[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include    * * * * *

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*** *  *    return 0;
}

Comments

Case 0: Correct output

Answer 2

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#include * ** *   * ** **
#include  *  ** ** ** *****

int main() {
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**   *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *  **   ** ** * **
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/* run this program using the console pauser or add your own getch,  * * **     *  **  ***  or input loop */

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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** **** *******    *  *  
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int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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* * * *   *  * *    *

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
    **   **    **** *
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int main(int argc, char *argv[])
{
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* **  *   *     ** *  **   ***  ** * *  * your input:");
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* *  **    ***** * *  *   ** *  (i=1)
* **  *  *      ** *  *  ***   *   * **   *  * ** *** * ** ** * ***    ***
  * ** *  **  ****   * *  ****** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*** **  *** ** *** *
* ******* * ** ** ****
int main(int argc, char *argv[])
{
 *  ***   *******  *   *   * *** i, a;
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**  **   * *   ** ** *  * ** * * **     * * ** *      * * * * *** **   **  ***  **   * *
*  *      * ** ****  ****  **  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
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*     ****  **   *

int    argc, char *  * *  {

* ******      ** int a=10;

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 * * * *     * **        a != 10 );
***  **   *   
*    * * * *  *** **  **** * * 9 8 7 6 5 4 3 2 **  *  **  
*        ** *   

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
   *** *     * *******
*  *    *** * *   * **

int   * argc, char *  * {

*   *   ** * * int  *

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** * *        
***  *   **** *    **   * 9 8 7 6 5 4 3 2 ** * *** **
   **  ** *    * * *  0;
}

Comments

Case 0: Wrong output