[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include    ** * **  ** *
#include * *  *     **   *

int main(int argc, char *argv[]) {
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*  * ******  return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *  *   *  **
#include    * ****  **  **

int main() {
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* *        *  * }

** *  * *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * ****  ** 
#include  * ** ***  *  * 

/* run this program using the console pauser or add your own getch, ** *    * * **  *  *** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
    ** ***** ** * *    * 
*   * * ** ** *  *   **
int main(int argc, char *argv[])
{
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* *      ** **     *    ***      *   ****      *  *****  * **     * *****    * * **
**   * *     *   *  * *    ****   0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
* ******* **  ***  * 
 * * ** *  ***   **    
int main(int argc, char *argv[])
{
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 ***** ** ** ** ***  ****   ****** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  ***     ******** * *** 
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int main(int argc, char *argv[])
{
*** *  **** * ****   *   *    * i, a;
*    * * * * **** *****  * * **  *   your input:");
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*   ****** **  * ** **    * ** * a<i; i--)
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    * * **  *  * * *      *   ********    *    ** * * ****  * *    * * 
******* *** * ***  *    **  *   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
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* **  *  ****       *****

int  *    argc, char *** ** {

 *** * * *  ** int a=10;

*   *  *  **** do{
*       * *   **  ** ***   *    * *  *          your * **    ** 
*   *  * ***  *   * * ***** * ** **    *** ** *   * * ** * 
**  **   * * * ** * *   *   
  **     ***** **  a != 10 );
*   **  **    
   * *  *  *       ****  9 8 7 6 5 4 3 2 *** *   
****   *  *** * * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

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*  ** *  * *** * ** *

int *  ***   argc, char    ** {

*** *** **   ** int ** 

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* *   * * **   *** ***   * * ** *  *  * **** * * ****  * *  *** 
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*   *  * *  * *     * *     *  * if( a      **  10)
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    ****  ** *  * *   a != 10 );
 *  *    ** *  
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* ** *   ***   * *  * 0;
}

Comments

Case 0: Wrong output