **        * *  is a prefix of %s", prefix, word);
 * *****  * * *  **        *   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**      ** * *    *** *  
 **    ****   *** *** **
 **   *  ***    * *   *

int main()
{
    ** ** **** char ** * *
     * *    char    *  *
   *  ** *   **    *  * * **** *       ** * word);
**  ** **   **  int i;
 **** * *   **  for(i = 0; ***  * **   *     ++i)
***    *  **     *  {
     **    **** *   ***    **  *    ** **** 
 *    **  *** * *  *  *    **   {
*  ** **  *****    ****   *  **  *    * * * ** ** **      ** * *  is not a    * of ********  * *  word);
** * ***   **** *        **  *  **** ** * **  * ** 0;
 **  *** *     ***  * ** *  }
          * * * }
 *  ** * *     **  *  ** *** * **  is a prefix of * *   ***   *   word);
****   *      *   * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.232
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users