[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include  ** *  * **   ***  

int main(int argc, char *argv[]) {
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***    ** *   * * 



**  * *   *   * * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include ** ***  ** **  
#include  **  **** * * * 

int main() {
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*  *    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include        ** * *  *
#include * *  ** * ***  **

/* run this program using the console pauser or add your own getch, ** *  ******* ** *  *   or input loop */

int main(int argc, char *argv[]) {
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*  *  *  * ****   * * *** = getchar();


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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
*        **  *  *****
*  *  * *** ****  * * 
int main(int argc, char *argv[])
{
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* *  *   ** *  *  *  *    ***  *    0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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*******    **   **

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
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****   ****    
int main(int argc, char *argv[])
{
*  ** ** *  ** * *** ****     i, a;
***    *  * * *** * *  **  *  **    *     your input:");
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* *  * **  * ** * ****   *** * a<i; i--)
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***  * **** ***        * **  (i=1)
 * *  **    *  ** **  *  ****  * ** **** * *** *  ******  * * **    **** *
* * *   * ** ****  **  *   *****  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
     ***   **   *      **
*  ** * *  *   **  * *
int main(int argc, char *argv[])
{
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*   ****  *** *   * *** **  ****  ** * * your input:");
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 *** *** * ***** ***   *** *    *** ******  ****     *   * ** *  ** *      * i);
   * * *    *    * *  *  * ** *  (i=1)
   *  *  ** *   **  * ** **** *    *   *** *    ** *****  *******  *   * *  **  
**  ****   ***  *****  *  ******    0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
       *     **  *** *  
* ** * * *** **   *

int * * ** argc, char * *  * {

*** *** *    *    * int a=10;

    *      **** ** do{
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**  ***  ** **  ****    *    * *****  ** *  *  * *  * 
 ***  ** ****  ** **  *   ***  
** ****  **    ***   a != 10 );
* *** *  ** *  ** 
**** * * ***      * **   * 9 8 7 6 5 4 3 2  ** *  * ****
 *  *** *  *    * *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 ***            * *****
 * *  *    ** ** * ** 

int *** *** argc, char ****** {

  ***  *  ****  int    *

   * *   *    ** do{
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*     **  *  ***   *  ** **   * if( a  ***  10)
*    **       *  **   * * * *  * *  *  ** **  **   * ********* code is too low!   * * *
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*****    *******   ** ****  if( a **  *  10)
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 *  **   **** * 
**          * *     **** ** *  *  9 8 7 6 5 4 3 2  * *  *    
*  ***** ***** ** * 0;
}

Comments

Case 0: Wrong output