[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include      * *  ** ***  *

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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  *   *  ** * **
#include *   ** *  ** *  

int main() {
*   *   *   * * int a;

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* *****    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **   **  *** *  **
#include ***** * ***  *  

/* run this program using the console pauser or add your own getch, **   *  * ** * ** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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   ****  * ***   ** * **
* *   *      *  ** ** 
int main(int argc, char *argv[])
{
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* ***    **  *   ** ** * ** **  * ** ** *   *  ***  *  ******   *  ****  *** **
 *    * *  * ****  ***      0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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* *  ***   *       *** *        * **   ****  ********   *  * * * **
*  *    **   **  *  

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
*  ** * * ****   *   **
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int main(int argc, char *argv[])
{
** * ** **  * *    **  ****  *  i, a;
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*** ***  * **** * *** *  *****  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
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** *   *   *  * *  ** *
int main(int argc, char *argv[])
{
* *  * * **   * ** ** * *  i, a;
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  ** * ** *    * *  **      *     * * ** * ***     *  **  *   ****  * * *  
  *** * * **     *****  *  ** * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
**** **  ** *** **
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int    **  argc, char  ** ** {

** *            * int a=10;

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**    **    ****** **  *  * 
 ** **  *       ** a != 10 );
    *    * **   ** 
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** * * * **   *  

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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  * *    *   ***** **   ***

int  * * argc, char **  *   {

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* * * * * ** * *   ***** *   *** * * *     * **  ** *** * * 
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****    * *  *  * *** *    **  **   
**   * *  * *  *  ***   *****  if( a   * 10)
* *  **    *  **   *  *  ** *    *         * * * * * ***   *    *    is too high!  **  * ** *
 * **  *   ** **   a != 10 );
** **** *  **  ** 
   * * *****  * *  ***  9 8 7 6 5 4 3 2   **      *  
 * ** *     ***    0;
}

Comments

Case 0: Wrong output