3 like 0 dislike
7.1k views

如果在矩陣中,多數的元素並沒有資料,稱此矩陣為稀疏矩陣(sparse matrix),由於矩陣在程式中常使用二維陣列表示,二維陣列的大小與使用的記憶體空間成正比,如果多數的元素沒有資料,則會造成記憶體空間的浪費,為 此,必須設計稀疏矩陣的陣列儲存方式,利用較少的記憶體空間儲存完整的矩陣資訊。

在這邊所介紹的方法較為簡單,陣列只儲存矩陣的行數、列數與有資料的索引位置及其值,在需要使用矩陣資料時,再透過程式運算加以還原,例如若矩陣資料如下 ,其中0表示矩陣中該位置沒有資料:

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

這個矩陣是5X6矩陣,非零元素有4個,您要使用的陣列第一列記錄其列數、行數與非零元素個數:

5 6 4

陣列的第二列起,記錄其位置的列索引、行索引與儲存值:

1 1 3
2 3 6
3 2 9
4 4 12

所以原本要用30個元素儲存的矩陣資訊,現在只使用了15個元素來儲存,節省了不少記憶體的使用。

 

請寫一個程式用上列的方法壓縮稀疏矩陣。

 

輸入說明:

一開始會輸入兩個正整數M N,代表矩陣的大小。接下來會有M行,每行N個數字。

 

輸出說明:

請輸出壓縮過的矩陣

 

輸入範例:
 

5 6
0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0



 

輸出範例:

 

5 6 4
1 1 3
2 3 6
3 2 9
4 4 12
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10
| 7.1k views

12 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(){
***** ** * ***** * * ***** a,b,i,j,num=0;
* * * ** ** * * * ** * * ***** * * **
** *** * * * ** * * * ** * * * * * *
* * * **** * * ** ** * arr[a][b];
    
*** ** * ** * ***** * ** * * *
** ** * *** * *** * * ****** * * * *** ** ** **
* ****** *** * * * * *** * ** * * ** * * * ** * * *** ** * ** * ** * * * **
* * * ***** * * * ** * ** ***** * ** * **** * * *
**** * ** *** * * * * * * ** * ***** ****** * ** ** *
** * ** * **** **** ** * *** ***
**** * ****** * * ** *
    
* * **** ** **** * **** * * * %d %d\n",a,b,num);
    
** * ** **** * * * *** * ** * * * ** ***
******* ** * * * ** * * *** ** *** *
** *** * * * * * ***** * *** * ** ** ***** * *
*** ** ** ** * * **** *** ** ** * ** ** *** * **** * * * * %d %d\n",i,j,arr[i][j]);}
*** *** ******** * * ** *** * ***
    }
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** * ** **** * * * * * ** r[1000][3];
* * *** * ******* * * * * * M,N,j,k,temp=0,count=0;
    
** * ********** *** ** *** ****** * %d",&M,&N);
    
*** * ****** ********** ** ** * ** **
* * * *** ** * * ****
* *** ** *** ** * * * * * **** * * *
* * * ** ** ** * * * *
****** *** * *** ** * *** ** **** *** ** ** *** ** ** * ** *** * * * * * **
** ** * * * * * ** ** * * * ** * ** ** * ** ****** * *
* *** ** * * ** ** * * * **** *** * * ** * *** * * *** *
**** * * * * * ** * **** ** * * * ** * **** * *** ** *** * ** ** ** *
**** * ** **** * * ** ** ** *** * ** * * ** *** **** **** * ** ** ** **** * ******
* ** **** *** *** *** ** * * * ** * ** * * **** ** * * * **** ** ***
** ** * * * * * ** *** **** **** *** * * * ***** **** ** * ** * * *** * * *** ** *** * ** * * *** ********** * *
*** ** *** **** * * * * * * ***** * *** *** * ** ** **** ***** ****** *** **** * ** *** ** **** **** ** * * * * *** *** *** ** * * ** * ** * ** * * ** ** *** * ** * ** * ** ******* * **** *
* ** ** * * ** * *** ** ** * * * ** *** ** ** **** ** * * ** * ** ** *** ** * * **** ** * * ** *
    }
   
   r[0][0]=M;
   r[0][1]=N;
* * ******* **** ** *
   
* ** **** ** ** * ** * *** **
   {
* * * **** ** * ** *** * * ***** *** %d %d\n",r[j][0],r[j][1],r[j][2]); * *** *** * **** ** * ** * * ** * ** ** ****** * * *** *** * ********* ***** *** ** * *** * *** *
   }
    
}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

2 like 0 dislike
5 answers
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10
| 3.5k views
2 like 0 dislike
18 answers
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10
| 8.8k views
4 like 0 dislike
16 answers
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10
| 14k views
3 like 0 dislike
16 answers
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10
| 10.2k views
2 like 0 dislike
3 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited
| 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users