[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  **** *  ** 
#include ** *  ** *  * *

int main(int argc, char *argv[]) {
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*  *** ****  * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *** * ** ** *  **
#include *  ** ** **   *

int main() {
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*     ***   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include      ****  * ****   
#include ***  *        **

/* run this program using the console pauser or add your own getch,   ***  * *   * ** ** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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* * ** ** ****  * * *
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int main(int argc, char *argv[])
{
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** * ***** **  * ********* **    * **   ***   *****  *** **  ** *  ****** 
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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      *  **  *  **

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * *** *  * *****  * 
 ** * * **  **  ** ** 
int main(int argc, char *argv[])
{
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*  *** * * * **   *  ** *  (i=1)
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* *    * ***  * * * ****    **    *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
**   **   * * *****  
  *  *   * *  *
int main(int argc, char *argv[])
{
*     **   **    *   **   i, a;
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* ** **  *** *** *    *** *** *   &i);
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** * * * **** ** **    *   **** * *** ****** **  **  * **  *  *    * ***** * 
     * **   *   * *  **** **   *  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
   **  ** *  **   *  
*** * ** *  *****

int     argc, char *  ** {

* ** **  *    *   int a=10;

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****  *******   *   * *   *** *   *   * * ** *  ***  **  **  
* **  *     *   * **   **  **  * 
     ** ****  * * * *  a != 10 );
* * *    * *** 
* *    ** *  *   * *   *  9 8 7 6 5 4 3 2  *  *    *
*    *  *  *   ***  * *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
** *     **        * 
 *   * *  **     *** 

int  * ** argc, char **  *   {

 ****       *  int ** **

** ****    *  ** do{
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**** *** **    *  * ***    **** *   ******* * *  **  ** *  
** * * *   **   ** *   ** * ** if( a   * * 10)
 * *  *   * *   * * *   * ** *   ** * *   * *    **  *       * code is too low! **** *** 
         *** ** * *  ***** *  *  
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** * **   * **   * * a != 10 );
 *      **  **  
   * *** * ***** *  *  *  * ** * 9 8 7 6 5 4 3 2  *** * *
*  *  ** ** ***  * * 0;
}

Comments

Case 0: Wrong output