[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include **  *  * * * 
#include ***  * *   ****

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  *** *  * **    
#include *** ** *  * *

int main() {
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** ***      return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * * * * ***** *** 
#include     *  **    

/* run this program using the console pauser or add your own getch, *  ****   **  * **   *  or input loop */

int main(int argc, char *argv[]) {
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* ***** ** * *  **    ** = ****   *
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
*     *  ** *  *    **
**     *  ** *** ***** 
int main(int argc, char *argv[])
{
***  *  * *  **     ** *** i, a;
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 **** ** ** * ** * *  * *  *    * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 *** *      * * *    
***       * *** 
int main(int argc, char *argv[])
{
***     *** **  *  *  **  *  *   i, a;
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**      * *   *   *** *** *  *   *  &i);
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 *   ***       * **  * *  (i=1)
*    ****  ***   * * ** * ** * ****   *    *     *  ** *    ***   * * 
**  *  * *** ****  **  **  * * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
***    **  * 
 *** ** *   ** * * * 
int main(int argc, char *argv[])
{
 ****   *   *** * * **   *   i, a;
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   * ** *     *** **  ** ** * (i=1)
 *****    ** ***    *   **   ** * *  * *  * *** * **  *   * * ****  **   *  
* ****  ** * * *   *  *  ***  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
 *** * ***      
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int  *  * argc, char *** {

  *  *  * *** int a=10;

 ***    ** ** do{
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**       * *   **  * *****   * *  *  *  * ****  **  *  
  * * * **    *   * *    * *  
  ****   ******      a != 10 );
*  **     * * 
*   * *     ***  *   * **   ** 9 8 7 6 5 4 3 2 *   * *    
  *   *   *** ** ***

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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int *    argc, char  *  *  {

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   * *** *****   do{
* *  **   **     **  * **    *   ** *** *  ***** your    ** *  * 
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***   *** * ** ***  *   if( a    *** * 10)
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** *   ** * ***   a != 10 );
* ***   ***** 
   *  *  ****    * *     * * 9 8 7 6 5 4 3 2   * ** ***
 * * *   *       *  * 0;
}

Comments

Case 0: Wrong output