0 like 1 dislike
9.2k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 9.2k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** ** ***** * *
int main()
{
* *** ** *** * * * ***** * * ** * * * * ** * * ** * *
** * ** *** * * * * *** * %f * *** *** ** ****** * ***
* *** * * *** * * *** *** = (b*b-4*a*c);
* **** * * ** ** * ** *** = (-b + sqrt(D))/(2*a);
* *** ** ** **** ** ** * = (-b - sqrt(D))/(2*a);
**** * * ** * * * ** = -b/(2*a);
* * * * ** ***** * =sqrt(-D)/(2*a);
* ** * * ** * ** ** ** * **** *
* * * * *** * *
** ***** * * *** * * *** *** * ** * * * ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ***** ***
**** ** * * ** * * **** * *** * ** * ** * ** ** ** * = %.2f\nx2 = %.2f",x1,x2);
** * * * ** * *** ** *

* * * * * ** ** ** ** ** if(D==0)
* * * ** ** * **
*** * **** * * *** * * ** ** *** * * * *** * ********* of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
***** * *** **** *** * * * *** *** * * * *** * * * = x2 = %.2f",x1);
** * ** * * * ** **
* ** *** * ** * **
* **** ****** * *
**** * * ** *** * * * ** ***** * ** ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * * *
** * ** ** * * * *** * * * ** * * * * * = **** * ** ** ** **** ***
*** *** * * ** ***** * * *** * *** ** * * ** * = * * *** *** *** * ** *
** ** * * ** * * * ******* *
** * * * ** * ****** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * ** **

int main()
{
* * * * * * * * ** n, i;

** ***** ** * ** ******** ** * ***** *** &n);

** ** ** *** ** ** * * ** = 1; i <= n; ++i)
** ** * ** ** ** *
* ** *** * * ** ** * * ** * *** * * * % i == 0)
* * ***** * * * **** ** * ** ** ** * * ** *** ***** * ** * * *** *** ", i);
* * ** * *** **

* * * * ** *** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
***** * ** *
*** *** **** * *

int main()
{
* ** * * *** * ***** *** ** **** * * ***
*** * * * * * * * * ** *** * ** **** ** * **** ** * * **
** *** ** ** * * = ** * * **
** * **** ** ***** * ** ** ***
* * **** *** * * * *
* ** **** ******** ** * ** * *
****** * * * * * ** * ** = -b /(2*a);
**** * * * * * ** *** ** * * * *
** * * *** ** ** **** ** * = (-b)/(2*a);
* * *** *** * ** * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** **** * *** * * *
*** * * ****** * * **
* * ** ****** * * * if(D==0)
** ** * ** * * * ** *
**** * ** * **** * = (-b + **** *
* ** ******** * ** = (-b - *** * * *
* ** *** * * ** *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ******* * ** ***
* * * * * * ** ****
** *** * * **** * ** if(D>0)
**** ***** *** * * * * **
* ** * * ** ** ** *** * = -b/(2*a);
* * * ** * * * * = (-b + * ****
*** ******* * * ** ** ** = (-b - *
* * * *** * * *** ** **** * ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * ** ** *
* ** * * *** *** *****
* * **** * * ********* **** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ***** ****
#include * ** * *
int main()
{
* * * ****** * ** a,b,c;
* * ** ** ** * * ***** * * *** **** ** *** ***** ***
***** ** ***** ****
*** **** **** ** ** ** **** **
* * * * * ******** * ** *
** **** ** * *** * * * * ** * * * ** *** ** **** ** ****** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * ** * * * + * ****** * * - * ** * * * * **
* ******* * ** ****** * *
** * ****** *
* * ** * ** * if (b*b-4*a*c==0)
* * ** * * ***** ** *
* ** ** * * * * * ** * * ** *** * ** * * * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** * * + ** * * ** **
* * ** * *** * * * * *
* * *** * * * ** * *
*** * ** ** * * *******
***** **** **** * **** *
* *** * * * ****** * * ** ** * *** ** * ** ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * **** ***** ***** *** *** * * * * * * ** * **** **
* * ****** * ** * ***
**** * * ** * ** * ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ***** *** *
#include ** ** *** ** * * *
int main()
{
**** *** * **** * * ** a,b,c;
* ***** * * * * * ** **** * * ** ***** **** * ** * **
* ** **** * ** **** *
* ** *** ***** ** * * *** **** ***** *
* ** *** * ** ** ** **
** * * ** * * ** ** **** * * * **** * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** * ***** + **** * ** ** * - * *
* * ** * ** * * **** * * *
* ** *** ** ** * *
* *** ** *** ***** * if (b*b-4*a*c==0)
****** **** * *
*** ** ** ** * *** * * *** * ** * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * + * ** * *** * *
** * * ** **** *
* *** ** ** * * ****
** **** * * * ** * **
** ** * *** * * ******
* * * **** * ** * * ** **** * * * * * *** *** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** *** ***** ** * ** * ** *** * *** ** **
*** * ** ** * ** * * ***
* * * **** * ** **** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** ** * **** * * ** a,b,c,d,x1,x2;
* *** * * * * *** *** ** * * * ** * * ** *** * * ** *
* * * ** * * * ** **** * * *
* *** * ** * * * ** *
* ** *** * ** * * ** *** * *
****** * *** *** * **** **** **
** * * ** **
** * *** *** ***** *** **** * * * ** * **** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ** * *
**** * * * * ** * * * ** * * * * * * * *** = %.2f\n",x1);
* *** ** * ** *** *** * * ** ** * * * * ***** * = %.2f",x2);
***** * *** ** ** * *
**** * * ** ****** * if(d==0)
* * ***** *** *** * *
* *** * * * ** * * * * ** * **** *** ****** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** * *** **** ***** *** * * * ** * ** * * * = x2 = %.2f",x1);
* ** * * * * ** ** *
* ** * ***** * **** ***
** ** * *** *** * *
** ** **** * *** *** *** ** ** ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** ** *******
**** * * *** **** ** ** * ** * ** * ** * * * = ** **** * ***** *** * *
*** ** **** * * * * * *** *** * ***** *** * ** * = *** ** ** * *******
* ** **** * * **** * * *
* ** **** ** *** **** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* *** ** ** ** * ** * * * ** ** * *** ** * *** ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* *** * ** * * * ** *** *** **** ** *** - (4*a*c);
* ** * ** **** * * * ** ** *** * ** * * *** * ** ***
** ******* * ***** ****** ** * ** * * * * **** *** * * ** **
*** *** ****** * * ** * ** * ** ** ** * * *** * ******** ** *** ** * * (-b+spD)/(2*a);
** * * * * **** *** ** ** **** *** * *** * ** * * (-b-spD)/(2*a);
**** ** * ** **** ** **** ** *** *** ** ** ***** * * * (x1==x2){
* * ** ***** * **** *** * * **** ** ***** ** ** *** * ** * ** * * * *** *** * *** * * *** *** *** * ** * * * **** **** ** * * X=%d\n", x1);
* * * * *** * * * * * * * **** * * *** * ** **** * ***
* * * * * * *** * * **** * ** * * **** * * * ** ** * {
**** * * * * ** ** ** ** * ** ** ** ** ** * * * **** ** * * ** * * *** * * * * *** ***** ** * * ** ** X=%d或%d\n", x1, x2);
** **** * ** *** *** *** * * * * **** ** * **** **** * * ***
        }
** * * * * ** ** ** * * * *** ** ** ** * * * if(D==0){
** **** ** * *** ** * ** ******* ***** * * * * * ** ** * * * * (-b)/(2*a);
* ***** *** ** * * ** * *** *** ** * * * * * * *** **** ** ** *
* ** **** * ***** * * ***** * * ***** * * **** ** **** * ** * * **** ** ** * * ** * * * * * X=0");
** ** ** **** * * ** ***** * * * *** * ** ** *** **** ** ** **
* * ** * * **** * * * * ** *** ** * ** * **** * * * *** * ** * * **
** * ** ** * ** * * **** * * ***** * ** * * ** * * ** * ******* * ** * ** ** ***** X=%d\n", x1);
*** * **** *** ** * *** * *** ** * * **** ***** **** * *** ** ** ** * ** *
        }
* * * ** * * ** *** * ***** * * * * ** **** * *
****** * * ** * * * * * * * **** *** ** * * ** ** *** ** * * * ***** **** * ** * * * * **
*** ** * ** *** * * * *** * * ******* * * *
    }
* * * * ** ** * * ** * * * * **** **** * * * ** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
*** ** * * * ** *** ** *** a,b,c,D;
* * ** * * ** * * x1,x2;
* ** * * ** ** *** *** * ***** *** %d ** ** * * * ** ** ***** * *

* *** * * * * ** * *
* ********* * ** ** ***
* * ** ** * ** * ***** * ** ** ***

** ****** ** **** * * ** * A,B,C;
** * * * * ***** * * * *

* **** * ****** ***** ** * ***
* * *** * * * ** ** * ***** * * * * * *** *** * * * *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and ** * * **
** *** * ** ** * * ** * * ***** *** * ** * * *** * * * = %.2f\n",x1);
**** ** * * **** ** * * * * * ** * * * ** ** * *** ** ** = %.2f",x2);}

* ***** *** ** * * * * if(D==0)
**** *** ** * *** ** **** *** ** * * * ** * **** * ******** ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* ** * ** ****** ***** ******* * *** * *** * ** * **** * * *** = x2 = %.2f",x1);}

** * **** ** **** * ****** if(D<0)
* * *** ** * * * *** * ** * *** ** * ** *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** * * *** * * *
* * * * ** * * * *** *** ** *** *** * * ** *** * ** ** ** bb,d,dd;
* **** * * * ** * *** ** ** ** * ** * * * * *****
* * ****** * * * ****** ** * * ***** * ** ** * *** ** * *
**** * * **** **** * *** ** *** ** * ***** *** * ** * * = *** * * *** * ****
* * * *** *** *** * * ** ***** ***** * ****** * *** * = * **** * *** *****

* * * * * * * *** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * * ***
int main()
{
** * **** ** ** * * * * **** * *
***************** * * ** ** * * %f *** ** *** **** ** * ** * *
*** * * * ** *** = (b*b-4*a*c);
* ***** ** * *** = (-b + sqrt(D))/(2*a);
*** ** * ** * * * * * * = (-b - sqrt(D))/(2*a);
** *** *** ** * ** *** * = -b/(2*a);
***** ** * * ** ******* =sqrt(-D)/(2*a);
* **** * ** **** *** ***** ** *
* ***** ***** **** * * *
** ** *** * * *** * ******* ** * * **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ***** * ** * * *
* * * * * ** ** * * * *** * * **** *** *** = %.2f\nx2 = %.2f",x1,x2);
* * * * * * * * * * ****

* * * * * **** ** **** * if(D==0)
*** ** * * ** ** ***
* * ** **** ** * * * * * **** *** * *** *** ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** ** *** *** ** * ***** ***** * ***** **** = x2 = %.2f",x1);
***** ** * *** *** **** ***
** ** * *** * * ** *
**** *** * * ** * * *
* * * * ******* ** ** ** * * * * *** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** **** *** *****
* * ** ** ** * ** * * * ****** ** * * ** * ** **** * ** ** = ** ** ** * * *** *
* * * * * **** * * **** * ** * * * * * *** = * ** * ** * * * * *
** ** *** * * ** *** *
** ** *** * * * * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* **** * ** * ** **
int main()
{
* *** * * * *** ** *** * ** ********* *** * *** *
* *** ** ***** ****** * * * * *** %f * *** ** ** * ** *
* *** *** * *** = (b*b-4*a*c);
* * ** ********** * * * * = (-b + sqrt(D))/(2*a);
* ** **** **** * * * = (-b - sqrt(D))/(2*a);
*** * *** * ** * * = -b/(2*a);
***** * *** ** *** * =sqrt(-D)/(2*a);
** ** ** * * * *** ** * * **
***** * * *** * * *** **
* ** ****** * **** * **** * * * * * ** ** * * * ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * *** * **
** *** ** * *** ** *** * ** * * ** * ** * * *** * ** ** = %.2f\nx2 = %.2f",x1,x2);
*** * * * * * ** *

* * * * ** *** ** * * if(D==0)
** * *** * * ** ******
* ** * * * * * ** ** * *** ** * ** *** **** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** * ** * * * * * * * * * *** ** *** = x2 = %.2f",x1);
*** * ** * *********** ******
** * * * * ** ** * *
* * *** ** * * * ** ****
** ****** ** ** * * *** * ** * * * ******* * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ** * *** **
* *** * ** **** * *** ***** * * ** * *** * *** * *** *** = **** ** ** * **** *
* * ** ** *** * ** ****** *** * *** * * * *** * = ** * ** * * * ***** ** * *
* ******* *** **
*** * * ** ****** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.85
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users