10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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f2=2;
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
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int main()
{
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*** * **   *  ** ** * * *** * ** while (n > 0);
* **  *   ******* * * ** **     *** * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  ** *   * *  

int  ** *  *    ** * *   *  * 
int d=1000;

int main(){
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**  ** ***  * * *    * *** * * *     *  *   * ***** *****   = sum + currentdigit;
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  **    * *** *****  *   *
*     *****  * **   ***  **  ****** * %d", numdigits, sum);
  * *        *** *    *  ** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**     ** ***  **  *  ** n,digits = 0,sum = 0;
  *     ****  ***  ***   ***  * * * ** ***    * *   *  
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 *  *  ** * ****** ** ***** * ** * *    * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 ** ** ***    ***       * * ***   a,digits=0,sum=0;
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  ********** ****** ** *   **  * *    *  * %d",digits,sum);
    * * *  *  ***  *   *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
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int main  *  
{
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 *  *****        *  *   **  **  * n,digits = 0,sum = 0;
* * *** *    *  *****  ** **  * *      *  * *  *  
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               * ***  *        *  *   **** *  ** * * * *   = sum + n%10;
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* *   ** *   ** ********    * while (n > 0);
***** *******   ** **  * *** **       *   **  * ***    *   *
*     ** *  ******   * ***  * *  **  *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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       *** *      ********  **   **  * %d",a,c+d+e+f);
**** *  **     **   **   *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*   * ** * *  * ***  *   * *        num,digits,sum=0;
 * * ** ** *** *   *** **  ****** *  * ** * *   * *** ** **  *
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*   ** ** *  *   ** * *        ******    *
* * ** **    * *****   * ***   
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** * ******* *   **   **  *** **  ** *  **    * *  ** * * *  * ** **  ** * ** = num / 10;
* *  ***    ** ***  * **    *  ***  * * *  ***    *  **    * **     ***   * 
    }
  * ** *      **     *  ****    **  *     * %d", digits,sum);

 **  *   * *  *    **   * * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output