0 like 1 dislike
7.9k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.9k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * ** * *
* * * ** *** *

int main() {
** ** *** *** **** * * ** ****
* * ** ** ***** ****** ***** *** *** %f ** * &a, &b, * * * **
** *** ** ** * ** * ** **
* * ** * ** ******* * ** * {
* * **** * ** * * *** * *** * ** ** * *** *** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * = ***** * = *** * * * a, b, c, (-b)/(2*a), *** * (-b)/(2*a), ***
** *** ********** **** *
*** ** ** * * * ** *** * if(d==0) {
* * * ** ** * * ** ** *** * * * * ***** ** **
* * **** * **** * *** * * * * ** ** * *** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * a, b, c, x1);
** * * **** ****** * * * * *
**** ***** * * ****** * * * ***** * {
* * ** * ** * ** * * **** * * *** * ** * *
* ** **** * * *** * * *** ** * ** ** * ** * **
** * * * * * * * * ** *** * *** *** ** * ** * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * = %.2f\nx2 = ** ***** ** a, b, c, x1, x2);
** * * * *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * *
* ** * * ** ** * *
#include **** * *****

int main()
{
***** ******* ****** ** * *
** ** * * * * ** ******* * %f * * * ****** * * *** **
* ** * *** ***** ** *** ***
* *** ** * ** **** ** * * ***** *** **
*** * * ***** *** *** * ** **
* ** *** *** **** *** ** *
** * * *** ** ** **** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * = %.2f\nx2 = *** ****** *
* * * * ** *** ****** ** if(D==0)
* ** * * ******* * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** * ** *
** * ** **** **** ** * *** * ***
**** * * **** *** * ** *** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * ** = *** * * = * ** * * * **** *** * ** * *** * *
* * ** * * **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * *
* * * ** * *** **
* *** ** * ** *

int main()
{
* * * ** * * * * *
* ** *** **** ** * ** *** * * * %f * ** **** *** *** ** **** *
* ** * *** **** * **** ** * *
*** * *** ** * * *** ** ** ** ***
*** *** *** ** * **** * * ***
* * * * ** *** * *** *
* * * * ** *** * ** *** ** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** **** = %.2f\nx2 = ****** ** * *
* ** *** *** ****** * *
** * *** *** * * *** **** ** * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * ****** *
*** ** ** ** * * *
****** ** * * ** **** ** *** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** *** = %.2f + * ** = %.2f - * * * * ** *** * * **** * * *
* ** * * * * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * *** * ** * ** * a,b,c,x1,x2,D;
* ** * * ********* ** *** * * %f ** *** ** * ******** ** *
* * * * ** * ** * *** ** * **
* **** *** **** * * = (-b + sqrt(D))/(2*a);
** ** ****** *** * * = (-b - sqrt(D))/(2*a);
* * * * **** ** ** * *** ** ***
** * ******* * ** * *** **** * * * * ** *
****** * ** * * * ** * ***** * ****** ****** * ** * * * * ** * * * ******* * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** * ** * * *** * **** *** * * *** *** *** * * * ***** * * * ** ******* * = %.2f\n",x1);
* * ** * ***** * * * * ** *** * ** **** ***** *** * *** **** * ** * *** * **** = %.2f",x2);
** ** ** *** * ** * ** *** ** * * ***** * *
****** ** *** **** if(D==0)
* *** * ** * * * ** ***** * * *
** * * **** *** * ******** ****** ** ** ** * * * * ** *** **** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ***** ** * * ** * *** * ***** * * * * * ** * * * ** * ** ** * * ** ** * * ** = x2 = %.2f",x1);
* *** ** * *** ** * * * ** *** * ** ******** ***
** ** * **** ** * *
*** ** **** *** ** *** * ******* *** * * **** ** * ** **
** *** ** ** * * ** ** * * * * **** ** * * * ***** ***** **** * * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
**** * * ** ** *** *** * * * *** * **** ** **** * * **** ** * ** ** = ** * * * ** * * ***
** ** ***** * * * ** ** **** * **** * **** * *** * ***** ***** * * ****** = * **** * *** * **
*** ** * * *** * ***** * *** ** * * * **
*** *** ** ** **** ** *** ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
***** * * ******* ** ***** a,b,c,x1,x2,D;
*** * ** ** * ***** *** *** * ** %f * * * * **** * *** *
*** ** * ****** ** * ** *
** * * * * * ** ** = (-b + sqrt(D))/(2*a);
*** ** * ** ** * * ** = (-b - sqrt(D))/(2*a);
** ** ** ** *** *** *
** *** *** **** ** *** * * * * *****
*** ** * * *** ****** * ** *** * * * * ** ** *** ** **** * *** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* ****** ** * * **** * * ** **** * *** ** * * * *** **** **** * *** * ** *** * = %.2f\n",x1);
* *** * * *** * * * * ** ** ** ** * ** * ** ****** ** * *** *** * * * * = %.2f",x2);
** **** ** * **** * *** ** * * * * *** ** **
*** *** * **** *** **** * ** if(D==0)
* * * ** * * ** * * * * ** * ****** *
* ** * * * *** ** * * * ** * ******* * ** ** **** * ** * * * * ** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* *** * * * * * ***** * * * * ****** * * * * * * ** ** ** * * = x2 = %.2f",x1);
* ** * ***** * *** ** * * * **
** **** ** * ** * ** *
*** * * * * ** * ** ** *** * * *** *
* * *** ** *** ** *** ****** * * ***** * * ********** *** **** * * * ***** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
** * * * ** **** *** ********* *** **** * * * ** * * * * * *** = *** ** *** * * * *
* * ** * * * ** * *** **** ** * * ***** ** ** ** ** ** ** *** *** = ** *** * ******** * *
* *** ******** * * *** *** * * * * * *
* * * *** * * * ** * ** * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
** ** * *
** * ** *** ** *
int main()
{
*** * *** ** * * * ** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * * *** * * * ** * * ** ***** * * *** ***** * *********

* * **** * * ** ** * ** ** ** *** of %.2fx^2 + %.2fx +%.2f = 0 **** * *
* * ** * * * * ** * * = (b*b-4*a*c);
* ** ** * * ** * * * *** (D < 0)
* * * * * ** * ** ** *****
** * * * *** * * * * ** * ** complex and ** *** ** *
***** *** * *** ** *** **** *** = * * * * * ** **** * * *
* ** ****** * **** ** * * * * * = ** ** ** * **
* * * * * ** **
*** ** * ** ** ** (D > 0)
** **** ** **** * *
** * * * * * *** ** * *** * real and ** ** **
* * ** * * ** ** ** ** * = * *** ***** + sqrt(D))/(2*a));
* * ** * * ** ** * ***** ****** * = %.2f",(-b - sqrt(D))/(2*a));
**** ** ** ** *
** * * * * * * * (D == 0)
* **** ** * * * *** **
** ** * * * * ** * * * * real and same\n");
* ****** ****** * * * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
**** * **** * ** ** * ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** ** ** * *****
* *** * *
int main()
{
* * **** * ****** ** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
** **** * *** ** * ** * ** ******** * * **** ******

* * ** ******* * * * * * * of %.2fx^2 + %.2fx +%.2f = 0 ** * *********
** * * ** * * * * *** *** = (b*b-4*a*c);
* ** * **** * * ** **** ** (D < 0)
* ** *** *** * *** ****
* ** * * ***** * ******* * * * * complex and *** *** ** * *
* *** * ** * * * * ** * **** * = ** *** * *** * * * * ***
*** * ** *** * ** * * * *** * = * ** * ** * * *** * *
* * * * * ** **
*** * * * ** * ** * (D > 0)
**** * * * *** *** **
* * * * * * * **** * real and ** *** ***** * *
*** * ** * * * *** **** ** * * = *** * ** ** * + sqrt(D))/(2*a));
* *** * * *** * *** *** * * ** = %.2f",(-b - sqrt(D))/(2*a));
* *** *** * * * **** *
* * ** *** ** *** (D == 0)
** ** * ** *** * ** **
********* ** * * * * * * * ***** real and same\n");
** * * * * ** ** * * * * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** ** * * * ** ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** *** * ** *
* *** * *** *** ***
int main()
{
**** ***** * **** *** a,b,c,D = 0,x1 = 0,x2 = 0;
*** ** ******* ** ** * *** ******* ** ***** * *******

* * *** * ** * **** *** of %.2fx^2 + %.2fx +%.2f = 0 ** *** * **
** *** ** * ** * ** * *** = (b*b-4*a*c);
* **** * * * ***** ** (D < 0)
* * *** * * *** *
** ** * ** **** * *** **** * ** * complex and ***** *** *
* * *** ** * * * **** ** * = ** ****** * ***** *** *
* * * *** ** *** **** ****** = ******** ** *** * * *
* ***** ** ** ****
** * *** ** * * * * * ** (D > 0)
** ** * * * * *
* ** * **** * *** * ** **** **** real and * ** * * ** ****
* * * ** * * ** * = * *** * *** + sqrt(D))/(2*a));
* ***** ** * ** * * ** * = %.2f",(-b - sqrt(D))/(2*a));
* *** * **** ****
***** ** **** * *** (D == 0)
* * **** ** * ** * * ***
* *** **** * * * *** * * ** real and same\r\n");
*** * *** * ** ***** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
***** * ** * * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ** *** ***** *
* ***** ** ** *
int main()
{
* * * *** * *** ** *** a,b,c,D = 0,x1 = 0,x2 = 0;
**** ** *** * ** * **** ** * * **** **** * ** ** * **

* ** **** **** * ***** ** * *** of %.2fx^2 + %.2fx +%.2f = 0 * ** ** * *
* *** * * * ** ******** = (b*b-4*a*c);
* * * * *** *** *** (D < 0)
*** * ** * * ** * * ***
* * * ** **** *** * * ** * ****** * complex and ** * ** ** *
** ** * * ** ** ** **** ** ** = * * * ** * **** * * *** *
***** * * * ** * = * * * * ** ** * * * * *
* ** * *** * * *
*** *** **** **** * (D > 0)
* * ** *** * **** ** *
* **** * * ** ** * real and * ** ** * *
** * * **** * * * * ** * * * = * * ** + sqrt(D))/(2*a));
* * * ** ******** ** ** * ** = %.2f",(-b - sqrt(D))/(2*a));
** * ****** ***** * * * * **
***** * ** *** ** ** * *** (D == 0)
****** ** * * ***
* * * ** **** ****** ** * *** **** real and same\r\n");
* * ***** *** * * ****** ** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** * * ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** *
* ** * ** * ***
int main()
{
* ** ** ** **** ** **** * a,b,c,D = 0,x1 = 0,x2 = 0;
**** * ** ** * *** * *** ** * **** * * * ** ** *

*** * ** ** * * * **** ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* *** ****** * * * = (b*b-4*a*c);
* ** ** * *** * * ** * * ** = (-b + sqrt(D))/(2*a);
*** ** * * ** * **** = (-b - sqrt(D))/(2*a);
* * ******* *** *** ** * ** (D < 0)
*** * * * ** ** * *
* ** *** * * * * * * ** *** complex and * ** ** ****
**** * * **** *** ** * * * * ***** = * ***** ** * * * ** * **
* ** * **** * *** ** **** * * * = *** * ** ******* * **
** * * * * ** **
* * * ** *** * ** * (D > 0)
*** * * *** *** **** ** ****
* * * * * ** ***** ** ** *** * ** real and ** **** *** **
* * ** **** **** * ** * * *** * = * * **
*** ** *** * * ** **** * * * * * = %.2f",x2);
*** * * **** ** ** **
** * * * * *** ** * (D == 0)
** ************** **
* * ** * ***** * * ****** * * real and same\r\n");
* * *** * ***** ***** ** * *** * = x2 = %.2f",x1);
* ** * *** **** *****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.200
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users