[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  *   * *** *** * 
#include  ** *** * * 

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*** *** * *    *  
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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include   ****       * * 
#include  *  **    * ***

int main() {
**** * * * *  int a;

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**    *      ***  }

*    *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *** * *     *  **
#include      *  ** * 

/* run this program using the console pauser or add your own getch, **** **    **   *  **   or input loop */

int main(int argc, char *argv[]) {
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*       * *     ***** * *    ** = getchar();


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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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* ***  ** *  * * *
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int main(int argc, char *argv[])
{
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** * *     **  *  *****  *  * (i=1)
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 ** * * **   * ****   **  * * *  ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
    ****  *  *  *    *   * *     ***    
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
** *  ****  *     *  *  
*** ***  *** *    * **  *
int main(int argc, char *argv[])
{
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* * **  ** * ** ***  * *  *     (i=1)
*    ***  ** ****  *  * * **      * * *** *** **  *  **  *** **       *** **  
**    **      * *  ***   *** ***  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 * ** **     **  ***
*    *     **  *   *
int main(int argc, char *argv[])
{
*  * *** *** * *    **  *  * i, a;
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***     ****     *  **  *   * *    a<i; i--)
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**** ***  * **  *  * ****    ** ** * *  **  * ****** *      **  **  ** * 
 * ** *   ****  *** * *  ***  *** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
****      * ******   ***
**   * * * *  * *   ** 

int * ** argc, char    {

*   * *  ***       int a=10;

***   **    *    * do{
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* ** * * * *  * *** ***     * * * **   * **  *  *   * ** *
   ** **   ** *       *    * * * * 
*  **   * **  *  **** a != 10 );
   ** **   
 **  * ** ** * * * * * * **    9 8 7 6 5 4 3 2  * * *****
 **    *  *  ** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*    **  ******  * **  
**** * * * **  * ** * **   

int   * * * argc, char  *  {

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*  *      **** do{
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** ****** ** **  *    a != 10 );
 * ***   * *  * 
********    **  * *   ***     ** * 9 8 7 6 5 4 3 2 *****  ** *
 **  * * *   ****  **  * 0;
}

Comments

Case 0: Wrong output