0 like 1 dislike
17.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* ***** ** * * ****
* * ***** * *

int main() {
***** ** ** * * *** ** * ****
** * *** *** * * ** * * ** ** %f ** ** * * &a, &b, ** * *
* * ** **** **** ** *** **** **
*** *** **** **** * ** * * * *** {
** ** ** * **** * * * * * * ** *** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * = ***** ** = * * *** *** * a, b, c, (-b)/(2*a), *** * (-b)/(2*a), ******
** ** * **** *****
* * * * *** ***** **** ** * if(d==0) {
* ***** * ** * ** * * * ***** ***** * *** ** ** * * * * *
*** * * * * ** ** * * * ** *** * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** ** a, b, c, x1);
** * **** ** *** **
*** * ** * * *** *** * * * ** ** {
* * * * * **** * ****** * *** * ** ** ** * *** ** * *
* * * **** * * * *** * * * * ** ** **** ******* * * *
* ***** ** * * ** * *** * * ** * ** *** **** ** * ** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * ** = %.2f\nx2 = **** * a, b, c, x1, x2);
* * * ** * **** * * **
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** **** *
* * ****** * *
#include * * * ***

int main()
{
* * * ** * ** ** * * * ** * *****
***** * * ** * *** ***** *** *** %f * * * ** * * ** * *
* *** * **** * *
**** ** * ** * * *** * * * *
** *** ** * **** * *** **** **
** * *** * * ** *** * ** * * ***
** * * * ** ** ****** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** = %.2f\nx2 = * * * *** ****
** * * * * ** * * * * if(D==0)
******* * * * * ** ** * * ******* of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * ** * *** *
*** ** ** * * * *** *
* ** * *** * * ** ***** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * = *** * = ** * * **** *** *** * ** * * * * * ** * * * *** *
*** * ** * * * * ** * *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** * *
** * * * *** * *
* * *** **

int main()
{
*** * * ** * * * * * * *** * * * *
* ****** **** ** *** * ** ** %f * ** * ********** *** **
* ** ** ** * ** * * * ** *
* * * ******* * ** * *** * *
** ******** * * *** * * ** ** **
** ** * ** ** * * ****** *** ***
* ******* *** * * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * = %.2f\nx2 = ** * * ** * * *
* **** * * * *** * * *
** ** * * ** * * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ***** * *
* * * * * ** ** * * *
* * * * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * = %.2f + **** * = %.2f - *** * ** * * * * ** *** ***** **** * *
** ** **** * * ** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * ** * ** *** ** a,b,c,x1,x2,D;
** * **** *** *** ******* * ** * * * * %f * * * *** ** * ***** *
** * ****** ***** * ** * * *
** **** * * *** = (-b + sqrt(D))/(2*a);
******* ***** ***** * ** * ** = (-b - sqrt(D))/(2*a);
* * ** * * ** * * *** ** ** *
* * * * * * *** * * * * ** * ** * ***
* * * *** * ** ** *** * * ** * * **** * * ** * *** ** * * ***** ***** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * * * *** *** * *** * **** ** * ** * *** * * *** * ** * ***** * ***** *** *** = %.2f\n",x1);
* * **** ********** * * ***** * * *** **** * * **** ** ** * ****** * * *** = %.2f",x2);
* ** * * * * ** * ** **** ** * ***** * * * * *
** * * *** ** ** * **** if(D==0)
* ** * * * ** ** * *** ** *** * * **
** * ** **** *** ** * *** *** *** ** *** * * * ** ********** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * ** *** *** ** * **** *** ** * * ***** ** ***** *** ***** ****** ** = x2 = %.2f",x1);
* **** ** **** * * *** ** ***
** **** **** ** * ** ** ***
** * ** *** * ** * ** **** *** *
** ** ** ** ** * ** * * **** * *** *** * * * *** ***** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* *** * ** * * * * * ** *** ******* * ** ** * * * ** * * = * * * ** *** ** *** * * * *
* ** * * * **** *** ** * ** * *** * ** * ** * * **** * * ** = * ** *** ** ** ** * * * **
** * ** * ** * * ** * * * *** **** * **
* * * * * ****** * *** *** *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** **** ** ** * *** * a,b,c,x1,x2,D;
*** ***** *** * * * ** * * *** ** %f ** *** *** * * * * * *
** * *** * * * * * **** *
** * *** * * **** = (-b + sqrt(D))/(2*a);
* * * * * ** *** ** = (-b - sqrt(D))/(2*a);
* * * * *** * * * * * *
*** * *** **** ** ***** ****** * * * ** ***
** * *** ** **** * *** *** ***** *** ** *** ** * ** **** **** ** *** * * *** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
** ***** * ** ***** ** ** * **** ** * ***** ** ****** * * * * * ** = %.2f\n",x1);
* ** * ******* ** * * * * **** ******* ** * * * * **** * ** ***** * * ** ** = %.2f",x2);
* * * * ** * ** * * * * * ***** **** ****
* * * * ** ** * * ***** if(D==0)
** * * * * * *** ** * * * * *** ** * * *** * ***
** * * *** *** ** ** * * * *** * ** * *** ***** *** * ** * * * **** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
** ** *** ** * * ** * * * ** *** * * *** * * **** * * * ** *** = x2 = %.2f",x1);
***** ** ***** ********* **** ** ******* **
** *** * * *** * * * *
* * * * * **** ** * ** *** * * * * * *** * ** *
** ** * **** *********** * * *** ** ** *** * * ** ** ** ** *** ** * * *** * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * * ** **** ** ** * ** * ** ** *** * * *** * **** ***** ** * * * ***** ** * = *** * ** * ********* **
* * * *** * ******* * * * ** ** * * * * * * **** * ** ** ** *** * = *** *** ***** *** ***
** * * ******* * * ** * ****** ** ****
* *** ** ******** * * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* ***** ** ********
* ** * *** * *
int main()
{
* ****** * * * * * *** ***** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * **** * * * *** **** * * *** * * **** *** * ****

* * * * * * * **** ** * ** * * **** of %.2fx^2 + %.2fx +%.2f = 0 * * *** *
* *** ** * ** ** * = (b*b-4*a*c);
** * * ** ** ** ** ** * ** ** (D < 0)
* * * * ** ***
** * * ** * * *** *** complex and * ** ** *
* **** * * * *** **** * ** ** = * * ** ***** * *** *** **
** * * * * ***** ** ** * * = ** * * * * * * * * * ** * * *
* * **** ******* *
** ** ******* ** ** (D > 0)
* * * * *** * *
*** * **** * * ***** * ** ****** real and ** ****** *
* ** ** * ** * * * * ***** ** * = * * * ** + sqrt(D))/(2*a));
* **** * * *** * ***** ** * ** = %.2f",(-b - sqrt(D))/(2*a));
* * * * *** * *
* * ** ***** ** ** **** ** * (D == 0)
* * ** **** ** ** *
* ** ****** * ** ** * **** * ** * * ** real and same\n");
**** ** * ** * * * ** ** * **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** **** ** ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* **** *** * ** *** ** **
** * ** * **
int main()
{
*** * * * * * * * a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** ***** ** * * *** * * * * * ****** ** * * *

* * *** ** ** **** * * * *** of %.2fx^2 + %.2fx +%.2f = 0 ** * **
** * * * * * **** = (b*b-4*a*c);
*** *** ** *** ** ** ** *** (D < 0)
** ** ** ** * ** *
* * ***** * * *** *** * * * *** complex and ** **********
* * **** ** * * * **** **** * = * * * *** * * ** *** * ** **
** *** * *** **** * *** * * ** = * *** ** * ***** ** * * * **
** * * * * * ** * * **
** ****** ******* (D > 0)
*** * *** * * * *
** * ****** * * ****** * * * * real and *** **
* ** *** ** * * * ** * ** *** *** = * ** ***** + sqrt(D))/(2*a));
*** * * ** *** ** * *** * ** = %.2f",(-b - sqrt(D))/(2*a));
** * * * * * ** ** * ***
** *** ** * **** *** *** * (D == 0)
***** * * * ***
* * ** * * * **** * * ** * real and same\n");
* * * * * *** ** * * ** ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * * * **** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ** * *** *** ***
***** ******* *
int main()
{
* * *** * * ** * a,b,c,D = 0,x1 = 0,x2 = 0;
********** **** * * *** ** * * * ******* **** * ** ** ** **

* *** ****** *** * **** *** of %.2fx^2 + %.2fx +%.2f = 0 **** * **
*** * * * **** * ** = (b*b-4*a*c);
* ***** * * * * *** **** (D < 0)
** ** **** * *** * *
* ** * ** ** ** * complex and * * * *
* ***** ***** * * ** * ** * *** = * *** ** ** * *** * **
* ***** **** *** *** *** * * *** * = * * * * ** ** * *** * *
* ** ** ** ** * *
***** * ** ** ****** *** ** (D > 0)
* ** *** * ***** ** *
* * * ** * ** *** ** ** * real and * * *** *
** * ** ***** * * ** * * * * * * * = * * * * + sqrt(D))/(2*a));
* ** ** * ** *** ** *** * ** = %.2f",(-b - sqrt(D))/(2*a));
******** ***** * *** *
*** * ** ** **** * (D == 0)
* * * *** * * *
** * *** *** * * * ** **** real and same\r\n");
** ** * ** ** * * ** *** ***** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * ** **** *****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * **** * * **
** * ** * * **
int main()
{
** ** * **** *** * ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** * ** *** ** * ** ** ** * * ***** *** * *** * *

** * ** ** * * ** * ******* of %.2fx^2 + %.2fx +%.2f = 0 ** *** * *****
*** ** * * ** * * ** * = (b*b-4*a*c);
** *** *** *** * **** * (D < 0)
* * ** *** * ***** **
*** ** * * ***** * * * * *** * complex and * * ** ***
** *** * * * * ** ***** ** * * = * * **** * * ** ** ** * *
* *** ** ***** **** * * * ** * = *** * * **** * ***
* * ** * ** ** * *
** *** ** ******* ** * (D > 0)
* * * *** ** * ** ***
* *** ** * ** *** * ** * *** real and * * ** * *
* * * ** * * * * * **** * * * * * * * = * * * * * + sqrt(D))/(2*a));
* * ********** * ** * ** * = %.2f",(-b - sqrt(D))/(2*a));
***** **** **** * * *
** * ******** ** ******* (D == 0)
* ** ** ** * ***
* ***** * * * * * ** ** real and same\r\n");
* ** * ** ** *** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * *** * * ****** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ***** * *** *
*** * ***** * **
int main()
{
**** * * * * *** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* *** * *** *** * ***** ** * * * * * * **** * * * *

* * * **** **** * * *** *** *** ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** * * * **** ** * * = (b*b-4*a*c);
** ** * * * ***** = (-b + sqrt(D))/(2*a);
**** * **** * *** ** ** * = (-b - sqrt(D))/(2*a);
* * ** ** ***** * * * ** ** * (D < 0)
** * ** * ** ** * * * *
* **** *** * * ** ** * ** **** *** **** complex and ** ** * ** ******
** * ** *** ** * * * * * ****** = * ***** * * * * * **** * ***** *
* ** * **** * * ** * ** * ******* * = * * ** ** *** ** ** ** * *
* *** *** *** * *
** * * *** * * * * (D > 0)
* * * ******** * ******* *
** * ** * * ****** *** ** real and ** * ****
* * * * * ** * ******** * * * ** = ***** * *** ***
** * **** * * * **** * *** * = %.2f",x2);
* **** *** * *** **
* * ** * ** * **** *** * * (D == 0)
* ** ** * *** * ***
*** ** * * ** **** * * * * ******** * real and same\r\n");
******* * ** *** * * * * * * = x2 = %.2f",x1);
* ** ** ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users