[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

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#include *** *  * * *    

int main(int argc, char *argv[]) {
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**     ** *  * ** *   ***   * }
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****  *  ****   return 0;
}

Comments

Case 0: Correct output

Answer 2

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#include      * * *  *  
#include * *******   **  

int main() {
****    ** **  int a;

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*   ***    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include   ** *  * *    *
#include * ****    * *   *

/* run this program using the console pauser or add your own getch, *  **  **** * ***      or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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* *    ***   * ** **   **
*  * ** * ** ** *  * **
int main(int argc, char *argv[])
{
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*** * ** **** *  ****  ****  *** *  *   ***  *  ** **    ** * **    *    ** *  *  
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 ** *    **** ***  **
** * *     * *  * *  
int main(int argc, char *argv[])
{
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*** * ***  ** *   *** ***** * *  ** * * your input:");
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*    ***** *  **  ******      ***   ****  *  * * **  ** *    *     *   **  ** *** **  *
* *** ******** *  *    ****   ****    0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  *  ***   * ****    *
 ** *** **   *  **   *
int main(int argc, char *argv[])
{
*****  * *   *  * * *   * **   i, a;
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*  ****    *** * *  ***      *** ** **    *** ** * &i);
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 ****   * ******  * ** *   *   **   ***********   ********    * *** *   **** 
**  **  *** ** ******  **    * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
*      ****  ** * *** *  
    **  *  *    **    * 

int **    argc, char  ****  {

      ***   * * int a=10;

*     *   *    do{
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****   *      *  *  a != 10 );
 *  *  * * ** * *  
  ** ***  *  * * * ** ** ** ** 9 8 7 6 5 4 3 2 * * *** **
***** **       *   **  

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
* **  *  * **** ** * * 
**    ******* *    *

int     *  argc, char *****  {

** * * *   *   * int   **

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**     *   **  **** *  **    if( a      * 10)
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*   *     *       * *     * * * * if( a **     10)
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   *  **  ** **     a != 10 );
**      **  **  
*   *    ** * *  * * * *  9 8 7 6 5 4 3 2  **   **  * **
*       ** **  *  *** 0;
}

Comments

Case 0: Wrong output