10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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{
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f2=2;
else if  ** 
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else f2=4;
*    ****       ***  *   *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 *     * **** ** * * ** *   *  * a,b,c,d,e,f;
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    }

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  * * ***** * * *   **    *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
  *** *** ** * *  **
int main()
{
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**  * *  * *  *    *** *  **    **** * * * *   * * **   **  **  
*   * * ******* * ***  *   * {
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**    ** *** ******        **   *   while (n > 0);
**  *   *  * ***** *  * ***  ***   * **  **   d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include *   **  ***  *

int **  **  * ***     *****
int d=1000;

int main(){
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**  *    ******   ***      ** *     * ***     ***  * ** 

**** * *****  **   *   *  *  **    ***  * *   ** * *** **  *  ***** %d\n", numdigits, sum);

       *** *   ***    * * * * 
* *** * **  * **   **    *** * * *      * ******   %d", numdigits, sum);
 * ****     * *     ** * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 * *   * * *   * *   ****  *      n,digits = 0,sum = 0;
    **  ***** *  **   ** ***  * *  *  **      *** *   ** * 
* **    ** ** *****     * * ** {
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 * * ** ***** ****  *  ** *  * *     ***   ** 
****    *   *    * * ****      **** *   **  ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  ** ******* **  *  *  ***  * a,digits=0,sum=0;
*** * **   **** *** * **  ** ***      *** * *  *
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   ** ******* *   *   **  (a>0);

 ** * ***    **   *  *  ** *** * *    ** %d",digits,sum);
      ***** ** * * * ** * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*  * **  ** ** *  
int main ****
{
int *     ** 
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else if *   
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else f2=4;
*  *** ** *   * *****   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
    * ** ** *    *   *     * * * n,digits = 0,sum = 0;
 *        **** *    *** *** **    ***   *  ** ***  ***  
**    ** * ****** ** ** **** {
* *  * **  *    **    * * **  ****  *** * *  ******   ** = sum + n%10;
 ****  * *  * *  **    *   *   *   *  * ***  *  **     * 
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**  **** ******  * while (n > 0);
 *   * **     *** * * **  ** * *   ***  *     * *
 ******* * *    *  *     *  ***   **   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**  **  ****   * **     * ***  a=1,b,c,d,e,f,g;
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    }
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  * *  *** *    * * *****  * *  **  ****  %d %d %d\n",c,d,e,f);
*  ******  * *  * **   * * * ***    *   %d",a,c+d+e+f);
*** * *  ****      *    * *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* ** *     *         ** *   ***  *** num,digits,sum=0;
  *      ****  *****   ***    * **    * *** *     ***  **       
** ** * * * ** *  *** *** *  ******       * **** ** ***  ***  **** *  * **    &num);
*********** **    **  *  * **   ****    *** *
**  * ***  *   ***  ** ** * ** 
*  ****    *     * *    * *  *   ************* ***   * * *** * *   *     *    * * += num % 10;
* *** *   * * **  ** * * *   * ***  *      ***  * ** **  **  *** **** * *    *   **** = num / 10;
 *   ****  * * ***   *  * * **   **  ****    **   **  **  ***  ***** * ***
    }
  * * * * * ***  ***   ** *   **** * * %d", digits,sum);

** **   *  * * ** *  *  ***** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output