[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
#include * *  ** *     
#include *  *  *   * 

int main(int argc, char *argv[]) {
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 * ** **   *   ***     **    *  **  ***  * **  

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** * * *   *   *  
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 *  ** *   return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
#include *  ** * ** **
#include ** * * ** *      *

int main() {
       * **   *** int a;

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*** *    return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
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int main(int argc, char *argv[])
{
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* ***  ***   *    **   * ** *  (i=1)
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 * ** ** ** ***  ** *****  * 0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
    **  *** * *****
   ** * **        **
int main(int argc, char *argv[])
{
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 * *** *      *   *  *    ** (i=1)
  **    * ** *** **     * **** **** * *  **** * * *    ** *** *  ****  *    **
* **   *    *   *      ****  * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
*  * * ***    * **
******* *  *  *  *  *  *
int main(int argc, char *argv[])
{
 ***  * *  ****    ***  ** *** *     i, a;
 * *    ** *   * ***  **   * *   * *  **  your input:");
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 ** ** **  **   * ***  (i=1)
  **  *  * *   *  *** *   **  ****  **   * **  *** *****    *  * ** ****
 *****   ****    * * * * * ** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
**     * ***  * ****
  *  ******** 

int * *** argc, char ** **** {

** ** *   *    ** int a=10;

* * *  *  *  do{
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***  **** **    ** * * *  *    *  *  *   ******* * ** *   * *  * 
  ** *   * ** ** * ***  *  ****   
  * *    * *   * a != 10 );
* *   **  **** 
** * **      *  * **** *  *  *   9 8 7 6 5 4 3 2     *    *
*  *    * *   * *    *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
**   *  *  **      ** * **
  ** * ** ** *  * * **

int  ** * argc, char * ** *  {

*  * ** *  *** * int *  

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    *   **  *****   ***   *** 
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*   *** * ** *  **** a != 10 );
*  ***  *  *  
***   * * * ** *   * *   ** 9 8 7 6 5 4 3 2 * *  ** *  *  
   **  *     *  * * ** ** 0;
}

Comments

Case 0: Wrong output