[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

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#include ** * *** * ***  *

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Correct output

Answer 2

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#include **    *** *** *
#include **    **   * *

int main() {
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  *    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
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/* run this program using the console pauser or add your own getch, *       ** **** ***  * *   or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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int main(int argc, char *argv[])
{
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  ** ** *****   **** *** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**    ***    **    **
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int main(int argc, char *argv[])
{
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***     *  * **    ** *   *    **  *  *   **   your input:");
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***** * * *   ****  *   **  * ****** ***   ****   ******  **** *****  ****  *
 ** *  *  **  *  *    **** *     0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
   *  ** ** ** ***   
*   * * *  ** *
int main(int argc, char *argv[])
{
  ** *   * *  **   * *** **    i, a;
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**              ***  ***   ** ** *  ** *    **** *** *****  ** **  * *  **   i);
** *  * * *  *      ** ** *    (i=1)
****  *   ** ***   * *   ** *** * * * *  ** *    *     *  *    *   ** ** *   
 *  *  ***** *** ********  *   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
  * ******* *   * * *
  * **  ** **      *  *

int *  * argc, char **   ** {

    ** **  *   int a=10;

*** *** *  ***  ** do{
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*  * *  * *  **     * *    * 
*   * **    * ** **   a != 10 );
     *  *   
 *  *     ** *    *   * *   *  9 8 7 6 5 4 3 2 *  * *  **
 * *   * *** ***      

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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****   * ***   ** *    *

int * **   * argc, char  * ** {

** * **  *      int * *

* *** *   ** * * do{
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       * *    * ****   **** * if( a ** * 10)
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*** *  * **** *   *  * *  * 
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* * **   ****  *   *   *****  *** * *  **** *    ****    *   is too high! * *  **
*            **     * a != 10 );
* *  * ** *  
   ****   **  **  ** **** ***  **** 9 8 7 6 5 4 3 2  *** * **
* * *** *    *** *  *** 0;
}

Comments

Case 0: Wrong output