[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
#include ***  * * * *    
#include    *  * ** **    

int main(int argc, char *argv[]) {
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***  * *  *    ** ** *** * ****  your  * *********  * * ** *  **** *** **  *** ****     *  * DO NOT change
  * *  **** * *   *   ** *** ***  * 

** ****        **  *  *   ***  * * Your  * ** * start from here
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*    ** **    **  **    * = a; i >= 0; i--){
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* * * * *  ***    *** *    *** *  *   *   **      *******   **
*   * *     * ** * * * ** **   else
*****  * ** ** *  * * * ** ***    **     * *      *  
****  * ** *      *   *  * * }
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*   *  * *    



***    *** return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
#include ** * * ** **** *
#include *** *******  ** * 

int main() {
* *  **  * ** *  int a;

* ****  **  * *   *  *  * your  ****  ** * 
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* **   *    *** * 
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* *  * *     **   *       ****  * * }
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**        return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
#include   * *** * ***   **
#include * ****  ****   **  *

/* run this program using the console pauser or add your own getch, *  * **  **    **  * * or input loop */

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*  **   *  *  ** **   ***  * *     =  ****
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******      ** * ** *   = getchar();
*  **    ** ** *  * * *  =    * * 
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*     ***  * ******** * *   ** = getchar();


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* *** *  *  *** *  **   *  ******* *   * *   ****   **      * ****  * *** ***** q +  ****  - 'a'));
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* *** * ** * *   *  * **** ** *
*    * *  *** *     * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
 *  *** * *  * *   * * * *
** **  *** **    
int main(int argc, char *argv[])
{
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*  *    ** *   *****   *      ***  ***** ** * ** &i);
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* * *** *   *****  ***   *   ** ** *    ** * **  **   **    * * ** *  *   **
   ** ** * * * * * ** * **** * 0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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*  ******* ** ****   * * * *  ** *  *  ** *  *** * **  *  *  ***  *  *  *  *  *** ***** * *   *  **  * *  *
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*     * ***  *  * * ** ******   *   **   * *   ****    ***     * *   *** ***  *** * *      ***     ***   **  
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** ***** * *** **** * * **  ** * * **    * ** ****  * ****  **  
   *   **** * *  ** 

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
 * *   *    * *   *** 
 * * ***  * **   
int main(int argc, char *argv[])
{
  * *   *   *    **  **   **       i, a;
* **   ** *   * *    *  *** ** **** **   *  your input:");
   ****** ******  ** ** ** ** * **** * *  ** &i);
* * ***   ***  **           * ** * a<i; i--)
 *** * **   ** * * *       *   * *** *   ***      * * * ***** * ** ***  ******* *  i);
*     *  * ***     **  ** *****  (i=1)
 *****  * **  * ** * * **   * ****   *  ** *  *** ** ** * ** * *   **   * * ***** * **
******* **   * *   * **  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
 *  ** * * **  *  *
 **   *  *     *    ** **
int main(int argc, char *argv[])
{
 **** *  *  ** *    ** ***** *   i, a;
*****    **   * **  *** * * *  ***  your input:");
  * **** ***      **  ****** *** ** * ****     &i);
**  *    * **   ** *** *   ***  a<i; i--)
* * **  *  *****  ** *  * * ** **   * ** ** ***     *  **  *** ** ** **  * *  * i);
 *** *  **  **    **  *   * * (i=1)
    ****     ***  ********* **      ** * **  *   * *   **  *  *    *  * **** ***   *  *
 * *    *      * **   *  *     ***  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
 * *   ** *    *   **
*    **  * *  ** *  ** 

int  ****   argc, char ** *  {

  *  * *   *  * ** int a=10;

*   * *  *** do{
 *     *       *    **    * *  *   *** *  **    your  *  **** *
 * *  ***   **   **   **        *** * * **** ****   **  
      * *** ** ***      
** **   * * *     * a != 10 );
**   * ** **   *   
** ** *  **** ** **   *   **   9 8 7 6 5 4 3 2 *** ** ***
**   * *     * * **

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
* *   *  ** * *** *** * 
*** *  ** ********* 

int * *** argc, char **  * {

**   *  * * ** int   *

**** *  * * **  do{
* **   *** ** *  *** ***   *   *   **   ***** **  **** *  your *  *  * *****
****    **  ** *  ****  *   *** * *   *****  **  
* * * *    *     ** *  *    * * if( a  * * * 10)
 ***  ***  **   *** ***   *  * * **    *   ***   ***  ** * code is too low!   *****
** * * **   *    *** *  **   * 
* **    *** *    *    if( a *  * 10)
* * * *  ****** * *    *** **  *  *  ***   *     ** **** ****     is too high!   **** 
* * *   **   **  * a != 10 );
 *   *** * *  *** 
  **   **   * *   *** * *** 9 8 7 6 5 4 3 2  *   ** *
****  *   ** * *  0;
}

Comments

Case 0: Wrong output