[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include   ****  **   *
#include ** *   *** ** **

int main(int argc, char *argv[]) {
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 *  *    * *   **  * *******  *   *** ** * * *  

     *  * *    *    *** ***  ** Your **** *  start from here
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*    ** *    **** *  * *** ** = a; i >= 0; i--){
    *     * *** ** **  *    * * * ******* * if(i == 0){
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**      * ***    ***   **     else
**  *     *   ****   * *    * ***** ****** **  * **  **
* *    * ** * *  *   * ***  }
**   * *          
**  * * ***  *   



***   *   *** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *    ** ** * *  **
#include * **** * *  **    * 

int main() {
 *  ** * *   * int a;

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***     **  ***  ***  
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   *** ** **     }

    *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **  ** *** ****
#include     **  *  * *

/* run this program using the console pauser or add your own getch,   *  ** ***** *  * * or input loop */

int main(int argc, char *argv[]) {
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***   *      * ***    ** * = **  * 
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***   **    *  * **  *  **  **  =  *      
*  * ****  ******  *  *   * = getchar();


* * ** **** ***  ***  ** 
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
*    * ** *******     
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int main(int argc, char *argv[])
{
***  *    *  **  *  **    i, a;
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* * **    *  *** ***  **   *     *    * *** **  **  &i);
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***  *   *  **** ***** *  **  *  (i=1)
   ** ** **   * **  *  * **   *   * **  **** **     ***   *   *  *  **    *
  ***** *******  **  * *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
 * *    * **  ******* ** *** your input : ");
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* *** *** ******* **  **        *  **  ** ***      ***  **    **   *   ** ****  **  *** * **  ** ******  **
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**   *******      *      **   *********  ***   **   ** ** * *** *
 *       ** ***  ***

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
   ** * **  ** ***  * 
      *  *** * ** *
int main(int argc, char *argv[])
{
****   * *** * **** *** ***  * * i, a;
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* **  ** * *  ***  * * *   **    * **  **** &i);
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 * *  **      ** ***** * *  (i=1)
* ***** * *   **  *  ***      *  * * ***  * * **** **  * * ****   ** ***        **
*****     *****    ** ******* 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
* *** * *** ** **  
 * ** *  **   * **  **
int main(int argc, char *argv[])
{
**   * **  ** ** ***    * *      *  i, a;
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 * ***  ** *  **  ***  *    *         ** **  &i);
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** *  **** * ** ** *****  * **  *** **   ** *    ** *   *   * *  ***** * * *  ** **  i);
   **** *** *** ** *   *  * (i=1)
* ***** * *  *  *   ** * ***   **     ** * * * * * * ********  ** **  * ** *  ***   
 *   * * * ** *    * ***  * * **  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
 *   ****  **   *    
 **     * * *     

int    **   argc, char  * * {

 ****     * * *  int a=10;

* * **** ***** * do{
***  * ** **   **     *    ** *  ** *** * *** *  * your   ****  ** ** *
*   **   **    * * * **     * * * * *  * *   * ****** 
  ** ***  **     ** *** * *  *   *  
 **** ****          * a != 10 );
**  *   **  *  *  * 
* * *  *   *       *  ***   9 8 7 6 5 4 3 2 ***  ** 
* **   *     *** **      

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
***** *     *** *    *
    ** ** *** **** *

int **  * argc, char  * * ** {

****** * **  int     

***** *   *    ** do{
*    * ** * * * *   ***   *** * * **  **  **  *   your  ** *   *
   **  * *    **  * ****   ** * ** * **    * * *** * * **  ** *    *
  * *     ** ** * * **    ** if( a   *  10)
      ** * *     *      * *    * ** *    *       ***  * ****** code is too low!  * **  
*    ** **     **  *   * *** * * * 
*  *  *  **      ****   * *  if( a  * * *  10)
***  ***  ***  *   *  * *     * ***   *** ** *   *  *  *** *  is too high!  * *   
 ***  *  ** **  a != 10 );
  *  **      * **  
*   **   * *  *  *  *     *   9 8 7 6 5 4 3 2 **  *     
* ****  ** *** *   0;
}

Comments

Case 0: Wrong output