0 like 1 dislike
14.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 14.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
**** ***** * * * **
***** ** ** **

int main() {
* * * **** * * * * ** ** * *
* ** ** * * * * * ** ********* * *** %f * &a, &b, * *
* * * * * * * * * ** * ** ***
* * * ****** ** * ** {
** ** * * * * * *** **** *** ** * ***** * * ****** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** * = ** = * * ** a, b, c, (-b)/(2*a), * * * * * (-b)/(2*a), ** * *
*** ** * * * * * ** *
*** * * * ** ****** * if(d==0) {
* * ** * *** * * ** * * * ***** **** ** * ****
* *** ** * **** * * ** **** * ****** ** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** *** a, b, c, x1);
*** * ** * * ******
* **** * *** ** *** * {
** * * * ** * **** *** ** * ** * * *** * *** * *** ***
* * * ** ** * *** *** ** * * * ** ******* ** ** **** **
*** * * * ** ** * ** ** ** *** *** * ** ** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** = %.2f\nx2 = ** * a, b, c, x1, x2);
******* * *** ***
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ********* *
* * ***** **** *
#include ** * * ***

int main()
{
* ***** * *** *** * ***** * ** * * *****
***** ** ** * ** * *** *** %f ** * **** * * * * * *
** * * *** * * * * * * *** * *
* * ** * **** ***** * * * ****
* * ** *** * ** ** ***** *** *
** ** * * *** ** * **** *
* * ** * ** ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * = %.2f\nx2 = ** * *** ** **
* * * * * *** * if(D==0)
* * * * ***** * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * *** ** *
* * * **** * ** * ***
** * **** * * ** * * ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * = ***** ** = * ** ***** **** ** ** ** * * *** ** ** *
** * * * * ** * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** *
* ** ** * **
* * * *** * ** **

int main()
{
* *** ** ** ***** **** **** * * * * *
** *** *** ***** ** * *** ** * %f * ** * * * * *** *** *
* *** *** * *** **** * ** *** * ***
* ** *** * ** * ** ** **** *
** * * * ** * ** **** ***** ****
* ******** * * *** * * ** ***** *
**** **** ** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * *** = %.2f\nx2 = ****** * *** *
* * * *** * * ** ** *
* * *** * ** **** * * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ***** **
* * * * * ** * * *** **
** * * ** * ** * ** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** = %.2f + * * = %.2f - *** * ** ** * * ** * * **
* ****** ***** ** * ** *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ***** ** ** * * **** a,b,c,x1,x2,D;
* ** * * *** **** %f * * * * *** ** *** ****** *
** * ** **** * * * ***
****** *** ** ** ** * = (-b + sqrt(D))/(2*a);
* ** * * ** * * ** ** = (-b - sqrt(D))/(2*a);
* * * * * * ***** * ** ***
*** * ** ** ** ****** ** * * * ** * ** **
** * ** * *** * * ** *** ** ** * ***** **** ** * ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * *** * ***** * * **** *** *** * *** *** * **** *** ** ** * ** ** ** * ** * * = %.2f\n",x1);
* * * * * * **** * * * *** **** *** * **** ** * *** * **** ** *** * = %.2f",x2);
** ** * * * ** * * * ** * ** * * * *
* * *** * * *** * ** if(D==0)
* *** * **** *** **** **** * * *** *** ** **
** ** *** ** * *** * ** **** ** ** * ** * ** * * *** ** * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** * ** ** * * *** * * * **** * ** ** * * ** **** ***** ** * = x2 = %.2f",x1);
* * ** ** * * * * * * * * * * * * ***
* ** * *** * ** * * * * *
** ** ** ****** * ** * * **** * **** **
* * * ** ** * ***** ** * * * * * * ***** ** * * * ** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
** * **** * **** * * * ** * * * ***** * ** * **** ** ** * * * * ** * ** = * * *** **** * *** *
** **** * ** *** ** **** * * * ** **** * * * ***** * ** ** * * * = * * * * *** * ***
* ** * * * * ** *** * * * ** ** * * *******
***** *** * ** *** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** * ** ** * * * **** * **** a,b,c,x1,x2,D;
**** ** * * * **** * * * * %f * **** ** ** *** ** *******
* ** * * ** * * ** **
*** *** * **** ****** * * = (-b + sqrt(D))/(2*a);
** * ** * **** ** * = (-b - sqrt(D))/(2*a);
*** ** ******* * *** ***** ** *
* * * * **** * ** * * * * ** ** * * **** *
*** **** * * ** ** * ***** * ** ** * ** ** *** * * * * * * *** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* ** * * ***** ** * * **** **** ** * ** **** * * * ***** **** * = %.2f\n",x1);
* * *** ** * * ** *** * * *** * * ** * ** * * * *** ** **** ** * = %.2f",x2);
** *** * ** * ** * ** * ** * ** **** *
** * * **** * * if(D==0)
* * ** * ****** * * ** * *** ** *** * ****** *
**** * * * ** * **** * ** ** ** ***** * * * * ** *** * ** ** * * *** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* ** *** ** *** ** * * * ** * ** * * * ** * * * * ********* *** = x2 = %.2f",x1);
********** *** * * * ** ** ***** **** **** **
** * ********* ** *
* * ******* ** * * * ** * ** ** * ** *
* *** * ** ** * ** **** *** ** * * * * ** ******* ** ** * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
** *** * ** ***** **** **** *** ** * * ** ** * * ** *** ** ** *** * = * * ** **** * * *
* * * ** ** ** ** ** *** ** * *** ** ** * * ** ******** ****** ** * * ****** ** ** = * * **** *** * *** * * *
** ** * *** ***** **** **** ** * * * * * *
* * * * *** ** * * * * * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
** ** * ** * **
** ****** ** ****
int main()
{
** *** * **** ** * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** * **** ********* ** ** **** * ** * * * * **** * *

*** *** * * * * * **** *** of %.2fx^2 + %.2fx +%.2f = 0 ** * * *
* ** ** *** ** * ** = (b*b-4*a*c);
** * ** *** ** * * * * (D < 0)
* *** * *** * * *** * ** *
* * ** ** ** * ** **** complex and ** ** * ****
* *** * *** ** * ******** = * **** * * *** * ** * *
*** * *** ******* *** *** ** * ** = ** ** * * * * *
** * ** ***** *** *
* * * *** ** * *** (D > 0)
* ** * * **** ** ***
******* ***** ** * ****** * real and * *** * *
** * * * ** ***** * * * * * * * = ** * * * ** + sqrt(D))/(2*a));
* ** ** * * * ** * * * * * *** * *** = %.2f",(-b - sqrt(D))/(2*a));
*** * * * * * *** **
* * *** ** ** ** ** **** (D == 0)
*** * * * * * *
** ** * *** * * ** ** * real and same\n");
* ** * ******** ** ** ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** ** ***** * ** * * ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* ** ** * * *
** *** *** * **** *
int main()
{
* ** * ** *** * * a,b,c,D = 0,x1 = 0,x2 = 0;
*** * **** * * ** * ** *** ** * * ** * *

* **** * *** * * *** * of %.2fx^2 + %.2fx +%.2f = 0 *
* *** * ***** = (b*b-4*a*c);
** **** * ***** * * (D < 0)
* *** **** * ** ****
** * * * ** * ***** ** ** complex and * * ** *
* * * * * * ** * * ** ** * * * = * * * ** *** **** ** ** * *
* **** ** * ** * * * ** * = * * ** * *** * * * *
* * *** * ***** *****
* * * * * * * * * ** (D > 0)
** *** ***** *** * ** * **
** ** * ** ** ** ** * * real and *** *** *****
* * *** * ** ** * * **** * * = * * **** * + sqrt(D))/(2*a));
** ** ** ** **** * * **** *** **** = %.2f",(-b - sqrt(D))/(2*a));
** * * * **** ****
* *** *** * * * *** ** (D == 0)
***** * * ***** * ***
* *** * * *** * * * * **** real and same\n");
** **** * * * * **** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * * * **** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** ** ** * ***
*** * * *
int main()
{
** ** * **** ** * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ** ** ********* ******** **** ***** * **** * ****

****** ** ** **** * ***** * * * ** * ** of %.2fx^2 + %.2fx +%.2f = 0 * ** **
** * ** ***** * *** = (b*b-4*a*c);
***** **** **** * ** ** * (D < 0)
** * **** * ** * *
****** * * *** ********** * complex and * *** ** * **
**** ** *** *** ***** * * ** * = ** ****** ** * * * *
* ** ** ** * * * * ** *** * * = ****** ** ***** ** * ** ** *
** * * * ******** **
*** * ** ** * * * (D > 0)
*** ** * * * ** ** * **
** ** * **** * * *** * real and * * * * * *
** * * **** * **** * **** = *** ** * * + sqrt(D))/(2*a));
* *** * ** ** ** * ** * **** = %.2f",(-b - sqrt(D))/(2*a));
* * ** *** * *****
*** * * ** ** *** ** * * * (D == 0)
* ** * ** * ** * * *** ** *
** *** * *** * ***** ** real and same\r\n");
********* * * ****** ** ** ** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * * * **** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * *****
** * * * ** * *
int main()
{
* ** * * ** * *** ***** a,b,c,D = 0,x1 = 0,x2 = 0;
* **** **** * *** * ** * **** * ****** *** * *** * **

* **** * * ** * *** ** ******* of %.2fx^2 + %.2fx +%.2f = 0 * * ** *** *
*** ** * * ** *** **** = (b*b-4*a*c);
* *** * *** * * ** (D < 0)
** ******** * ***** **** *
** * **** * * ** *** * ** complex and * **** * * ** * **
* *** *** * *** * ******** **** ** = * * ** * * ** * *** *****
* * * ** ******* ** *** **** ** = * * * * *** * *
* * * ** *
* * * ** * ** ** * * (D > 0)
**** * * * * * ** ** ** *
* ** * *** * ** ****** *** ** real and * * * * ***
********* ** * ** ** ** * = * * *** ** * + sqrt(D))/(2*a));
* * ** ** * ******* * * *** * = %.2f",(-b - sqrt(D))/(2*a));
*** *** * ** **** ** *
* ***** ** * * ** ***** (D == 0)
** ** ** **** **
** ** *** * * ***** * real and same\r\n");
** ** * * ** *** * ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * ** * ** * ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * **
* * * * ***** ***
int main()
{
** * * * * ***** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * *** ** ** * ** ** * * * * * * * * **** ***

** * *** * ** ** *** * *** ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** * * *** * * **** = (b*b-4*a*c);
**** ** ** * * ** *** * = (-b + sqrt(D))/(2*a);
** * *** **** * *** = (-b - sqrt(D))/(2*a);
** * * *** * * ***** * (D < 0)
* * ** * * * * *
* * *** * ********* ***** ** * * complex and ** ** ** ***
**** * ** *** * *** ** ***** ***** * = ***** * * *** * * * *** ** *
* * * ** * ** **** **** * ** = * * **** * * * **
* ** * ** **** ** **
* * * * *** * * *** * (D > 0)
** *** * * ** **** *
*** * * * * *** ******** real and * *** * *
* **** * **** * ** * * ** = ** * *** *
* * *** *** ****** * ** **** = %.2f",x2);
** ** * *** * **** * *
* ** ** * * * ** (D == 0)
* **** ** **** ****
** * * * ** * **** * ** * ** real and same\r\n");
** ** * * * * ** *** ** ** ** = x2 = %.2f",x1);
* * *** * ** * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users