[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include    ** ** **  * 
#include **  **        * 

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* *  ** * *   *** *  *   *   * * ** your      *  *    *    * **** * *  * ** **  **   *** **** *  DO NOT change
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*  *  **** ***  * *******   Your  * ** start from here
**     * * * * **  * *  *   *   i;
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* *** * * ** *   
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     *    *  ***** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include ***       ** 
#include *  *  *****  *  **

int main() {
*  **    *   *  int a;

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 *  *  *    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ** ***  * * ***
#include  * *** ******  

/* run this program using the console pauser or add your own getch,    **  ******  *  ** or input loop */

int main(int argc, char *argv[]) {
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*  *** **  ***  *  **    *
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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*  ** *** *****   **
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int main(int argc, char *argv[])
{
***** *     **       *   ***   ** i, a;
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*   *  * **** **   ***   * (i=1)
*** ** *  ****     * * ****  *****     **   **  ** ***  *** * **** ****  * * * ***
   * **   ** * ** *  *  *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
**  *  ** * *  ** *   *     your input : ");
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
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***  ***  ***   ****  *
int main(int argc, char *argv[])
{
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  *   * * *** ** *   ** *     *     *  * ** *  *  * ** *** * *  *  ****   
 **     ****** *    * *  ****  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
******* ***    *  
 **  * * * ** ****  ***  
int main(int argc, char *argv[])
{
 ***** ** *  * * * ***   ** **** i, a;
* ******    *  * **        ***  *     *  your input:");
*  *  *****  **     * ***  * * **  ** *    *    ** &i);
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   **  * * *  ***  *  *  ******* ** *   *  *  *   ** *** *     *  ** * *  **  i);
 *      **** ******* *** (i=1)
  *    **     *** ** * ** ** ** *   ***   ** * * **  **    * **       **      
  * **  * *  * ******    ******* 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* * * *  *   ** ** **
   *   * *  *      **     *

int   * argc, char ****   {

 *** *  * **** *** int a=10;

*        * * * *  do{
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* **   **       *   *  ** **  *       ****  **     *  ******  *  ***
* * ***   * ****  * **    **    * 
**     * *  * * *  a != 10 );
**  ***      * ** 
* **** *   * *  ** * *   *  * 9 8 7 6 5 4 3 2   ****    
** *    **   *** **** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*     ****   * ***  *
**     *******  **  ***

int   *    argc, char *     {

 *** * ** ****   int    

   **    *    do{
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* ** * * ***           *** ****    if( a  * *    10)
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** * ***   * ** *    *     * * * if( a   ** 10)
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 **    *  * ****  ***** a != 10 );
*** * *  ** *  
   **   *          *  * * ** ** 9 8 7 6 5 4 3 2    *** * *
*  **  * *****   * 0;
}

Comments

Case 0: Wrong output