10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
 *   *****   *    
int main (void)
{
int  * *   *** 
**  * ***  ***** **** * * *  
**   
 **** ** 
  *   * 
  ****
* **    
* ** **
**   *
*** **
    * ****    *      * *  ****
if **** * * * ****** ** *   *    *   **
 ** 
else **  * *** * * * *  ** *
f2=2;
else if ***
** 
else f2=4;
*** **     * * *** * ** * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
******   **   * ***   * ** a,b,c,d,e,f;
** *    * * ***    * *   * *   * count=1;
*   *  ** *  ** *  ***  ****   *       * *  * ** * *   
*    *  *** ***  * * *  *     
          *     * * ** ***  *  ***
* * *    ***  **** * *  **** ** *    *   *  ** **
*  **  *** *  * *  ** ** ***   * * ***** **** 
**   **        ** *   * * ** * ** 
*     ** * *  *******     * *  * *** * * 
    {
 * **   *   * *   *  *  *  ***  ***********   * * *** **** 
* * * *** *  ** *    *** * *  *   * ****  **  **   *     * *** * ** 
    }

  *  * **  ** *  *  ** ***** *** **  * * %d",count,f);
     ** ******** * ****** ***     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
    *** **** *  * *  *   
int main()
{
         ***  *** ** ****     *  ** n,digits = 0,sum = 0;
*  **  ** *****  ** ** * **   ***  *    * **** **  *  *
    * ***     ***   *   * *  {
*  *  **    ***  *  * * *** *  ** * **   **  **  * *  * * = sum + n%10;
  **   ***** ** *  ** **      *  ** *  **  *** *     *  * *   
 * **  * ** *****  *  ** ***  **   **  *    ***  *  *   *
   ** **    *   *  *** *  ***** while (n > 0);
**    ** ****** ** ***   *     * ****   * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include ******* *  *  *  

int ** *  *  **   ** * *  *   
int d=1000;

int main(){
**  **  *  ****  * *  **** ** *  * ** * ****  * *  *  ** 
*  ** ** ***  **  *  *  * *  *****  **  * 

   * *  * ** *   *  *     *   *  ****** ** * **   *  ***    = a/d;
** **** * *     **** *** ****   **  ***** *  ****   * **    ** **  *  *    *****  
   ***  ****  * ** * *  *  **** * * * *  **   ***  **** ***   ** = sum + currentdigit;
* *        ********   ***   *  *** ** ** ** **  * ****  = a - (currentdigit * d);
* *   *  * ** * *  *****  *   ***  ** *  ** *  ********

  *  * *   **  ** **** *    *** *******    *** **  * *  ****   ** * *  %d\n", numdigits, sum);

** *   *  **** *  * * ** *  ***
   *** *   * ***  *** * ***  * * ***** * * %d", numdigits, sum);
**  *  ***    * * **      *** *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  * ** ** *   *  **  *****  *  n,digits = 0,sum = 0;
 *****   ** *  ** * *** *     *  *** ** * * *  ***  **** *   ***
 **   *   *    *       *  *  **  * {
*****   *   *  ** *  **   **  *   * ****  **** * *  ***    = sum + n%10;
** ** ** ** * **** * ** **  * **   * **  ** *** ****          
        **** *  *     *  *  *     * *  **  **  * *    ** *   * *
*     ** *  *** **** ** *   *  * while (n > 0);
 * ** ** *  **  ****** ***  * **  **  ***** *** ** * 
* *  ** * ** ** * ****** *  **       **** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 * * *   * *** *  **   ** * a,digits=0,sum=0;
** **   *   ****  * ** *   **** ** *  *     * * ***   
**  **** ****   ***   * **    {
*******  *    ** ** * ** * * * ****  *  ** ** * ***
*** * *   * *** * * *** *  **** **     *   * * ** **** **
  * *** * **** * ***     * *****   *  * *  **  *  ** * *   
*  ***** ******    ***  *
*  ****** *  **   *** **  *** (a>0);

       **** *** * ****  ***   *     *    %d",digits,sum);
* * * *  **  **   *   ****  * *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 **  *    *  **  *  
int main  *  
{
int   ***    
  ****** **  * *  **  *  *  **
 ** **
  ****
*    *
 *** *
  *  **
*   ** 
*   * *
*   * **
*  *******   **      *   * ********  
if             
    
else * * *  ** *
** **
else if ** * 
 * *
else f2=4;
*   ** *  *  ** ** **  ** ** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 ** **** * **   **** *** * n,digits = 0,sum = 0;
 ** * ***  *     *  * *****    ****  ** * ***     * **** * 
* **   ****     ******* *       *  {
 **   *** ****   *  ****   ** **  *  ***  *** ******* = sum + n%10;
 *** * **  *   *   *    *      * * ** * ***** ** ****** 
 ** ****  * * * * ****** **  *  ***** **  *** * **   *  *   *  
* * *****     ****     *  ** while (n > 0);
** ** ***    * ** ** * *******  ******   ** *****  *
 ***   ***  *   *  ***  *   * ***  ***  * ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**  *  *  * *  * ** *  *   ** a=1,b,c,d,e,f,g;
*** *   ** ** *  ** **** ** * **** *  **********  
 ** *  * *  * ***  *   * ** ***   
 *  ***  * **  ***   *** ****    
* *  * ***    *** *
   * ***    *****   **    **  * * **
*    *** ** * * *  *    * **       *
    }
***  **   * * **     **** *   ****   
 ******  **  **** ***  ** *  **    ** **
  *  * *  *** * * * **    **   *  
  **** *** ** ***   *   *  * ***
  *   * **** ***  *** *  *  ** ** *  %d %d %d\n",c,d,e,f);
*  *  ****  * *   **   ** **  ***  ** * %d",a,c+d+e+f);
**  *  *     * * * *  * * ** ** *    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* *  ** ********* *   **   ***   * *  num,digits,sum=0;
* ***    *****      ****   *  *   **** *   *   *** ***  *** *
  ****  ** * ****    ** ** *** * * **   * **    **   *     *** * **   ****  * ** ** &num);
  *   ***    * *   * **   * ** *** *  * *
* *  * * *  ** ***     * *** *
  * * *     * *  * * *** ** ******  * ***  *  ******  *     ****   *   * **   += num % 10;
  **** * **** * **** ** *****     * ** * **** * *     *   **    *   **   ** = num / 10;
*   **  * * *          *   **** **  ** ** *  * * ***  *       **  * **   *   **   *  * 
    }
 ****** *****  * ******  **  **** ** *  %d", digits,sum);

  ***  * ***  *** *  ***  *  **** ***** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output