[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include *  **  * ** ** * 
#include **** **   * * ****

int main(int argc, char *argv[]) {
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* *    *     * ***    **   * your *** ********     *** ** * * *   ** ** * ** ***  ** *  DO NOT change
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*  ** **   * *** ** *  ***  i;
*    *    **  *    *     **   ** = a; i >= 0; i--){
** ** **       *** ** * *    *  *  *  if(i == 0){
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* * * *  * ***  * * **    ** * **  *        **
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***       * ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  ****** **  *
#include *   * ** * * * * 

int main() {
** *****   * ** int a;

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***    *** * }

***   **   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *****    * *     * 
#include ******   *   * *    

/* run this program using the console pauser or add your own getch,      *****     *    *  or input loop */

int main(int argc, char *argv[]) {
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* **  *      *  ***** *   *   = **  *
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*   *  ** * * **   * * *  ** q >= 'a' * ** * *****   q <= 'z' )
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*   *  *****  **   * * *    **    ** *  **   *  **** w >= 'a'  *   * ****  * w <= 'z' )
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
   * ** * *     ** *   
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int main(int argc, char *argv[])
{
   *   **    * *  *  *   **** i, a;
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*** *    **   * * **** *** * * *** a<i; i--)
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****   **    *    ********   * *     *  ** ***  *   ***** *  *** * *  ***
** **     **** * *   ****** **  *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
        *** **  *   *   * ***   **** * * 
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***     **  * ** *  ** ****   ** ***     ** *******  * ** *** * * **   **     * *
*** *********   **  *  * *   *  * *   * **  *   * **  * **    * *  * *    *
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
*  ** *    * * *  *        * your input : ");
*  *  ** **** ** **   ** *  * * ** *****   **  * *  ******* **  **  **     * ** *    *  ***** *       *
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   * **          **** ****   * ***** *  ** *** *   ** ** *** **  **
** **  ** ***** *     

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * **   ***  * ** 
** *   *** **** *     
int main(int argc, char *argv[])
{
*****  *** *** ****  **   i, a;
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*******  ***** *******   * *  *  ** *** * **  *  *    &i);
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***** ***  ***   * *         ** ***    *  ***  ** *** *   *  * ** *   * ** **   i);
   ***    * **     * * ***   (i=1)
***    *********   * **    *  *   * * *  ***** *** *  * * **   *  **    
 *   *  *  ** *    *** ** * *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  **  *** ** *** * *    
  *** *    *   *   ***   ** 
int main(int argc, char *argv[])
{
* *    *   *  *** * **** i, a;
  * **        ***    ***  ********* ** your input:");
****  *  ** ***    * ** * *** *******  **** * &i);
****   *  **    **** * *  * *  a<i; i--)
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    *****    * * ** **   (i=1)
* *******   ***** *  *** * **** *  ******  *** *  *** ** ** *   *  **  *    **
**    *  * **     *  *  ******* * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
** ** ******  * *  ** 
**  ** * *   **** **      

int  * ** argc, char   * ** {

** * ** * *   int a=10;

*  *   ** ** ** do{
 ** *     *    * *** *  ****         ** your    *   * 
**** **    ***   *  *   * ** *   ** ** *   ** ** ** *   **
 * *    *    *  **** * * *    
   **  * * * *    * a != 10 );
 ** *    *  ** 
*     * * ** * ***  **   ** 9 8 7 6 5 4 3 2 **  *        * *
 **** * *   *   *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 ***    ** *  ** *   *
*  **  * *  *  ******** *

int *  *** argc, char  ***** {

   *  *   **     int *  *

*  *  * *   ***  do{
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* *  *       * **    ***  *        ****  **      ********* 
****    *  *  **   *  *  *  * if( a  * * *  10)
     **   **** ***      ***   ***  *** * * * * *  ***  * ***   code is too low!  **** **** 
 *  * * * **** *   ****    *** 
** *** *  ***  *  *        ** if( a ****   10)
*  *  * *  **   * ** *   ** *     * *      *  * ****** ****           is too high! * ***** 
 *  ***  * ****    ** a != 10 );
**    ** **  *  
 * ** ** ***** ****  * * * 9 8 7 6 5 4 3 2  **  *   * 
 * *  **   * *   ** 0;
}

Comments

Case 0: Wrong output