10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
*   * * ** *    *
int main (void)
{
int       **  
 *    **    *  * *    * * * 
*  *   
** *   *
    *
 *   * 
*  * *
** * 
*  *
* ** * 
*   ** *  * ** ** **       *    ** * 
if  * *       *  ** *       *** *    ****
* *  
else   *** *  ** * * 
f2=2;
else if ***
   *
else f2=4;
  **     ***   * ***   ***
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
* *  * ** ****    **    ***     a,b,c,d,e,f;
***  *** * * * ***** **  * ** count=1;
 * ***   *   *******  *  * *  * * * **   ***     ****
 * *      *  *** *  * *  *   *  ** **
* **** **** ** ** * *  *   *  *   *  **** 
 * * ***    *******    **  * *  *    * **** * 
  * * ****  *     *   *  * * ** ***  **** ** *  **
* **   *    **    *  *       *   **   
 ****  ** ** **      * **     **   ** * 
    {
  *    **   ***   *     * * *    ***** * *** *  **     * 
     **  *       *     **   *** * * * *   * ***** **   *  **  **
    }

* * *   * * ** *          ******** *   *  %d",count,f);
*    *  * * * ***  * **    **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
* *  *  * * * * ****  * 
int main()
{
 **** **  * *** *  **** ***   *   n,digits = 0,sum = 0;
 *        ***    ***   ******       *    ** **  *
 ***    **   *  * * ** ** {
 ** *     * ** **  *  ** ***  ** * ** *    ***** * ** = sum + n%10;
 * *   ** *** *    *  **  ** *      *   *     *        ***
 * *  ** * ** *  ***  **   *   **** **  **  * ***** ***   * 
    * * ****  *   *** *   *   * while (n > 0);
 *  **  * *****  ** * *     * * * *   ****** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include  **** * **  *    *

int   **** *   ****  *  *
int d=1000;

int main(){
  *  ******* * ** ** **   *  * **     *  * **   *  
**       *  ***  **** **  * *   * *** *

*   ***    *** * *  ** ** * *    ** *** ** **    **** **     * * * * = a/d;
  * **** ****    * *  *   * *  ***   *****  ***  * * ***   *  *** * **  ** * ** ** *** *******      *** **  
  *  *********    **  **    ** * * * ** **  ***** *** ** **   = sum + currentdigit;
   * ** *       **     * ** * *** ** *   **   *  * *  *** = a - (currentdigit * d);
* *  **** ** *   * * *** * *  ** * **** *   * *        

   *    *  *  * * ***** *** *  * **  **** *** * ** * ***  ****  %d\n", numdigits, sum);

 *  ** **** *      **  *   ** * 
* * * ** * *  ** * ****   **** ********* %d", numdigits, sum);
  * *  * *  * * ** * ****         * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  ** *  * *****  * * * *    * *   n,digits = 0,sum = 0;
*  *** *** ****** **     *  * * * *  ******  *  ** *  
  *  *      *** *  *  ***  {
  *   *** **      ********* **** ** * *  * **** ** ***   ** * *  ** = sum + n%10;
*  **** *** *********    *    ****  * *  * **  ***    *** **** *
  *   ***  *  *   *  ** ** *   *  **   ** ***   * ** *  *** 
**  * * *  **** *** **  * *** while (n > 0);
   * *  * ** * *  *   ****  ***** ** * ****** *** ***  
 * ****    *     ****    **  * *   * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
**   ***   * ***  ** *** *   *     a,digits=0,sum=0;
 * *** *  *  *** *     **     ****    *   * *  ** *  ****  **
**  ****  *  * *  ** * ** * ** {
***** ** *   * *  *  *  ***  * **  **   *****    * * *** ***
**  **    * ***   *   *  ***** * *  *          
  ****    **    ******  **   * * ** ***** *     * *  **  * ** *****
    ***  * ** ***** * ****  **** 
  ** *** **   * * * *   ** *  (a>0);

**   * * * *  * ** *** **  *** **   *  * **   %d",digits,sum);
*** * **  **  * *   ** **  *    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 **** *    * *** *  *
int main   
{
int  *   * ** *
*  ****** * ***  * ** * *
*****
* * *  *
  * **
*     *
** * *
**   ***
 **
* **** 
** *      ***  * *  *****  *** * **
if ***** *  ***  
  
else *    ***  
   
else if   ** 
**
else f2=4;
 *    *  *    *    * *  *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**  *     * **    ****** *     n,digits = 0,sum = 0;
 * * ****  ***** * *****     ***  * ******    ****  
*   *** ** ***   * * * * *   * **  {
 *  **   ***** * * *      ***    *   * *     ** ***  **   ** = sum + n%10;
*  ******   * * *  * ** *    ** ** * * ***** **  ** *  **** * ***
*  ** **    ** **         ** ***** ** ****   * ******** * *  * *  
  **  *   *  ***  *  ******* while (n > 0);
* **   ******   *   ** * * *  ** ** ** * * * * **  *
  ** * ** **** **  *** * * * ** * *  *  ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*  **** ****** **  *   ** *  *  a=1,b,c,d,e,f,g;
** ***  * *  * *      **       *  *   * ****  
 * * * ** * * **   ***   *****  
* ****  ** * * **** *  ****** * * ** * *** **  * 
* * ** *   * *    * * * **    *** 
** *    ***   * *   **** * *  *
**** ******  * ** *  ***** ***
    }
* *  * *** *  ***** **
* *** ***  * ***   **    * **  * *
*  ***** ***** **   ***  *   *  ** ** *
      ** *     *  ***  *
* ****        *      *  **   * ** * **      *  * %d %d %d\n",c,d,e,f);
 *  **    *    ** **  *   *** *  ** ****  %d",a,c+d+e+f);
    **  **     ** * *  *******   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* ***    ***** * **  ** * ** **      *  ** num,digits,sum=0;
   *  ** *   ** ***** ** ***   * ***   *****    * *** * ***   **
** ** **  *   * ***       ***  ** * *** **** ** * * ****** ****     * *   ** * ** *  &num);
   *      *  ***  ***** * ** ** ** * *
* * *    *  * *  * * *** 
 * * *  *   **** * *  * ** *      * *  ** * ***** **** **** * *      *  ** * += num % 10;
* * **      **    ** ***  * * ****  **      ** ****   *  *  *  **  *  * **   = num / 10;
 ** * *  * * ****   *      *********   *    * ** *** **  * ** **   * ***  **** 
    }
  **  ** * **** **  *  *** * *     *   %d", digits,sum);

  ** * *  *  * *      ***  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output