0 like 1 dislike
17.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** ** ** * * ** *
int main()
{
** * ** ***** **** * * * *** * ** * ***
* * * * * * ** * * ** * ** *** * %f ** *** * * *** *******
** * * ** ** * ** = (b*b-4*a*c);
*** * * * * ** = (-b + sqrt(D))/(2*a);
** * * * * * * * **** **** * = (-b - sqrt(D))/(2*a);
* ***** **** * * * *** ** * * = -b/(2*a);
** * **** * * **** * * * =sqrt(-D)/(2*a);
** *** * ** ** **** * * *
** * **** *
* * * *** * ** ** *** * * ** ** ** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** *** * ** **
* ** * * * * ** * * ** *** **** * * * ** * ***** ***** = %.2f\nx2 = %.2f",x1,x2);
* **** ** ** * ** *

* * * * * ** *** ** *** if(D==0)
* * * * ** ** ** * *
** * ***** *** * ** **** * * ** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** * **** * * ** ** ** * ** * ***** * * **** ** * = x2 = %.2f",x1);
* ***** ********* ** ***
* *** *** * * **** * ***
** ** * ** ****** **
* *** ***** ** ** * * *** **** ** ** * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** ** *
* *** * * ** * **** *** * * *** **** * ** * = * **** *** * * * * ***
* * * *** * ********** ** * * * *** * * * ** ** ** = * * * ** * **** * *
* ** * ** * * **** *
* ** *** * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * ** *

int main()
{
** ** * * ** **** n, i;

*** ** * * * ** * ** ** **** * ** ** ** &n);

* * * *** *** * * = 1; i <= n; ++i)
* * * ** * *
** * * * * ** **** ** * * ** * *** % i == 0)
* * ***** * * * *** * * ** * * * *** * ** * *** * * * ** **** ** * ", i);
*** * * ** * * ** *

* * ** * * * ** * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** * ** *** *
** * ** *** * ** ***

int main()
{
* ** * * ** * **** **** *** * * * **** *
* * * * **** * ** * * ** ** ** ** *** * **
* * * * * ** ** ** = * * *
* ****** * ** ** * **
*** ** ** * ** * **
*** ****** * * ***** * ** ** *
* *** * * ** * ** = -b /(2*a);
* ** ** *** * ** * ** *** *
* * **** ** * *** = (-b)/(2*a);
* ******* ** * ***** ** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ****** * *** *** *****
** ** *** ** * * * **
***** **** * * *** * if(D==0)
* * *** * ** ***
* * * * * ** * *** * * = (-b + ***** ***
** *** * ** * * ***** = (-b - ** **
*** *** *** ** ** * * * ***** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** *** * *
* * * **** * ** ****** *
* * * * * ********* if(D>0)
* * * * * ** * ** ** * *
* **** * * * ** ** * = -b/(2*a);
** * ** * * **** * = (-b + ** **
* * * *** ***** ** = (-b - **** ** **
** * **** *** ******** **** * * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** **** **
*** **** *** * * ** *
** * *** ** ** * *** * * * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ** **
#include *** ******* ***
int main()
{
* *** *** * * ****** * a,b,c;
* * ****** * *** *** *** *** * *** * *** ** *** **
* * * ** **** *** * *
*** *** * **** * * * ** *** * * *
** * ***** *** * *
*** ***** * ** * *** *** * * * ** * * ***** ** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ****** * *** + ** * * *** * - * ** ***
*** * * * ** * *
* * * * * * ** * * *
* * * * ** * if (b*b-4*a*c==0)
* * ****** ** * ****** ** *
* ** * * * * *** * *** * * ** * * * **** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * ** * * + ****** *** *
*** * * ** ***** * **** * *
** *** * *** **** ** ***
* * *** ** ***
* * ** * * * * * * * ***** *
**** * **** *** * * ** * * * ******** ** * ** ** *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * ** * ** ** * ** * * ** * * ** **
** * * * * *** ** * **
** *** * ** * ** * *** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ***** ** * *
#include ** ** * * ** *
int main()
{
*** ****** ** **** * * a,b,c;
** * *** * *** * ** * * * * * * **** ** * ** **** *
* * *** * * * * ** *
** * * * ** * * ** * * *
* ** * * * * * *
* *** * * ** ** ******* * * * * * ** * * * ** * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * ****** + ** ***** * ** * - * * * ** **
* **** * * * * *
* ** *** * * ** * *
* * * * ** * * ** ** if (b*b-4*a*c==0)
* *** * *** * *** ** **
* ****** * * * * * ** ** ** * ******* * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** * + * * * ** * *
** * ** * * * * * **
* *** ******* * * *
* ** **** ** * * *
*** *** * * **** *
* **** **** * * * * * * * * *** * * ** * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** ** * ** * * ** ** * ** ** ** * * * * ****
*** * ** ** ***** ***
* * **** **** * ***** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* * * **** * * * * * ***** * a,b,c,d,x1,x2;
* * * ** ***** * * * *** * **** **** ** * ** * * *** **** *
* * * ** * ** ****
*** ****** ** * * **** *** ** *** *
* *** * * * * * * * ** ***
* * * *** ** * ** ** **** * **
* * ** ** ** * ** *
* **** *** ** ** * *** * ** * **** * * * * ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** **
****** * * ** * * ** ***** * *** * ** * * * = %.2f\n",x1);
* * * * ** *** * * * ** * ** ** **** *** **** = %.2f",x2);
* * * * ** * ** * ** **
* * ** * * * * ** * ** if(d==0)
* ** * ** * * * *****
* ** * * ** * * ** ** ** * * * ** * *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ** ******* * ** ** * * * ******* ******** *** = x2 = %.2f",x1);
* * * * * *** *
***** ** *** ** *** * *
** * * *** ** * * * **
** * ** ** ** * *** * * * *** * * * ** ** * **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** ** * *******
* * *** * ** ** ** * * ** *** * ** ** * ** ** ** * *** * = * *** * ******* * **** *
* ** ** **** * *** * * * * ** * *** ** *** * *** = ** * * * * * * * * * *
*** * *** * * ** ** **
* ** ** * ** ****** * * ** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** ** ** ********* * * * ** * * *** ** * * ** *** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** ** * ** ** * *** ** *** ** * **** ******* - (4*a*c);
***** * * *** * * * * ** * * ** *** * * **** *
* * ** *** * *** * ** * * * * *** *** *** *** * * ***** * * * * ** ** ****** *****
* * * ** ** *** ** ** **** * * ** ** **** * * *** (-b+spD)/(2*a);
** **** **** ** ***** * * ** * ** ** * ******** * *** *** * *** * * (-b-spD)/(2*a);
*** ** ****** ** ** * * *** * *** * * * ******* * ** **** ** *** (x1==x2){
*** * *** * ** ** * **** ** ******* ** * * * * * * * * ************* * * * **** * **** *** * * * * ** * **** * * ** X=%d\n", x1);
* *** ** ** * * * * ** ** ** ******* * * ** *** * ** * * * *
* ** * ** * ** ****** ******* * ****** * ***** * * * ** ********* {
** * ** * ** ** ** * * ***** * ** * * ***** * * * * * ** ******* * * * * *** ** * *** ****** * * ** ** * ** X=%d或%d\n", x1, x2);
** *** *********** *** ** *** * **** ***** **** ** * ** **** * *
        }
* * * ** ******** ** *** *** * *** **** * * * if(D==0){
** * * ** * * *** *** * * ** * ** * * *** *** ** * * * (-b)/(2*a);
* ** * ** * * **** *** ** * **** * * * * ** * * ** ** * ***
**** ** **** ** * * * *** * * * ****** *** ** *** **** **** * * * *** * * * ** ** * ** * ** *** **** * * X=0");
*** ******** * ** ***** * ** * ** * * * ** **** * ** *** ** ****
* * ****** * * * * * * ** * * *** * * ** * * ** ** ****** * * **
* * *** * * **** * * ** ** **** **** * * ** * *** **** * *** *** *** * * *** * ** * ** **** X=%d\n", x1);
* * * *** * ** * * * * * ** * **** ** * ****** * ****** ** *** **
        }
******* * * ****** * * *** ****** * * * * ** ***
** ****** * * * * * * *** * * * * **** * * ****** * * * ***** ** ** * * **** ** ** * *
* * ** * ****** * ** * * * **
    }
** * *** * * * * * **** * ** * * ** ***** * *** * * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * ***** * * * * * * ** a,b,c,D;
* ** * ** ** * ** * ** ** ** x1,x2;
** *** * ** *** * **** * ** %d * ** ** ** * ***

** *** *** **** * * ** **
** * * * **** * * * * ** *** * **
* ** *** * ** * * * ** ***

* * ** **** * * * *** A,B,C;
*** **** * **** ** * * ** *

* * ** ** **** ** *** *
* *** **** *** * *** * ** *** ** *** ** * * * **** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0  are real and *** * * ** ** * *
* *** * ** *** * *** ** *** * *** ** * ** ****** ** * = %.2f\n",x1);
** * *** **** * * **** ** ** ** ***** * ** * * * * ** * * = %.2f",x2);}

***** ** ** * * * * * * if(D==0)
** ** ****** *** *** * * * * * *** *** ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** ** ** *** *** ****** ***** ** ** * ********* *** * ** * = x2 = %.2f",x1);}

***** * * * ** ** * if(D<0)
* * * * ** * * * * * ********** ******* **** * ** ********* of %.2fx^2 + %.2fx + %.2f = 0  are complex and * *** * ** ** *
* * * * *** ** * * * ** ** *** * * * * * * * * * bb,d,dd;
** ** ** ***** * *** * * ** ** * ** * ***
* * * * *** * * ** *** *** *** ** * *** * ** * ** ** ***
* *** ** * * ** * * **** * * *** ** * * *** ** ** * = ** * * ** **
** *** * * *** * ** * *** **** ** ** * * * *** ** = * ** **** * * ***

**** * *** * * *** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * * *** *
int main()
{
* ** ** ** * * * * *** ***** * **
** * ****** * * ** ** * **** *** %f ** * * * * * ** *
** * * * * ** * * *** = (b*b-4*a*c);
***** * * * ****** **** * = (-b + sqrt(D))/(2*a);
* * ** *** **** * * * ** = (-b - sqrt(D))/(2*a);
* * *** *** * * * ****** * * = -b/(2*a);
*** * ** * * ***** ** * *** * =sqrt(-D)/(2*a);
** ** *** ** *** ** **
*** ** ** ** * **
* * **** ** **** * ** * **** ***** * * ** * ** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ***** * * * * ** *
** * * *** * * ** * * ** * * *** * * * * ** ****** = %.2f\nx2 = %.2f",x1,x2);
**** ** * *** ** * * *

* * ** * * ** * * *** if(D==0)
* ** ** ** * * * **
*** * ** **** ** *** ** ** ** ** * * * * * * *** *** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** * *** * *** *** * * ** ***** *** = x2 = %.2f",x1);
* ** * * * ** * *
** ******** ** * ** *
* * * ** ** ** * *
* ***** * * ** * * * * * ***** * ** ** * *** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * * *** *
*** * * **** * * * ** ****** * ** * ****** ** * = * * ** ** ** *** *** *
*** * ** ** * ** *** * *** * * * ** * * *** *** * ** = * **** ** *** * * *
** * * ** * **
**** * * ********* * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** *** ** ** ***
int main()
{
** ** * * ** ** * * * * ************ *** ***
*** ****** *** * * * *** * %f ****** * *** ** * *** * **
*** * * ** **** ** * = (b*b-4*a*c);
**** ** ** * **** * = (-b + sqrt(D))/(2*a);
** * ******* * * * * = (-b - sqrt(D))/(2*a);
**** * ***** ** * * * = -b/(2*a);
* * * ***** * * * * **** ** =sqrt(-D)/(2*a);
* *** ** ** * * ** ** * * ** *
**** * * ***** ***** *
* * ** *** * ** ** ***** ** ** * ****** * *** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** **** ** **
* * **** ** ** ** * * * * * * * * *** * *** * * = %.2f\nx2 = %.2f",x1,x2);
*** * * ** **

** * ****** ** ** * if(D==0)
*** * **** * *** *** *
** ****** * * * ** *** * * **** ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ***** ******** * ***** ** **** ******** ** * * * *** * ****** = x2 = %.2f",x1);
* * ** ** * * *** * **
***** * * * *** *** ***
*** *** ** **** **
***** * ** ** * ** * ***** * * * ** * * * * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * **** *** * * * *
****** * *** ***** * *** * * * * * ** ***** ***** ** = * * ** ** ** * ** * ***
** * * ** ****** * * * ** * ******** * * * ** = * * * * * *** * *** **** **
*** * * ** ** ** *
* **** * * *** ** ** ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users