0 like 1 dislike
13.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 13.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * *** ** ** ** *
int main()
{
** * ** * **** ***** * * * * ** * * * ***
**** ** * *** * * ** * * * * * %f **** ***** * * ** * *
*** ** * *** ** * **** = (b*b-4*a*c);
**** ** * * *** *** = (-b + sqrt(D))/(2*a);
*** * **** * * * ** = (-b - sqrt(D))/(2*a);
* *** ****** *** * ***** * = -b/(2*a);
** * * * * * ** *** ** ** =sqrt(-D)/(2*a);
** * ** * **** * **** *** ** *
* ** * *** * **** ***
** ** ** ** *** * * * * ******* * ******* * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * *** * ** *
** * ** * * * * * *** ** * * ** **** * *** = %.2f\nx2 = %.2f",x1,x2);
** ** * * * ** *

*************** * * if(D==0)
** *** * *** **** **
* ** ** * **** *** *** * * *** * ***** * * *** * ** ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * ***** * * * * **** ** * ** * ***** = x2 = %.2f",x1);
* ** *** *** * ** *
* * * ** ** * ** * ** *
* ** * *** **
*** ** ****** **** ** ** * ** **** ** **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * * *
*** *** * **** ***** *** * * * * ** **** * * **** * = * * ** **** *** ********* ** **
*** ** ** ** ** ** * ** **** * * ** * * * ** **** * = **** *** * ** * **** * ****
** ****** ** * ** * * **
* ** * ****** * ** ***** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ***** ** *

int main()
{
* **** * * * * * n, i;

* *** * ** *** * ** ** &n);

* *** *** * *** * * * ***** * ** = 1; i <= n; ++i)
* * * ** * * * **** *
***** ** ** * *** * * * * * % i == 0)
** * ** * *** * * * * * * ** ***** * * * * ** ** **** ** * ** ** * **** ", i);
** * *** **** *****

* * ** * * * ***** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** ** **
** ** ** ** * **

int main()
{
**** ** * ** *** *** * * ** * * *
** * *** ******* * ** * * * * *** **** * *** * * ******* * **
** * **** ***** * * ** = **** *
** ** ** * *** * * *** * *
** ** * *** * * * *
* ** * ** * ***** ***** * * ** * ***** * *
* * * * * * ** **** **** * = -b /(2*a);
***** * * * * * * * ** * *** ***
***** ** ** *** *** **** = (-b)/(2*a);
** * **** * * * * * *** **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * * **** * *** **** *
* *** *** * ******* ***
* * ** ** * ** if(D==0)
***** ** *** **** *** * * **
**** ** * * * ****** = (-b + * ** *
** * * ** ** *** * * * * = (-b - ** *
** ** * * ** * ** * ***** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * *
* **** ***** * **
** * ***** * * * *** * if(D>0)
** * ** ***** *** *
* * ** *** ** * ** = -b/(2*a);
*** * * * ** * ** ** ** = (-b + * ** *
* ** * ** *** * = (-b - ** * **
* * ** * ***** *** *** **** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * * *
* * * * ** **** * **
* * ** * * ** * * ** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * ****
#include * *** ****
int main()
{
** *** **** * ** * ** * a,b,c;
***** ** *** * * * * ** ** ***** ** * ** ******* *** *** * ****
*** * ** **** *** *
* ** ****** ***** * **** ***** * ***
* *** * * * ** **
* * ** ** * * * * * ** **** * * * * *** ** ** * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** * *** + * *** * * * - ** ** *
***** * *** * *** ******
*** **** * *
***** * * ** *** * * * ** if (b*b-4*a*c==0)
** * ** ** * ** ****
* * * ** ** * * *** * *** *** *** ****** ** **** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * *** * + * **** *** *
** * ** * *** *
* * ****** *** * * ***
*** ****** * * * * * * ** ** **
**** *** * **** ** **
* * *** ** **** *** ***** * * ** ** * * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** ***** ** * * *** ** ** * * * * ** ****** * * *
*** * * **** * *
* * * * * * ****** * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ******** *
#include * * * ***
int main()
{
** ** ** * * * * ***** a,b,c;
*** *** * * * * ** * * ******* ** * ** ****** ** * ** *
* ** ***** **** *
**** ** * ** * * ** * * **** * * *
* *** **** * ** ** *** *** *
* * ** * * * ** **** ** * ** * * * * ***** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** + **** ** * *** * - * * *
* **** *** **** *
** * ***** * *****
* * * * * *** if (b*b-4*a*c==0)
* * ** ** ** * ** **
* * *** ** * * ** * ** * * * * ** * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * + * * ** * *** *
***** *** * * ** ** ***
** * * ****** *****
** * ** * * ** * * ***
**** ** * * ** *****
* * * * * * ** ***** ** *** * * * * ****** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** * * ** ** * ***** * *** * ** * ** ** ** *** * *
** ***** * * ** * ****
* * ** * *** * * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
*** ** *** ** * ****** a,b,c,d,x1,x2;
* ** ** ** ** * ** ** ** * * * **** ******* ** *
* ** * *********** *** ***** ** **
** * * *** ** * * * **** ** * * ****
** *** * ******* * * * ** ** ***** ***
* * * * * *** *** **** ** *
** * ** **** * *
** * ** ** * **** * * * * ** * * * * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ***** *
* ** ****** * ** *** *** * ** ** * ** ***** * * * **** = %.2f\n",x1);
* * ***** *** *** ** ** * * * ** ****** * * * *** = %.2f",x2);
** * **** * ** * * *
* ** * ** * * ** * * ** if(d==0)
* ** * * * ** ** ****
*** *** ***** ****** * * * * * * * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
****** ** * ****** ** **** *** ** * * ******* = x2 = %.2f",x1);
* ** *** ** * **
* *** ** * * ** *** ** * **
* * * ** * *** * * ****** *
* * * *** * * ** * * ** * * * *** * ****** * **** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** *** *
** * ** ** **** * ** * *** *** * * * * * *** * **** * = * * ** * * * ***** * ** *
** * **** * * ******* ** * ** *** * * **** * **** = * * ** **** *** *** * *
* **** ** *** *****
* * ** * *** *** ** *** ** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * *** * ** ** * **** ****** * * * ** * ** **** * **** * *** * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* *** ** * * * ** ** ** ***** ** * * **** - (4*a*c);
*** *** ****** * **** ** * ** * * * ** ****** *
**** * * * * * *** ** ** ** ************ *** * * *** * *** *
** * * * * ** **** ** * * * * * ** ** * * ** ** * * *** * * (-b+spD)/(2*a);
**** ** * * * * *** ** * ** * * ** * ** * * * * * (-b-spD)/(2*a);
** * * * ** ***** **** * * * *** * * * * ** **** * ** * * ** * (x1==x2){
* *** * * * * * ***** ******** * *** ***** * * * **** * ** * * ****** * * ** ** * ** *** ***** **** ** *** ** * ** *** * * * X=%d\n", x1);
** **** * * ******** * * * ***** ** * * ** * * * * *
* * ** ** ***** *** * * ** * * ** * * *** ** ****** * ** * * * {
** * *** *** **** *** **** * * * * * * *** ** * **** * ** * * * * *** ** *** * * ****** * ** ** * ** *** * *** *** ** X=%d或%d\n", x1, x2);
* ** * *** * * ** ** ** ** * * *** ** * * * **** ** **** * ***** **
        }
*** *** *** **** *** ** ** * * *** **** * *** * if(D==0){
** * **** **** * * * ** * *** * * *** *** * * ***** *** *** ** *** (-b)/(2*a);
*** * * * *** * ** * ** * * * * * ** ***** * ** * ** * * *** ***
* ****** * ** * ** ** *** * * * * * *** ** ******** * * * ** * * * *** * * * ** **** ** * * *** X=0");
* *** * ** * * ** * * ** * ** * ** * * * *** ** ** **
**** *** * * * * ******* * ** ** *** * *** * * ***** ** **** ** * ***
* * ** * ** **** ** ** *** * * * ** ****** ** *** * * * **** * ** * * ****** ** * * * * *** ** * X=%d\n", x1);
** * ** * * *** ** **** *** * * * * ** *** *** ** ** ** *
        }
** ** ** ** ** * ** ***** ***** * * * * *
* ** *** * * ** * ** ** * * * * ******* ** *** * * * * ** * * *** * ** * **** * * * ** * ****
****** * ** ** ** *** * * * * ** ** *
    }
*** ****** * *** * * ** * * * * * ** ** * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * * ** ** * * * * * a,b,c,D;
** ** * * * ** ** * * x1,x2;
* *** ** ** ** ****** ** ** * * %d ** ** * ** * ****** *

** ** * * ** * * ** * *
**** ** * ** **** * * * * **** *
***** ** * ***** **** **** * ***** ** *

** * * * * * ** ** ** **** * * A,B,C;
* * *** * *** ** * * ** * *

* *** * **** * ** * * * ***** **** * **
** * * * ** * ** * * ** ** ** ** * *** * ***** *** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * ** *** ***
* * ** ***** ** ** *** * ** ** * * ** * * ** *** ** * ******* = %.2f\n",x1);
** ** *** ***** ** * *** ** * *** * ** * * * ** = %.2f",x2);}

** ** **** * * ** * ** if(D==0)
** * ** ** ** ** ** * * ** ** ** **** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* ** * * *** ** ** ** ** * ** * *** ** * ** * * ** * *** ** * *** = x2 = %.2f",x1);}

*** * * ***** ** *** * if(D<0)
* ** * *** * * * **** * * * ** *** * ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** *** ***** *
* ** **** ** * * * ** ** *** ** * bb,d,dd;
* * *** * * ** *** ****** ** ** * * **** ** * **
* * * * * ** * ** **** * ***** * * * ** * ** ** *
** * * ** * **** *** ** * *** * * * * * * * * = *** ** ***** * **** **
* ** * ***** * ** ** * *** * *** * ** * * * * * *** = * * ** * **

* * * ** * * * * * * * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * * ** * ** ***
int main()
{
* ** ** * **** ** * * * ****** *** ** * * *
* ** * * * *** * * **** ** * * * %f * *** * ****** *
* * *** ** * *** * = (b*b-4*a*c);
** ****** ** ** * ** ***** = (-b + sqrt(D))/(2*a);
* ** ** * ** ******** * * = (-b - sqrt(D))/(2*a);
* * * * *** * * * * * = -b/(2*a);
** **** **** * * **** * =sqrt(-D)/(2*a);
* * * * *** ** **
* * ** * ** **** *** *
***** ***** * * * * * ** * * * * * ** ** ** * *** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** ***
* ** *** ** * ** * * ***** *** ** ***** = %.2f\nx2 = %.2f",x1,x2);
**** * * **** *** * **** **

* * ****** **** * ** * if(D==0)
* ** * * ****** * **** ** *
** *** * * * ** **** * * ** * * **** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** ** * *** *** **** ** * ** * ** * * * * * ** ** * = x2 = %.2f",x1);
* ** * ** ***
* * * ** *** * ** *** ***
* * * ** ** * ** *
*** * *** * * ** ** * ** ** ** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** **** * **
* *** ** ** * * * *** * * ***** * * * * * * = * *** ***** **** * * *
* ** * * ** ** * ** *** ********* ** ** * * ** = * *** ** * **** * ****** **
***** * ** * * * *
** * * * * * * * ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * * * **
int main()
{
* * *** ** * * *** * ***** ** ** ** *
** * * * ** * * ** * * ** %f ** * * *** *** *** * * * *
** ** *** *** *** * *** * = (b*b-4*a*c);
*** * *** * * **** * * * = (-b + sqrt(D))/(2*a);
* ** * * ** * ** * = (-b - sqrt(D))/(2*a);
* *** * ** *** ** ** = -b/(2*a);
* *** * ** * * *** *** =sqrt(-D)/(2*a);
* * *** **** * *** ** * * * *
* * * *** ** * *** ** ** **
* *** ** * *** ** ** * * ** ** * * ****** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ***** *** ****
** * ** * *** ** ***** * ** * * ** * ** = %.2f\nx2 = %.2f",x1,x2);
** *** ******* * ****** *

* **** * * ** *** * * * if(D==0)
*** ** ** * * ** ** *
*** * * **** * ***** * * **** * * ** * ******** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ***** *** *** * * * *** ** * * * ** * *** * = x2 = %.2f",x1);
* *** **** * ** * ****
** * *** ***** ** ** *
*** * * * * * * *** * * * *
*** ** * * * * * ** * * * ****** ** * ** ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** ** *** * *
* ** * *** ** * * * * **** ** ** ** * * * ** ** = * * * * ****** * *
* * ** **** * * * ** * ** * * ** ** * ** * = * * ** * * ** **
* ** * ** * * *
***** * * ***** * *** * ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.211.222
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users