10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
  *    *  *  **  * *    
int main (void)
{
int  *  **** *
* ****   **    **  *   * ** 
* *** 
 ***  *  
***** 
* *** 
 ** ***
** *****  
      
 *** **
* ****  * *  ** * *  * **  *  * **
if ***  * * ** *****  * ** *  *  ** *   *
***
else   * ** ** * *  *** *
f2=2;
else if  **
  
else f2=4;
 ** * **    ****       *  ***
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
  *  * **       ** *** ** **   a,b,c,d,e,f;
****** **  **  *  *** *       *   count=1;
 *  ****   *  **   *       * **** * **   * ** * * *    
* *  * ***  *** *** ** ** * * 
  **** *  *  *** *   ***  **  ** 
**   *   ** * *  *** *** *  * ***    *
 *  *  * *  *** ** **  **   * **** ** ***  * *
 **   ** ****   ******** ** **  **  **** 
** ****  *        **  ** **  **  *
    {
 **   **  *   * * * *   *  * ***   **** *    ** ***    *   *   * ***
*** *  * *  * *  * ***  *   ** ** ******* *** *    **   *
    }

*    * * *  **  * ***   ***    *  *  * ***  %d",count,f);
 ****  **    ** *       * *  * **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
   **  ****   *  **   
int main()
{
*    * *****  *********  *  ** n,digits = 0,sum = 0;
** *   *     * ***   *** **** **  ****  ***   ******  * * 
 * ***  *  *** * ** ** **** {
*** *  *  ** ***  *  ***** *   **  *  ***    * * *   *  * *  = sum + n%10;
       **  *     * * * ** *  **  *   *     ** * ***   **
 ***********  * ** **** ** *  * ***** *  ***** *** **** *  *   *
  * * *   * *** * **  ** while (n > 0);
 * ****  **  **** *  ****      **    * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include  * **        *  *

int    ** ****    ********** *
int d=1000;

int main(){
  * * * *  *  *** ******  * * ** ***  *   *** * *****
 ****   **   **  **    **    *   **   ** 

  * *** * **  *** *  *     *   **** *  * * *** ********** * ***   = a/d;
   *   * ****** ** **** ** *   *  ** *********   ***  * *    ** * **  * * *****  * **
**      ** * *    **   **** * *  *  ***  *       *  *  = sum + currentdigit;
 * ** **  *   * **  * * *    ***   *   ** *   ******** = a - (currentdigit * d);
* **   *** *  ** *****    * ** ***      *      ****  **  *  *

 **   *   * * *   ** ***     *  **       * * *   ** *    ****   ** *** * *  %d\n", numdigits, sum);

  ***  *   **  ***   **** ** **
  * *** ****** **** **   *      *    * **   * * %d", numdigits, sum);
**   * *   *** * ***** * *** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
   ****        ***** **  *  **  n,digits = 0,sum = 0;
 **** * *  * * * ** ** *  *  * * * * ****** **     * 
  ** ** * * *  *  * ** *  * {
* * * * ****   ** *  ***    *  ** *  * *   * * * *    * = sum + n%10;
 * *** *  ****  *   ***    * * ***  *  ** *****  *  ** *** ** * 
**  **  * **      *   **  * *    *  **    **     *  *  **    ****  
 **  *  * **   * *** ***** * *  while (n > 0);
** ** * * ** ****  **  *   *** * ********     ** * * 
 * *  **  ** *   ****  * * *  *** * ***  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*  ***** ****   * ** **   * *  a,digits=0,sum=0;
** *  **** *    *** ** **   ** **** ** * *  * * *  * ** *
     *   *********   * **** {
    ** ***  ** *   *      *   ****  *   *** * **  *  * ****** 
**  *  *   *  * ** ** * ** * *  * **   *    **  *  *
*  *    *     * ***  *      ***  * ** *  **  **  * **** *****
***   * * * **    * *     
***         ****       * ** (a>0);

* *  * *  ** *  *   *    *    ** %d",digits,sum);
    ****    *   *    * * ** ** *     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*   * *  *  ***  ***   
int main * *
{
int  ****** *
*** ****      ******* *    *
  * **
* *  * **
** *  
** * *
*     
 * *  *
*   * 
***  ** 
**** * **   ** ****  * *** * *
if   **   * * 
**
else    * * *
 * **
else if ***  
   
else f2=4;
***   *******  *  * ** **  *   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
   *    * *** * *   * *  n,digits = 0,sum = 0;
 *   ****     **   *  *  **  * *  ** **** *********
*  *  *   *   **** ***  *     {
**     *** **  *    **  **  *****   *  **   *  ******  **  = sum + n%10;
* *    **   **  *   *  *** * **     ** * **  * *** **    *****
** * * *  ** ** ** * **    *     **  ****  ** **  *  **  *
   * ** * * * * **  * **** *  while (n > 0);
**   * *   *** **  *** **  *     **** **** 
*   * * * *    *******  **    **  ***     **     d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
      ** * * *** *  *** **    *  a=1,b,c,d,e,f,g;
** ** ***** **  *   ******    **    **  *   * *  ** 
   ****   **  **  *  
 *    * **   *   **   * * ** * ***  ** 
   * ***        *  ** *  *** ** 
 * ** *** * ** **** *****  *
   ** ** *   * * **   * ** *   **
    }
      **  ***  ***  * ****  * *
** * *   *  ** ********    *   *   * ** 
 *      *  ********* ***  *   **  
*  ***** ***   ** *  **** *      ****
 * *    ** *** * * ** *  ****** * **    *  %d %d %d\n",c,d,e,f);
  ** *** *** *  **  *  ***  ***** ****   %d",a,c+d+e+f);
 **  *  *  * *  * *** *   **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  ***** *** *   * **    ** ** * *** **   *  * num,digits,sum=0;
 *****    **  *     * **   ***     * **** *     *    *** **  **   
 **      * * * ***   * *   * *   ***    ***  *   *    **  *   **   *** ***  **   * &num);
    **  *  * * **** * * *    **  ***  * *
 *  *  ******  *  * *       *
   **    ** ***  **  *    *******  ** **  *  * **** **    ** **** **   += num % 10;
***  *              **  * *  * *   **  * ******** *  *  ** ****** ****  ** = num / 10;
** **   ** * *   *  ** **** **  ** ******* ** **  **** ** ** ** ***  * *  * **** *
    }
 * *** * * ****** ****  *******    **    *  %d", digits,sum);

    *  * * *  ***  *** *  *** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output