[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include * * ***   * * *  

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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include   ***** *****
#include ** **   **     

int main() {
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**** **   **** }

****  **   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ** ** * *** * * 
#include   **         ** 

/* run this program using the console pauser or add your own getch,   * *   *      ** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
       * * *** **** 
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int main(int argc, char *argv[])
{
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*******    **   * * * * * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
*   *  **** ***  * 
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int main(int argc, char *argv[])
{
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****   ***   *  * *      **   (i=1)
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***** **   ****** ** * **   *    0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
   * ***         ***   
*  ** ** ** *  *** 
int main(int argc, char *argv[])
{
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  **  *** ** *  *  **     ***  *  * *** *  ******* * *  * *** *** * * * **** * 
****   ** **  *    *** * **  *  **  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
  *** *  * * * *    ** *
 ** ** **  *  * *   * **   

int **   argc, char  *  ** {

 *   ***   * * int a=10;

*** **    *** do{
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 *  *  *  *   * *   *  *  *  
 ******  *   ***   *  a != 10 );
* *    *      
 ****   **   **   *  *     *  9 8 7 6 5 4 3 2 * *  *** **
 ** *     * **  **

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
**         *     *  * 
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int **** argc, char *  ** * {

******** **  *  int   

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**  * ** * *  **  ** * * *    * *   ** *  ****   *  ** *   * * code is too low!  * ** 
***      ** ***    **     *** 
** *     *   *  ** ** *   *** * if( a   * *   10)
**** **  * * **** * **** ** **  *  *   **  * * ** **  *** *      *  * is too high!     * ** *
*  *  ** *      * a != 10 );
  *    ***  
**  ** *   **    *      *****      9 8 7 6 5 4 3 2 ******* ** * *
*** **  *  *   0;
}

Comments

Case 0: Wrong output