0 like 1 dislike
7.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* ***** * ****** *
int main()
{
*** * *** * *** * * * * *** **** **** * * *
* * ** ** * * ** *** ** %f ** * **** * * ** * ** ** ***
** *** * *** * ** = (b*b-4*a*c);
** * ******* ****** * ** = (-b + sqrt(D))/(2*a);
* * * * * *** * ** * = (-b - sqrt(D))/(2*a);
*** ** * *** * ****** * * = -b/(2*a);
* ** *** ** ** ** ***** =sqrt(-D)/(2*a);
******* * * ** ** * * *** **
** * * * ****** * *** * *
* * * * * ***** *** * * * * * * * * ** * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** * * ** ** *
** * ** ** * **** * * * * ** * * **** **** * * ** * ** ** = %.2f\nx2 = %.2f",x1,x2);
** *** *** * ** ** * * **

* ** **** * *** * *** if(D==0)
**** *** * * * ** * * **
** ** ** * * *** * * **** ** * * ** ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * ** ** * ** * *** * * * * * * ***** *** ** * = x2 = %.2f",x1);
* ** *** * *** **
* *** * * ** * * *
* * * * ***** *** ***
** **** ** * ** ******* ** * ** *** ** * *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * ** ** *
**** ****** * ** *** * * * ***** ** *** ****** * = * **** * * ** * * *** **
* ******** * **** * ** * * * ** ****** * * * *** * ** * * = ** ******* * * ** * **
** * ** ** * ** *****
* * *** ** * * ** **** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ***

int main()
{
**** *** * ** ******* * n, i;

*** * * * ** ** *** * * * *** * &n);

**** * * *** * ******** ** = 1; i <= n; ++i)
* * * * * *** * *
* * *** **** ** ******* * *** ***** *** * * * % i == 0)
**** ** **** * * ** *** * * ** ** *** * ** **** * *** *** * *** ", i);
* * * * ** ** *

* ** **** *** * *** ** * * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * *** ** *
*** ** * * **

int main()
{
* * *** *** * ** * * * * ** ****
**** * * *** * * ** ** ***** * * * * ** * * *
* *** ** * ** * = * * * ** * *
* * ** ** ** * ** * * ***
** **** *** ** ******
*** ** **** ** * * *** * * *
**** ** *** ** ****** * = -b /(2*a);
**** ** ** *** * ** * * * * *
*** **** * ** ** * * = (-b)/(2*a);
* ** * ****** * * * * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * * **** **** ** ** *
* * * **** ** * *****
** * ** *** * * * **** if(D==0)
* * ** ** ** * **
** ** * ** ** *** * = (-b + * * ** *
* ***** *** * *** *** = (-b - * *** *
* *** ***** * ** * ** *** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** ***
* *** * * ** **
* * * * * * ******** * if(D>0)
*** ****** * * **
** **** * * ** ** * * ** = -b/(2*a);
* ******* ** * * = (-b + * * **
* ****** ** ** ** = (-b - ******
** * ** ****** *** * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** * **
** * **** * **** * ****** * ***
* ** * * *** * * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** **** *
#include *** * ** *** **
int main()
{
* * ** * * ** ** * * ** a,b,c;
*** * ******** * ** * **** * * * * * * * ** * * *** *
***** ** ******* * *
******* *** * ** **** * * ******
* * * * * ***** *
* * * ** * **** ** ** * ** *** * **** * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** ** + *** * *** * - *** * *** *
**** * * ***** ** **
***** * * * **** * ** ***
* ** *** **** *** if (b*b-4*a*c==0)
*** ** * * **
* ** **** ****** * ** ** * * **** ** * * * * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** **** + * * **** ***
**** ** ** ** * ** * ** *
* *** * * *
** ** ** ** ** *
****** * ******* **
**** **** * * * * ** * * * * *** * * * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ********* * ** **** * * ** * ** ** ** **** * * ** * ***
** *** * ** * ** ***
***** ** **** ***** ** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** * **
#include * * ** * *
int main()
{
** *** * * ** * ** ** a,b,c;
* ** ***** ** * ** * ***** *** * ** * ** ** * *** * * **
*** ** * ** * * *** ***
* ** ** * * ** * ** ** *
*** ** ** ********* * *****
**** ** **** ** * *** * *** * * * ***** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** ** + ** ** ** ** - * * **
** ** **** * ** * *
* * ** * **** * *** * *
* ****** * * * * * * ** * if (b*b-4*a*c==0)
**** * ** *** ***
* ** *** *** ****** * ** * * * * ** * * ** *** *** * * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** * + * **** *** * * *
* ***** ***** * * **
** * ** ** * * * * * *
** * ** ** ***** *** * *
**** **** * * ** * ** ***
* * ** *** * * * *** ***** * * * ** ** ** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * **** * ** * *** ***** * * ** * ****
*** ** * ****** ** ** * * * *
* **** * * **** ** * *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * * * *** a,b,c,d,x1,x2;
* * ** ** * **** * ** * **** * **** *** * * *** * ** * * **
** * ** * ***** ******* ** **
* ** **** * * ** ** ***** * *
* * * * ***** ****** *****
* * * *** * * * * ** ****** **
* * * **** ** *** * **
* ** ** * * *** * ** ** ** * ******* * ** * ****** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** **** ***** ****
** * *** ** ** ** * * * * * *** * ** * = %.2f\n",x1);
* * * *** * * ** * ** * **** * * ** * * *** * = %.2f",x2);
*** **** * ** ***
*** * * ** * ** * ** *** * if(d==0)
* * * ****** **** *
**** * * * **** * * *** ** *** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * * *** * * *** * * *** ** * ** *** ** * * ** = x2 = %.2f",x1);
** * * ** ** * * *
**** * ** * * * *
*** *** * * ** * * *
* * * ******* * ** * * * ** ** * * * ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** *** ** * * *
*** ** **** ** *** * ** * * * **** ***** ** * ** *** * ** *** = ** * * * * **** ***
* ***** ** * **** * * * **** * **** * * = ** ***** * ** ** *** ******
** * * * **** ** * *
** * ** * ** ***** ** *** * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** ** *** **** * ** ** * *** **** * * *** * ** *** ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** * **** ** ** * ** ** ** * **** *** * * ** - (4*a*c);
*** ** * *** ****** ** * ** * * * * * ** * ** * * * *
*** * * * * * *** ** * *** ***** * * * ** ** * ** ** * **
** * ***** * * * * * * * * * * * * ****** ** * ** ** (-b+spD)/(2*a);
** * * ** * * ** * ** **** * * *** **** ** * * *** * * * * (-b-spD)/(2*a);
* * **** * * **** ** *** *** * * ****** * ** *** * ** * *** (x1==x2){
* * ***** ****** * * ** *** * ** * * * * **** ** * **** * ** ** ** *** * ** * * * * * *** * **** ** ** * * ** * * *** X=%d\n", x1);
* *** *** * * * ** *** * ** ** * ** ** * *** **** ** **** * * *
*** *** ** **** **** * ***** * * * ******* ** *** *** **** **** * *** * {
* * * *** * * * *** **** **** * * *** ******* ** * **** *** ***** ***** ** * ** * *** ** ** * **** *** * * *** * * * *** *** * X=%d或%d\n", x1, x2);
** * * **** ** ** **** *** * * *** * * * * *** ***
        }
** * ** *** **** *** * ** * **** * if(D==0){
** ** ** ** **** * ** * * **** * * ** ** ***** * ** * * * * (-b)/(2*a);
* ***** *** * * ** **** ** *** * *** ***** * * **** * *** * ** * *
* * ** ** ** * * ** ** ** * ** * **** * ** **** ** ** ** ******** * * * * ** **** **** * ** ** ** X=0");
* ** ** * * ** * *** * * * ** * ** ** * **** ** ***** * * ***
* * * * ** * ***** ** * ***** * * * ** ** ** * ***
*** * * *** * **** * **** *** * ** **** * * * ** * * * * ** * **** ** * * * ** **** ***** **** * * ** * *** * X=%d\n", x1);
*** **** * **** * * **** ** ****** * ****** * * **** * * *
        }
*** ** **** * ** ** * ** *** ** * ** **
* * **** * * * ** * * ** *** **** ** ** ***** ** ** ** * * * *** * ** * * * * ** * * * **** ** *** * * ***
*** * * * * * * * * * * ** ** *** * * * ** * *
    }
* ** ***** * * ** * * ** * * ** * * *** *****
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* **** ** *** * * * a,b,c,D;
*** * * * ** * **** ** *** x1,x2;
**** ******* ***** * ** ** * * * %d * *** * *** ** * * * ** *

*** ** * ** * * *
* *** * *** * *** * * **** ** *
* * **** * **** *** * ** *

* * * ** * * * * *** * ***** A,B,C;
* * * * * * * *

* ** * ** ** ******* * **
* ** * **** * * * *** *** ***** *** ** * ** *** ** * ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and ** * * *
* ******* **** ** * * * *** * * * * ** * * *** * * = %.2f\n",x1);
* * * ***** * * ** ** ** * * **** * * ***** ** * **** *** = %.2f",x2);}

** ** **** * *** if(D==0)
*** ** * * * ** **** ***** * *** * * ***** ** * * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** *** *** **** ** ** ******* * * * ***** * ** ***** = x2 = %.2f",x1);}

** ** * ** ** * * * * if(D<0)
** * * ***** * * * * * ** ****** ** ** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and **** ** * * *
* * **** ** * *** * ** * * * ** ** ** **** bb,d,dd;
* *** ** * * * * ** ** * * * * * * * ****** *** *
* * *** ***** ** ** *** * * * * **** * * * ** **
* * * * *** * **** * ** * ** * * ** *** * ** *** * ** * = * * * ** *** **
**** * * * * *** ***** ** * ** * * * * *** * ** ** *** = *** *** * ** ** * *

* ** ******** ** ** **** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
**** ** * **
int main()
{
*** * **** ** * * ** * * * **** * *
******* *** ** ** **************** ** %f ** *** * ** * * *
*** * ** *** * ** * ** = (b*b-4*a*c);
*** * * **** ****** ** = (-b + sqrt(D))/(2*a);
* **** ** * ** * *** * ** = (-b - sqrt(D))/(2*a);
* *** * * * = -b/(2*a);
* *** ***** * * * * * **** ** =sqrt(-D)/(2*a);
* *** ** * * ** **** ** *
* *** * *
** **** ** * **** * * ** ***** * **** * * * *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** *** *
** ** ** * **** **** ** * * * * * ** ** * ** ** ***** * * = %.2f\nx2 = %.2f",x1,x2);
***** **** ** ***** * ***

** ** * * * ** * ***** if(D==0)
***** ****** * * ** *** **
** * ** **** *** * *** ** * ** * ** * ** * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** * *** * * * *** ***** * * *** * ***** * = x2 = %.2f",x1);
** ** ** * * * * *
* * ***** ** ** ** ** * *
* ******** ******** * * ** *
** * * ** * ** *** ** ** ** * * ***** *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** ***** *
*** * *** * ** *** ** ** *** * * * *** ** ** * * * *** * = * ** * * ***** ***** ***
* ** * * ***** * * * *** * * *** *** * * ** ** * *** = * ** * ** * * * *
** * * * * *** * * *
*** * * ** *** * **** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** ** * ** ** *** ***
int main()
{
* ** ** * * * * * **** *** * * *** * ** ** *
**** * ** * * **** * * * * ** %f * ** ***** * ** **** * **
*** ** ** * ** * = (b*b-4*a*c);
* * * * ** **** * * * = (-b + sqrt(D))/(2*a);
* *** * *** * * = (-b - sqrt(D))/(2*a);
* * ** ** * ** * ******* * = -b/(2*a);
***** ** *** * * * ****** * * =sqrt(-D)/(2*a);
** ** * * *** *** ** ** *
*** * **** * * *** ***
* * * * * *** ** * **** *** * * * ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ******* * * **
** ** ** ** **** * ******* ** ** *** **** * * ** * ** * ** = %.2f\nx2 = %.2f",x1,x2);
** ** * * **** *

** * ** ** * ** * * if(D==0)
** *** ** **
* ** * ** * * *** **** ** * *** * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** ********** * * * **** ** ** ** **** ** * *** = x2 = %.2f",x1);
* ** * * ** *** ** *
* ** * * * * ***** *** **
******* **** * * ** *
* * * * * * **** * ***** * * * ** * ** *** ***** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * **** * ****
****** **** * ****** * ** * * * * *** ** ** ** ** ** = * ***** *** * ** ** * **
* ** *** * ** *** *** ** *** ** * *** * = * * *** *** *** ****** * **
*** * ** *** ***** **** * *
* ** ***** * *** *** * * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.162
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users