[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include **    ** * * * 
#include **   ** ** ** * *

int main(int argc, char *argv[]) {
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**     **   **     *    *    ***   your   **  ** * *  * *  * *  *  *   *   *   *            DO NOT change
* *   ** * ** * *  ** *  *  ** *   **   *  *

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 ** ***  * ** ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  *** * **   * **
#include    ** **   *** ****

int main() {
* * *  *    *  int a;

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 ** ***    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *   ** *  **
#include   ****   *** ***

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* * ** **  *  * **  ** **  *
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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*     ***  ** *** *****
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int main(int argc, char *argv[])
{
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** **    *  *   *** ** *   * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
* *  * ** *   ********** *     your input : ");
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*** *  * *  *  *****

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
  *** *** **  * **
    *  ** **     ****** 
int main(int argc, char *argv[])
{
 *     **      *  ****** * * i, a;
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*  ** **  *  * *  * *  ***  ***    * ** ** * &i);
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*   * ****   *     * ** *  *  *** (i=1)
   * *****  **  *  * ******* *   * *  ** ***** **  **** * **     *** *  *** *   *
  ****  *    ***  ** ******** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 * ****  **  *  * *
*    ******    *  * ****
int main(int argc, char *argv[])
{
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*** *     * *  ***** *  ** *  (i=1)
* *  ** *  *** * *  *  ********* ** *    * **** ** * * **   * *  ***    * ***  * 
   * *******  * * *   * ** **  *    0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
    ** ***   *        
**** *  **   *  ** * **

int ** ***  argc, char    * * {

**   **   * *     int a=10;

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****    *  **  ***   * ***  * *  
*     *      **  a != 10 );
 * * * *  **** *  
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 ** * ** *** ***

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
   * **  *   * *** ** **** 
** **  ** * **     *** **   

int      argc, char **** *   {

* *  **     *  * int * * 

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**    *** **  *** * **   *****   **** * *  * **   * 
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**** *      *   **** **    *   if( a ***  10)
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* ****     * * *  *   *   a != 10 );
   **   *   **  
** **   * * ****   * ***  9 8 7 6 5 4 3 2 **  *  *
 *** * **       * 0;
}

Comments

Case 0: Wrong output