0 like 1 dislike
13.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 13.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* *** ** * *** * ***
** * * * * * *** *

int main() {
***** *** * *** * * ***** ** *
***** * * ** ** ** ** *** * ** * %f * * ** &a, &b, * * ** *
* *** * * * * * *** ** * * * ***
* ***** *** ** ** * ** * * *** * {
* ** * * ** * * **** *** * ** * *** * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** = ** **** = **** *** ***** a, b, c, (-b)/(2*a), * * (-b)/(2*a), **** **
* *** **** ** * *
* *** * ** * ** * if(d==0) {
** * *** * *** * * **** * ** * * * * * **** ** * * **
*** * * * * * * *** * * * ** ** ******* **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ****** a, b, c, x1);
* *** ****** * ** *
* *** * ** **** * * **** {
*** **** ** * * *** * * ***** *** ** *** * *** ** * *
* ** ** * **** ** ** * ** ** * ***** **** ** ***** * ** *** *
** * *** ** ** * * * ** * ** * * * ** *** * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** = %.2f\nx2 = * ** a, b, c, x1, x2);
* *** ** * **** * ** *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** ******
** ** * * **** * * **
#include *** * * ***

int main()
{
* ***** * * * **** *** ** * * *
** ** * * * ** *** * *** * * ** * %f ** **** ** ******
*** *** ***** ** * * *
** * * * ******* ***** ** * ** * * * **
** * * ** ************ ** * * * *
** * * ** ** **** * * ** **** * ** *
** **** * * * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * = %.2f\nx2 = * * * * *** *
** * * **** * ** if(D==0)
* ** *** ** * ** *** ** * * *** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * ** *
* * ** * * *** * * *
** * * * * * ** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * = * *** ** * = ** ** * ** * * ** * ** * * * *
* ***** *********** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** ** * ***
* *** ** *****
** * * * ***** * * * *

int main()
{
** * * * * ** * * *****
* * * * ** * **** * ** *** %f * ******* **** ** *****
* * * * ** * ** * * * ***
** **** * * * * * * * * * ** * ***
* * * * *** * * * * ** *** *
** ** * * * * **** ***** *
* *** * ** *** ** * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * = %.2f\nx2 = * * * * * * **
*** * *** * **** * ** * ****
* * ******* **** ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** **** ** *
* ** ******* * ** * *****
***** * ** * ** ** ** ** ** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * = %.2f + * * * = %.2f - * * * ** * * * * * * * ** * * * ****
** * * * ** *** * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** * *** *** * ****** * a,b,c,x1,x2,D;
** * ** * * ***** ** ** * * * %f ** * ** * * ** * * * * * *
* * * * * * **** ***** ** *
* **** * ** ** *** * = (-b + sqrt(D))/(2*a);
* * * ** **** * ** ** ** * = (-b - sqrt(D))/(2*a);
* ** * *** **** **** * * ** * *
** * ** * * * * *** * * ***** * ** * **
***** ** ** * * ** *** * ** *** * ** * * ***** * * ** **** * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * ** ***** ** *** * * * *** * **** * ** *** * * * ** ** * * ** = %.2f\n",x1);
** *** ** ** * ****** * * * * ** ** ** ** **** ***** * * * ** **** * * ** ** * * * * ** = %.2f",x2);
* * * * * ***** ** ** * * * ** *
* *** * ** * * ** * *** if(D==0)
** *** ***** * * ** * *** ** *** *** * ** *** *
* * *** *** **** ** * * * *** **** ******* **** ** **** ** ** * * * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * *** **** * ** * ** ****** ****** * * * * * *** ** ** **** ** * * * = x2 = %.2f",x1);
** * *** ** * *** * **** ** ** * * *
* * ** * **** * * * ** ** ****
** * ** *** * **** * ** * * * **** ** ***
* ** * * * ** ** ****** * ********* *** * * * * * ** ****** * * ** ** *** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
**** * ** * ** * * * * * *** * * ***** ** * *** ** * * **** *** ** ** = **** * ** * * **** *
*** * * * *** ** *** * ** **** * ** * * ** ** **** **** * *** * * * = * ***** *** **********
* ** ** *** * * * *** *** * ** * **** * *** * * *
* * ** * ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * *** ** ** * * **** a,b,c,x1,x2,D;
*** * * ** * * * * * *** * * %f ********* * ** *** *
*** * *** ** ** ** *** ** ** * ** *
* * * * ****** * * * = (-b + sqrt(D))/(2*a);
* * * * * * ** *** = (-b - sqrt(D))/(2*a);
** * **** ***** ********* * * *
**** * * * ** * ** * * ***** ******** * *** **
** ** * * * ** * **** ** * *** ******* ** ** * * * * ** ** ** ** * **** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* *** ** ** *** * *** ** * * ** *** *** * ***** **** *** * * * ** * = %.2f\n",x1);
** * ** **** *** *** * * * *** *** * * * ** * *** ** * * ** **** * * = %.2f",x2);
** * ** *** * * *** * ** * **** ** * * ** *
* ***** * *** * *** * * ** * if(D==0)
** * * ** ** * ** * * ** * ** * * *
* **** * *** ** ** *** * * ** ** ** * ***** *** * ** * * ******** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* ** **** *** *** ** * ** * ** ****** * ** * * ******** ** * * * * * ** * * = x2 = %.2f",x1);
* ** * * * * **** ** *** * * ** ******
* * * * ** ** * ** * * *
* ******** ** * ***** ** * ***** ** *
* ** *** *** ** * ** ** ** * * ****** * * * *** * ***** * * *** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
** ***** *** * ** ** * * ** * ** * ** * * **** **** * ****** * * * * * * * = *** ** *** * **** * ** **
* ** * ** ** ** * * ** ** ** * * * * ** ** ****** ** ** * * ** ** **** * ** ** = * ** * * * * ** ** *
** * * * *** ****** *** * *** **
** *** * ** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
** ** *****
* **** ** ** **
int main()
{
*** ***** * **** **** * a,b,c,D = 0,x1 = 0,x2 = 0;
**** * * **** * ** * ** ***** * * ** ** *** ** *** * *

* *** * *** *** **** * **** of %.2fx^2 + %.2fx +%.2f = 0 * * *** *
* * * * ** * ** = (b*b-4*a*c);
* * * * ** * * * (D < 0)
*** ** ** **** ** *
* ** *** **** *** ** ** ***** complex and *** ** * * **
****** ** ** ** * **** ** * * * = * * ** * * ** * * ****
* ** * ** ** *** ** * = * ** ** * * * * *** **
**** ***** * * **** *
** * * * ***** * ** (D > 0)
****** **** ** ** ** ****
* ** * * * * * ** * * * real and *** **** *
* * * ** * * ** * *** * ** * = * *** ** ** + sqrt(D))/(2*a));
** * ** ** * * * ** * * *** = %.2f",(-b - sqrt(D))/(2*a));
** * * * * **** * * * **
** **** ***** ** (D == 0)
* * ** ** * *** **** *
** **** * ***** *** ** ** real and same\n");
* ** ** * * ** * *** * * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** * ** *** ** ** ***** ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* ** * * * * ***
* * *** * * *
int main()
{
***** ** * * * * ** * a,b,c,D = 0,x1 = 0,x2 = 0;
** * * * **** **** *** * ***** **** * * * *** * ***** * *** *

** ***** * * * * *** * **** ** * ** of %.2fx^2 + %.2fx +%.2f = 0 * * * * **
* * * * ** * ** ** * * = (b*b-4*a*c);
* ** *** * * ****** * ** ** (D < 0)
** ***** * * ** *
** ** * **** * * * * * * * complex and * * *** ** *
* * * * * *** * * ** * * = **** ** * * ** **** ** * **
* ** * * ** * **** ** ***** *** = * ** ** **** * * *
** * ******* * * * *
** *** *** * ***** (D > 0)
* * * * * * * ****
**** *** * ** * * * * ** **** real and ** ** ** *
* *** ** ** ** ** *** * ** *** = * * * ** + sqrt(D))/(2*a));
*** * * ******* * * ** * * = %.2f",(-b - sqrt(D))/(2*a));
** **** ** ** **** * *
* * *** *** *** * * (D == 0)
** * * * * *** * ** * * * *
** **** ** *** * * **** real and same\n");
**** **** ** * *** * *** * **** = x2 = %.2f",(-b + sqrt(D))/(2*a));
******** * * ** * * *****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ** ** * * **
* *** * * ****** *
int main()
{
*** * ** ** ** * *** **** * a,b,c,D = 0,x1 = 0,x2 = 0;
** * * * ** * * ** *** * * **** * * * ** * ** ** * *

** * ** * ** * *** * *** ***** * * * of %.2fx^2 + %.2fx +%.2f = 0 ** * * * *
* **** **** * *** * *** = (b*b-4*a*c);
** ** * **** (D < 0)
* * * * *** ** * * *
* ** *** * * * * * *** ** ** * * complex and *** * ** ****
* *** * * * ** ** * **** * * ***** ** *** = * ****** * ** **** *
* **** * **** * * * * **** *** = * ** ** **** **** * ** *
** ** * * ***
***** * * * ** *** * (D > 0)
** * **** * * * ** * * **
** * * * ** * ** ** ** ** **** real and *** * *
* ** *** ** ** ** **** ** * = *** **** ** ** + sqrt(D))/(2*a));
** * * **** * ** * **** *** * *** * * = %.2f",(-b - sqrt(D))/(2*a));
** *** ** ******* * * *
*** * * ***** * ***** (D == 0)
*** *** * * ** * * *****
* *** * **** * * * ***** real and same\r\n");
** * ***** **** * ****** * * ** * **** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * ****** **** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * *** ** * * *
** * ****** ***** ** **
int main()
{
**** ** ** **** * *** * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* ***** **** * * ** ** ******* ** * **** ** * * *

* * * * * ** ** * * * * * ** of %.2fx^2 + %.2fx +%.2f = 0 * ** * * *
**** * ** ** *** ** * ** = (b*b-4*a*c);
* ** ***** * ** * * ** *** (D < 0)
***** ** * ****** **
*** *** *** * ** * * *** * complex and ** * * * * *
** * ** ** *** ** *** * *** = * ** * * *** ***** * * * ** *
** * * * * ***** * ** * * ** = * * ** ** * *** ** ***** ***
**** **** ***** **** **
** * * * *** * * (D > 0)
* ** ** * * **** *
* ** *** ** * ********** *** ** real and * * ** * ** * *
** ** **** ** * * *** = ** * * * + sqrt(D))/(2*a));
** * * * ** * * *** *** * **** ** = %.2f",(-b - sqrt(D))/(2*a));
********* * * * *
** * ** * ****** ** * (D == 0)
** * * *****
* * * * ** * ****** * *** ** real and same\r\n");
******* * * * ** **** * * ** *** * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** ** **** ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** ** * ** ***
* ** ******
int main()
{
**** * * * * **** * * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * *** * ** * * * * * * *** * ** ***** * * * ****

* *** ** ** ****** * ** ** * * ** * *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
**** ** ****** = (b*b-4*a*c);
* * * * * ** ** ** ** * = (-b + sqrt(D))/(2*a);
***** * ** ***** * * * ** = (-b - sqrt(D))/(2*a);
** * * * * *** (D < 0)
* * * * * *** * ***
* * ** * ** *** *** **** * * * complex and *** ** * ** * * *
* * ** * ******* * * * * *** = ***** **** * ** ** * ****** ***
****** *** **** ** * *** * ** *** * = ** * * ** ******** *
* * ** **** ** * * **
** * ** * **** ** * * * (D > 0)
** ***** * * ** ****
** ** *** ** ** * *** * ** real and * ** ** *
* *** ** * * * * * ** ** ** = *** ** *
** *** * ** ** ** * *** * *** * = %.2f",x2);
*** ** ** * **
**** *** * **** * * ***** (D == 0)
******* * * ***** *
* ** *** *** *** * * * **** *** * * real and same\r\n");
* * ***** * * ***** ** ** *** = x2 = %.2f",x1);
* * ** ** * * * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.226
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users