0 like 1 dislike
7.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** * ** *** *
int main()
{
**** * * * ** **** ** *** **** * * * *
** *** * * ** * * * * ** * ** %f * * * ** * * * **
*** ** ** ** *** * ** = (b*b-4*a*c);
* * * *** * * * * = (-b + sqrt(D))/(2*a);
** * ***** ** **** * ** = (-b - sqrt(D))/(2*a);
**** **** ** *** *** *** = -b/(2*a);
* ******** **** * *** *** * * =sqrt(-D)/(2*a);
* **** * ** * * **** * *** *
* * * * ** **** *
* ** *** * * * ** * * ** ** * * * * * * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * ** ** ***
*** ** * **** * * * *** ** * ** ** *** * ** = %.2f\nx2 = %.2f",x1,x2);
** * **** * ** * * * ** *

** * * * * * * * * if(D==0)
* ** ** * *
* * ** * ** **** **** ** ** ****** **** ** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * ** ******* * ** ** * * * ** * * = x2 = %.2f",x1);
* * * * *** * * * ******* *
* * * * * ** *** **
** * * ************ **
** * * * * ****** * * **** ** **** ** * * * * **** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ****** * ****
* * * ** * ** * *** * * *** * ** * * *** ** * * = * *** *** * * **
** * ** * *** * ** ***** * * * ** *** = * * ** * * ** * **
* * *** ** * ** * *
** ** * ** *** ** *** * **** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** ** * * *

int main()
{
* * * *** *** * * * * n, i;

*** **** ** *** * ** * * **** &n);

* *** ** **** * ** * * * = 1; i <= n; ++i)
** * *** * ****** *
* * ** * ** * * ** *** * ** * * *** *** % i == 0)
* * * ** * ** ****** * * * **** *** ***** *** *** ** * *** *** * * ** *** ", i);
* ** * *** * * * *

*** ** * * **** **** ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** * * * **
* * *** *** **

int main()
{
* * * * * ** * * * * ** * ** * ****
** ****** * **** ** * * * *** * *** * ****** ******* *
**** ****** * ** = * * * ***
*** ****** ** * * ** **
*** * * **** **** * *
** * * * * *** * *** * * **
* * * ****** **** *** * ***** = -b /(2*a);
***** * * *** ** ** *** * * ** * *
* ***** * * *** = (-b)/(2*a);
*** * * **** ** * * * **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** ** ** *** *****
********** ** * *** * ****
* * ** * * **** * if(D==0)
* * ** * *** * ** *
* ** *** ** ** * *** = (-b + ** *
** * * ****** * = (-b - * * * *
****** **** **** ** ** *** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * *
* * * * * ** *** *
* ** ***** * ** ** * * if(D>0)
****** *** ** * ** *** *
* * * ****** * * ******** = -b/(2*a);
* ** * * * * * ** = (-b + *** *** *
** * * ****** * ** * = (-b - ** * *** *
***** * * * * * * * *** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ***** * * **
*** *** *** *** * ** *
* ** ** ** *** * * **** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include ** * ** ** **
int main()
{
* * ** * ** * *** * ** * * a,b,c;
* * **** **** * * * ** *** ***** ** * ** *** * *
*** ** **** * **
** ** * *** ***** *** ** *** * **
******** ** * * * * **
* **** * * ** * * ** ** * ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * ** * ** + ** * * * * - * * ** ** **
***** *** * *** **
* ***** * ** ** * **
** *** **** ** * * * ** if (b*b-4*a*c==0)
* * ** ***** * **** * *
*** * ** * * * ** * * ** * *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** **** ** + ** * *
** **** ** **** * * *
**** ** * * * **
***** *** ** *** *** *
* * * **** ** * **
*** * ** **** ** * *** * * ** *** * * ** **** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** ** * *** ** ** ** **** * *** * ** ** ** **
** ** * * ** **** ***
** ** *** ******* *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *
#include * ****** ***** *
int main()
{
** * ***** ** * ** * * * * a,b,c;
* ******* * * ** * * ** ** ** *** * * ** ** * * * ** * *
* * ** ** * **
* * ** *** * ***** ** ** * *
*** ***** *** * *
* *** ** * * ** *** * * * ****** *** *** * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** * **** * + ** ** * *** - ** * ** * *
*** * * **** * ** * **
** * * * * * *** *** *
* * * * * * ***** ** * * * if (b*b-4*a*c==0)
**** * * * * ** ** *
* ****** ** * ** *** ** *** ** ** ** ** * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * * ** + * *** *** **** **
*** ***** * * *** *** ** *
***** ** * ** * * * **
* * * ** *** **** * *
** ** ** * * * * ***
**** **** ** * ** * ***** ** * **** * ** ** *** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * *** ** * ** ** * ** * ** * ** * ** ***
*** ***** * ** *
* ** ** * **** ********* 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
**** ***** ** ** *** * a,b,c,d,x1,x2;
*** * **** ** *** *** ** ** * ** * ** ** ** ** ** * * * * *** **
* *** ** * * **** *** ** * * **
* * * * ***** ** *** * **
* * * ** * ***** ** * * * ******* ***
** ** * * ** * ***** ***** *
** * *** * *** ** * *
** * *** *** * * ** * * * * * *** **** *** * *** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * **** **** **
* ** *** * * ** * * * * *** ** ** *** **** = %.2f\n",x1);
* ** **** * ** * * * * ***** * * *** ** * ****** * = %.2f",x2);
*** *** **** * * * ** *
** *** *** * * ** * **** * if(d==0)
* * * *** * * ***
** * *** ** * ** ** * * ******* ** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ***** * * ** * * * * * ** ** *** * * *** * * ** * = x2 = %.2f",x1);
* ** **** * * ****
** * * * **** * *
* **** ** * *
* ** ***** ** * ***** **** ** ** ** * **** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * **** ***
** * * ** * * * ** ***** * * ** * *** * * ** * * **** = *** *** *** * ***** *
* * ** **** * ** ** ****** **** * ** * * * * *** = *** * * * ** ** * *
* * * *** *** *******
*** * * ** ** *** * ** ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * * * *** * * * * *** *** * * ***** * * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** **** * ** * * **** * ** *** * * * ****** - (4*a*c);
* *** ** * * ** ** *** *** * ******* ** ** * ***** **** *
*** ***** *** **** *** ** * * * * ***** * ******** ** ** *** * *** ****
* **** ** * * * * ** ** * * * *** ** * *** * ****** * (-b+spD)/(2*a);
** * ******* * *** *** **** ** ** * * * ** * * * *** ** * * * ******* (-b-spD)/(2*a);
*** ** ******** * * * ******** ** *** ** ****** * * *** ******* *** (x1==x2){
**** * * ** * * * * * * ***** *** * * * ** **** ** **** * ** ** * ** * * * * * ******** * * * * **** ** * * ** *** * * * X=%d\n", x1);
* * ***** ** ** * * * * *** * * ** ***** **** ** ****** *
**** *** **** *** * * * * * ** * ** ****** ** ** ***** ** {
* ** **** *** ** ******* **** * ***** * *** * **** ***** ** *** * ** * * * *** ***** * * ** * *** ** ** *** X=%d或%d\n", x1, x2);
* **** * ** * *** *** ** ** *** *** * * ** **** * ****
        }
****** **** * ** * *** ** ** * ** **** if(D==0){
** * * ** * *** * * ** * ** * ** * ** * ** * * * (-b)/(2*a);
*** * ** * ** * *** * * * *** ** ** * * * * * * * * ** *** * *
* *** ** * * ** ** * * **** *** * * *** ***** ****** **** *** ** * * * ******** * **** * *** **** X=0");
* **** ** ** ** ******* **** * ** * ** * * ** * ******* * **
** * * ****** ** * * ** ** ** * * ****** * *** ** ** ****** *****
** * * * * * * * ***** ** * * ** * * ** ****** ** **** * * ****** ***** *** *** * ***** *** * * X=%d\n", x1);
*** ** * * * **** * ** * * **** ***** * * ** * * ** *** ***
        }
* * ** * * * ** * * * ** * **
* ** *** **** *** * ***** * **** * * * * ***** * * **** *** *** *** ** ** * * *** * * * * ** *
* ** ** * * ***** *** ** * ** * * ** ** *
    }
* * *** *** ** * ** *** ** ** * * * *** * * ***** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
******** * * * ** ** ****** a,b,c,D;
* *** *** ** * ** ** *** * x1,x2;
* ** ** * *** * * ** * ** %d * * * ** ** *** * ****** ** *

* ***** ***** * ******
** * ** ** * * *** ** * * * * * * *
* * *** * * **** *** * *** *** **

** **** ** * ** **** ** ** A,B,C;
*** *** **** * * ***** ** * **** *

* ** * * ** ** *
**** * ***** ** ** *** *** * * * * * * ** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and ******** **
*** ****** * * * * * * * * ** **** *** ****** *** * = %.2f\n",x1);
*** * ** * * * * * * ** *** * ** * ** ****** * ** = %.2f",x2);}

** * * ** ** ********* ** if(D==0)
* * * * ***** * * * * ** * * * ** * * ** * * ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
*** * **** * ** * * ** * * ** **** ***** ** ** *** ** = x2 = %.2f",x1);}

**** *** *** *** *** ** if(D<0)
** ** ** * *** * ** * ** *** ****** * **** * * * **** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** * * * ** *
** * ***** ** * ** ** * ** * **** ******* * ** ** * ** bb,d,dd;
* *** ** * ******* * *** ** *** ** * * *** * * * *
*** ** * ** * * ***** * ****** ** *** * ** * ******* *** **
*** ** ** ***** ** * ** *** ** * * *** * * ** ***** * ****** = ****** * * *****
* * * * * ** * **** * **** * ***** * ** ** **** = * *** *** * ** *

* ***** * ** * * * * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** ***** ** * *
int main()
{
*** * ** * ** * * ** * *** * * * * * ** *
* ** * * * * * ** * * * *** ** %f *** ** ***** ***** * * ** *
* * ** ******** * * = (b*b-4*a*c);
**** ** ******* * **** ** * = (-b + sqrt(D))/(2*a);
* * *** * **** **** * = (-b - sqrt(D))/(2*a);
* * *** ** * **** *** ** * = -b/(2*a);
*** *** * * *** * * * ** =sqrt(-D)/(2*a);
* * ** ***** **** * **
* ***** * ****** **
* * ** *** * **** **** ** * **** ** **** **** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ***** **** **
**** * ** * * ** * * * **** ** ** * * * ***** * = %.2f\nx2 = %.2f",x1,x2);
* * ** * ** * *** **** * **

* * * **** * * ** * * if(D==0)
** ** **** ** * * ****
* * * * * * * ** **** ** ** * *** * * * **** *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * **** ** * * ** * * ** * *** * * ** = x2 = %.2f",x1);
* *** * * * ** **
* ********* **** * * ** ** * *
** ***** * ** * * *** *
* * * ** *** ** * * ** ** * *** **** ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** ***** **
* ***** * * * ******* ** * *** * * * * ** * ** *** * = ** *** * * * *** *
**** * * *** * ** * * **** * * ** ** * * ***** *** ***** = * ** ** * * * *** ** ** *
*** ***** * *** **
* ** * **** * **** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* **** * *** *** *
int main()
{
* *** * * ** *** * *** * ** *
* **** ** ** * ** *** * * * %f * * *** * * ** * * ** ** *
* ** *** ** * * ** = (b*b-4*a*c);
** * * *** ** * * = (-b + sqrt(D))/(2*a);
** **** ** *** *** ** = (-b - sqrt(D))/(2*a);
* * * *** ** ** ** * *** * ** = -b/(2*a);
****** * * * **** ** ** ** * =sqrt(-D)/(2*a);
* **** *** ** **** ** *** ****
** * * ** * * * *
* * * * ** * ******** * ** *** * * ** * **** * * ** * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** * *** *** *
* *** *** ** ** *** **** * * ***** = %.2f\nx2 = %.2f",x1,x2);
** * * * ***** ** *

*** * * * *** * **** if(D==0)
* ****** *** ** *
* * ***** ** * * ***** * *** ** ***** * *********** * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * ** * **** * ******* *** *** * *** * *** ** * *** ** ** = x2 = %.2f",x1);
* * **** ** * * * * **** *
*** ** ******* * *** *
** ** *** *** ***** **
** **** **** ** * * * ******* * * *** * *** ** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * *****
* ** * * ***** * * * * **** ******* * **** * **** * ** = * * * ** * ** * ** *
* * *** * * ** * *** * * ** * * * * * *** = * * * * * ****
* * *** * ** * * *
* ** * *** ** ***** * *** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.104
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users