10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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* **  ** ****** *           * ***    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
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int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
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int  * * *** ****    
int d=1000;

int main(){
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*** **   * *  *  ** **  **** *  * * * %d", numdigits, sum);
   ****  * ***    **** ** **** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  *****  *** *    * * n,digits = 0,sum = 0;
 *    * *** *  **  *  * * * *** ***   *  * ***     ** **  **  * 
        **    * * * **   * {
***   *** **   * *  **   * ** ***  ********  ***  *  * ** = sum + n%10;
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   *    **** ***  ** * * ** * * *****  *  * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  **    ****** ** *** **  * * a,digits=0,sum=0;
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**********   *      ***    
 *  ** **  * *   *   *    (a>0);

  **** *** * * ***  * **    *** ** *  ***  %d",digits,sum);
   ********  ***   *  ** **** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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***  * **********   **  * *
int main   *
{
int *     *  
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
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*** **   ***   **    *   * * *****    **  * *  * *  **
*** *   ****   **   *  *** * {
* *    ****   *  * **  *   *  **  * *  * *** **    *      = sum + n%10;
 *  ***  * ******   *** *  *  *********           ***
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 *****   * **  *  * *    * while (n > 0);
**** *   ** ****** *** * ******* **   ***** *  * **** * * ***
* **  ***** *   * **** *   ** ***  *  * *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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    }
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   * * ***      *  * * * ** ** * *** **** * %d %d %d\n",c,d,e,f);
 *   ****  * *   * ** *  * ** *  ** *  ** * %d",a,c+d+e+f);
 ** ****** **  *  *  ******  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  ***** * *   *  ***  ****  **   **  * num,digits,sum=0;
***    ***  *****    ** *  ***   *  *    *** **** ****  *  ** 
 *  *  * *  *  * **  ** * *    *       **  *  *   ****  **   *   * * ***  *  &num);
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**  *  *  ** *** *** **
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*     ***** *    *  * **** *   ** * ******         ** *** *  **  * **   ** = num / 10;
  *  *  *      *******  * *****    * * *** * ********* * **  * *     *  ****  *   
    }
* **  * *   **    *      ** ***   ***** *  %d", digits,sum);

 ** *     *   *  * ****  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output