0 like 1 dislike
11.9k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 11.9k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
** *** * *** * * *
* * *** ****** *

int main() {
**** * * * ** ********* ** *** * **
*** * *** ** *** * ** ** ** %f ** *** &a, &b, *****
* * * *** * * * * *** * * * *
***** ** ** * ** **** ** * * * {
** * ** *** * ** ** ** * * * **** ** * * *** **** *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** = * * ** ** = * ** * * * * a, b, c, (-b)/(2*a), * * ***** (-b)/(2*a), * ** **
* * * * **** ** ** **** * *
*** ** ** * *** if(d==0) {
*** * ******* * * ** *** **** * ** ** *** *** **
* * * * **** **** * **** ** *** **** * *** *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** a, b, c, x1);
*** * ** * * ** * *
* *** ** * * ** * * * {
** * * ******** * * *** * ** *** ** * * ***** **
** * * *** ** * *** *** *** * ** ** * * ** *** * **
**** * * * * * ** * *** * * * * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * = %.2f\nx2 = * ** *** a, b, c, x1, x2);
*** **** ** * * * * ****
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * ** *
**** * * *** ** *
#include *** * ** * ****

int main()
{
***** * * **** * *** * * ** **** * *
* * * ** ** **** ** **** *** * *** %f * * ** ** * **** **
** * * ** ** ** * * * **
** * * * *** *** * * * * *
* ** * ** ** ** ** *** ** * *
** ** * ** ** * * * **** * * **
* * * * ** * * * * ** * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** = %.2f\nx2 = ***** * **
* * ** * * ** * ** *** if(D==0)
*** * *** ** ** * *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * *** *
*** ******* * *
* ** * ** * * * * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** = * **** = ** ***** *** * ***** * ** * * * * * ***
* * ** * * *** * * **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** *
* ** * * *** * * **
** * * *****

int main()
{
* *** * * ***** * ** * * * * * * **
* * * ** * * * * *** ** ** * %f * ** ** * * ** *** ** * ****
** ****** * **** * * ** **
****** * *** * ***** * * **
** * *** * * ***** *** ** * * *** **
* * * * *** **** ** *** * *
** * * ** **** ***** ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** = %.2f\nx2 = ****** * **** * * **
** * * ** *** * ***** *** * *
** *** * * ** ** * * ** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** * *
* ** * * ** **** ** * *
** * * ** * * ******* * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * = %.2f + *** ** = %.2f - ** ***** **** **** * * ** * * ** ** ** *** **
** * **** * * * * ** **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
*************** * * ** * * ** a,b,c,x1,x2,D;
*** ***** * *** * ** *** * %f * **** * **** * ** ** ** ***
** *** * * ** **** ******
*** *** *** * ** * *** * = (-b + sqrt(D))/(2*a);
*** * * ** * * * ** = (-b - sqrt(D))/(2*a);
* * **** *** ** * ***** **
* ** *** * * * * * **** * ** *** * * ********
** * ***** * ** * * * ** * **** * * * ** ** * *** * ******* ****** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
********** ************* **** * ***** ** *** ** *** ** * ** **** = %.2f\n",x1);
** **** ** * * * * * **** * * * * *** * ** * **** ** **** * *** *** * * ** = %.2f",x2);
** * ** *** ** * ** ** * * ** ** *** * *
****** * *** ** * if(D==0)
* *** * *** * * ** * ** * ** * * **
* * *** **** ** ** **** * **** ** * * * **** * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** *** * * ** * * * ** * * * * ** * * * *** *** ** ** * * *** = x2 = %.2f",x1);
** ** * ** **** *** *** * * * ** *
*** * * ** ** **** * * **
* * * ** *** * ** **** * ** **** * * ** *
** ** ** ** * * * ** * * ** * ** **** ** ** ** * ** * * *** * ** ****** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
*** *** * * * * * * * **** ** *** * * ** ** ** *** ********** *** ** * *** = * * * * ** * *** *
* * ** * ** *** ** ** * * ****** ** *** * ** * * * * * * * * ** ** * ** * * * * = * * * ** ** * *** * ** * *
** * ** *** * *** * * ** * ****** ** * * * * *** *
** ** * * ** * ***** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** * ******** ******** *** a,b,c,x1,x2,D;
* *** *** * * * *** * ***** * * %f ** * ****** * ****
**** *** * * * * ** ** *** * *
* ** * * * ** * * = (-b + sqrt(D))/(2*a);
** ** * ** *** ****** * = (-b - sqrt(D))/(2*a);
** *** * *** * ** *** * * * ****
** * ** ***** *** * ***** ******* * * *** ** ***
* *** * * *** ** ** ** *** * ** * * * * *** **** *** * ** ****** ** * * ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * * * **** * * * * * * * ** * * ** * * ***** ***** ** * * ** ** = %.2f\n",x1);
* ** ** * * * * **** * ** ******* *** * * * * * * * *** ** *** **** * * = %.2f",x2);
** **** **** ***** *** *** * * *** ***** ****** **
*** * ** * * * ***** if(D==0)
* ** * * ** ** * ** * * **** * **** * *** ***
*** ** ** ****** *** ***** ** * ** * * * ** * *** * * ** * ** * ***** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
**** * ***** * ** ******* * **** * * * * *** ** ** *** * * ** ** ***** = x2 = %.2f",x1);
**** **** * * ****** * * * * * * ** ** *
** ** * *** *** *
* * * * * * * * * **** * * * *** * ** * ** *
* *** * *** *** **** *** * **** *** *** ** ** * * * *** * *** *** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * ** ** ** * *** *** *** * *** ** ** *** * ** * * * * * * ** * * *** * = * * * ** * * * *****
* * * * * ** * *** * ** * ** ** **** ***** * * *** *** * ***** = ** * *** **** * **** **
* **** ** ** **** * *** *** * *****
********* * ** ** * **** ** ** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
** ** ** ****
* *** * ** ** *** *
int main()
{
** ** **** *** * ** *** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * * * *** ****** * * *** ** * ** *** **

* * * * * * ** **** * *** * ** of %.2fx^2 + %.2fx +%.2f = 0 * ** ** * *
** *** * **** *** * * * = (b*b-4*a*c);
* * ** * ** * * * (D < 0)
*** * * * ** ** * *
* ** **** **** * * ** * complex and * * **** **
* * ** * * * * * **** *** **** = ** ******* *** ** * ** * * *
* * ***** * * ****** ** * *** *** = ** * * * * * * ** * *
* ***** ** * * ** *** * ** *
*** * ******* ** (D > 0)
*** * ** **** * * ** * *
* * *** **** * * * *** ** * real and ** * ** * *
** * * ** * ** * ** * = ** * * + sqrt(D))/(2*a));
** ** ** * ** * * ** * * * * ** = %.2f",(-b - sqrt(D))/(2*a));
* *** * ** **** * * * ** *
* * *** * ****** * * (D == 0)
* * *** ***** * *** ***
** * * * * *** * *** * * * * * * real and same\n");
**** ****** ** ** * * * * **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** ****** ** * *** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
****** ** * *
* * * * ** *
int main()
{
********** * * * *** ** a,b,c,D = 0,x1 = 0,x2 = 0;
** * *** * **** * * * * * * * ** * * **** * * **** *

* * * * * * * ** * ** * * ** * ** ** of %.2fx^2 + %.2fx +%.2f = 0 * *** **
* * ** *********** ** = (b*b-4*a*c);
********* ** * ** **** **** * (D < 0)
* * * *** * * * **
* *** * * * * ** ** complex and *** * * *** *
* * **** * ******** ** *** = ****** * *** ** * * **** ***
* * *** * * * * *** * * * *** * * = * ***** ** * * * * *****
****** * * * * *
** **** ** ** * ** * *** (D > 0)
* *** ** * *
** ** * ** * *** ****** * real and * ** * * ** *
* * * **** * * * * ** * * * ** ** = ** ***** + sqrt(D))/(2*a));
******* * ** **** * *** * ** = %.2f",(-b - sqrt(D))/(2*a));
* **** * * * * * *
* *** *** * ** ** * * (D == 0)
** *** **** * * *
* * * * * *** * *** ** real and same\n");
**** *** * * * ** * * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** *** * **** ** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** *** ** ** *
*** * ** * * **
int main()
{
** *** *** * ** ***** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * *** ** ***** ** * *** * * * ***** *** ** * * * **

**** * * * ** * * *** ** ** of %.2fx^2 + %.2fx +%.2f = 0 * ** **** *
** *** * * **** * = (b*b-4*a*c);
* **** ********* ** (D < 0)
* **** *** * ***
* * * * * * * * * * * * complex and * ** ***
****** ** ** ******* * ** * * = * ** * * * * ** *
* * **** * * ** * * * * * ** = ** ** ** * ******** **** **
* * ***** * * *** * ***
** * * * * ** * * * * (D > 0)
** * *** **** ** * * *
** * ** * **** * * *** *** ** real and * ** *** **
** ***** ** ****** **** = * * * ** * + sqrt(D))/(2*a));
* * ** * ****** ** * * * * * *** * = %.2f",(-b - sqrt(D))/(2*a));
** * *** * * * * * * **
*** * * * * ** * * ** (D == 0)
**** * **** * * * ** ** *
* * ** ** ***** * ** * ** ** * real and same\r\n");
* ** * * * ** ***** ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * ** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** ****** **
** ******* * * ***
int main()
{
* * * **** *** * * *** a,b,c,D = 0,x1 = 0,x2 = 0;
** *** ** * * ** **** * * * * * *** ** *** ** ***** *** ** ****

***** * ** ** * * *** **** ** * of %.2fx^2 + %.2fx +%.2f = 0 **** ****
* *** *** ** * **** * = (b*b-4*a*c);
**** * ** * ** * * ***** (D < 0)
* **** ****** * * *
** ****** * ** ** ** ** ** complex and * * * *
** * * * * * * * * ** * * * = *** ** * * *** ** * *
**** * *** * *** * * * ** * = ** ** **** ****
** *** ***** ** * * **
** ***** * *** * * * *** (D > 0)
* ** * ** *** * * **
*** ** *** ** ** * * * * ** ** * real and * ******* ** *
* ** * * * * ** *** * * ** = * ** * ** * * * + sqrt(D))/(2*a));
* * ** * * ** * * ** *** = %.2f",(-b - sqrt(D))/(2*a));
** **** *** ** * ** *
* * * * * *** * (D == 0)
* * * ** ** *** *** * **
** * *** * ** * ***** * ** * * real and same\r\n");
* ** * * *** **** **** * * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** *** * *** * * ******* *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * *** ** *
* * * *** * *
int main()
{
* *** * * * * *** ** a,b,c,D = 0,x1 = 0,x2 = 0;
** ** * *** * * * ****** * *** *** * *** * * ** ** * *

* * *** * * * ** ***** ** * *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** * ** ** * * * * *** = (b*b-4*a*c);
* ** * ***** ** ** * * = (-b + sqrt(D))/(2*a);
* * *** *** *** ** * = (-b - sqrt(D))/(2*a);
**** ** *** **** * (D < 0)
** * ** ** * *** * * * *
* ** * ** * *** * * * * complex and * * *** ***
* *** * * * ** **** * ** **** ** = *** ** ** ***** **** *
* * ** * *** * ** * ********** *** * = * *** * * ** * * ****
*** ***** ***** * ** ** *
* * * * * ****** * (D > 0)
* ** * **** ** * **
* * ** * ** * * * * ** ** real and ***** * * ***
* ** * * ** * * * ** * * = ** * ** ** *
* ** * * * **** * * ** ** ** * **** = %.2f",x2);
* ** **** * * * **** ***
** ** ** ** ** * * ** **** (D == 0)
* * ** * ** * ** ** * * *
*** * * * ***** * * * *** *** real and same\r\n");
* * *** **** *** = x2 = %.2f",x1);
* * * ** *** * ****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users