[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  * ***   * *
#include **      **   **

int main(int argc, char *argv[]) {
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****** * *  *  *  *********  ****  * 

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****  *  *     **  *  *  *  ** i;
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*****     ** *   *  * *   *   * ***  *  *  *   **** ***
    * ** *** * **  *  ***  * else
* *   ** *        *    *** **    *  **** *   * * * **
*  *   *  * **** ***   **** }
** *  *  ** ** * 
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  * *    * *** * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  **  * ** **   
#include  *** ** *** * 

int main() {
** ** * **  *  * int a;

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**         return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ** ** *  *   *
#include **** **    

/* run this program using the console pauser or add your own getch,      * **   *****   *** or input loop */

int main(int argc, char *argv[]) {
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*  *  ***    **** *  ***   * * = * *** 
**  *     ** * *    *    = getchar();
** **** * *   *  * ***    **** = getchar();
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
* *   ** *   *  *  
***** * * ***  ** * *   
int main(int argc, char *argv[])
{
 **  ***** ** * *    *****   ** * i, a;
* **** ******** ****** * *****        * * your input:");
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*   * ** *** * ***  ******  ** * *  *** ******  *    *** *  *       ***     i);
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**   *    * ** * ****** *  * *  * *  **  * *  **  *   ***  ******* **** ** ** * *  
** ** * ** * * *** **          ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
** **  *  *** *   *** *     ** * your input : ");
*    ***  **   ** ****  * ***      * *   * **  * **  **   *** *** ** * *** *  * * ****** ***  * **
*** ****** ** *    ***  *****   *********  ** *** * * *  **** ****  **    **      *
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*** ** *  *  * **** *   *  * ***  *   **  *    *  *  *****    * * ***  ***
**    **  **    **  * * ***   * * ***     *** *  **  ****  **
     *  *  * *  **   

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * ** *** *  ** *   * *
 *  * *  * *  *   **
int main(int argc, char *argv[])
{
  ** **  *  * * ***  * * * *** i, a;
**  **  **  *** * *** * ***  *   * your input:");
 * **    *  **   ** * * *  * ** * **        * ** &i);
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        **  ** *   **  ** ******   *   * **   ***   *     * * **** **  * * * * i);
* *     *  ** * *   *  *    (i=1)
 ** ***   * *   *   * ***    *  ** *** ****   *  **    * * **     *** * **    *
   ****  *    **  *   *   * **  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*   ** **     ** *  ** 
     *  ***  *** ***** ** 
int main(int argc, char *argv[])
{
*  **   **   *  *  *    *     * *  i, a;
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* * *  **   ******  ** ** **  *** *********** ****   &i);
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   ** ** *** *    *  **   *   *    ******   *  ****** * ***** *********  * * ** i);
*  *    * **   *******  ** *** * (i=1)
** ***  * *  ** *** *** ***  ***  * ****  * * * * *** * **    *     * *  ** ***
 ***   ** * * **  ** * * ** **** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
  *   *** * * 
 *   *    ***** *  ***

int *   *** argc, char *    {

**     *  ** * * int a=10;

*** * * **   do{
  ** ****  ***  * *** * *****     **     *       your  * * ** ***
*     ** * * **   **  ***** *** * * ***   * * * **   *     *  ** 
     *   * * *** **   *  *      
* **   ***  * ** * a != 10 );
* ****   * *   ** 
*** *  ****  ******* * * 9 8 7 6 5 4 3 2 ***** **
* * **  *    *   *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
  **  **** *    
**   **   * *    ** **  **

int  **** argc, char *   * {

 *    ***   * *     int    *

 ** * * * * *** do{
*   *  ***    ** * ** *** * * *  * ***** * your ****** ** *  
** ****   ****     * ** * ****    * *   * *** **    *    * ***
  ****   * ** *    * *     if( a **    10)
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* ****   * *  *   *   *  *  * * 
      **     **  *    * *   **  if( a ** *  10)
*    ** * ***  ** **   *   *** * *  *** *  *  *  ****   *      ***  **** *    is too high!  *  ** * *
  * ** *  *   *** **   a != 10 );
 ** * * *  *   ** 
*   *   ** **    ****    * * 9 8 7 6 5 4 3 2 ** * * *** 
 **   *   ** ** * 0;
}

Comments

Case 0: Wrong output