10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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{
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f2=2;
else if ** 
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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**        *   * ** *    ***   **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*****  * ****  *** ***** 
int main()
{
* *  * * * * * ****   * * *****  n,digits = 0,sum = 0;
**  *   **  * *  *  *  ** ***    * **   *    ***  
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   ** **  *       * **    while (n > 0);
  * * *  ** ** ** *  * * *  *  * *      *  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include     ** * *** ** **

int *  **          ***   
int d=1000;

int main(){
       ***** **     *  * *    ** * *   * ***   
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**** ****  *  *   *****  * *    **  *    ***  **    *   

*** *  *    ***** ** * ** * ** *   *  **   **   * **   ** * * ***** *     %d\n", numdigits, sum);

*  **  *** * **  *** ***    
* *  **   *  * * * *  * ***  * ** *** **   %d", numdigits, sum);
**    *** *   ***   **     * * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
* *  * ** ** ****  *  **  * *  n,digits = 0,sum = 0;
*   **** ** ****** ****  *** * *  * ** ***   
* ******   * *   *** **  {
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* * * *** *******   *** * *** while (n > 0);
   ** ** ** * *      *** *** *   ** *  *  ** *  *** * * 
  * *  * ** *** * ***   **** *   * *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 *** **   *  *  *** *   a,digits=0,sum=0;
 *   *  ** ** ** *  *  ** ** *  * * * * * **  * * 
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**  ********* *  ** *  *  
   *    *   * *  * ** ** * ****  (a>0);

**  * * *      *   * ** *   ** *   *** %d",digits,sum);
  ***********   *    *  * ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
     ** *   *     **
int main  **
{
int *      **
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else if *    
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else f2=4;
      **   *   ** * **   * * 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*** ** *  **** *** * **   n,digits = 0,sum = 0;
* *  * *  ** * ** ****       ****   **   *   * *     **********
   *     * **  * *    ***  * *  {
 *** **   * **  ***     *  *  **  **  **  * *   * **  = sum + n%10;
 **  ***   *   **** ** *        * ****  ** * ********   ** 
 *** *  ** *** ** ** * ***** * * * **   *   **  ***   *  * 
*  *  ****** * * ** *  *** * while (n > 0);
* *      **   * * ** **   * * ******  *     *
*** **  * *    *** * *****   ** *  * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
      * ** *       *   * *** a=1,b,c,d,e,f,g;
***** **  ** ** ***   *  **    ** **  *  ***  *****
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    }
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        * *** ***  ***  ***   *     *   %d %d %d\n",c,d,e,f);
*    ******** ** *   *  ***** ** ** *** %d",a,c+d+e+f);
** *** ***      *      ** ** * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*     * ** ***    *   ** ***** num,digits,sum=0;
 *     * *** *  **   ** ** ***      * ** * * *** * *** 
***    **  *  *    *   ***  ** **** *** * * *****  *** **    *    *    ***  *  *   *** &num);
****    *  *** ** *********      *  *  **  
*  *  ** * ********  * *  *
 * *** ** * *    ** ** *     *  *  *  ** **        **** * += num % 10;
  * ** **    **  * *****     *  **    ***  *   ***       ** * * * **** *  *  = num / 10;
 ** *   **  ** **  *** **    * ***    ** ** *   * **   ***     *   *  *   ***   *  *
    }
 **** ***    *     *  *   * ***  *   *   %d", digits,sum);

** ** *     ***  **   **      0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output