10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
  ***    *   * *  ** 
int main (void)
{
int *      
 *  ** *** *  *  **    * ***
***** **
* * **  
*     
** * ***  
     **
 *   **
  *
 *   
*** **   ** ***  *** *  *      * * 
if *   ** * *  * *** **   ** *
  **
else   * *    * ****  ***** **
f2=2;
else if * *  
** *
else f2=4;
  **   *    *  *   ***     **
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
  *     * *   **          * *  **  a,b,c,d,e,f;
 *   ** *  * * * *** *** *   count=1;
  ****  *      * ***  * * *****   * *           
   * **   * ** **** ** *****     * 
   * *   *  * ** ***  * **  *    *  
    *  *  *   * *** * **   ** ***      
* **** * ***  * *******     *   * * * * * *  *  ** 
 *   *    ***     *  * * ** ** 
*  * *  *    * ****  *      *** **    ****  *
    {
 *  * **   * * ** **  * **** *  ** *    * **** *      * * ****
 ***  *****       ***  ***   ** * ***    **     *   *** *
    }

* **    *    ** * *    * *  ***** *    %d",count,f);
* ** *   *   *   **    ** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
  * *    ** * * **  
int main()
{
 ** ***   ** **** *    *   n,digits = 0,sum = 0;
* * *****   ** ** *********         *  *    ** * ****
 * ** * ** ** * *** *** * *    * {
****  **   * * ** ***   ***   ***  ****   * ** * * *** *  = sum + n%10;
*  * ** ** * *        * ***  *  * **** *  * ******   ***     
     * ** *** ** * ** **** ***  ***   **  **  *  * *  **  **
* *   **  * *  *   **  *  *  while (n > 0);
    ***   **  ***** *** **   **** * *   * ** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  ***   * * ** *

int ** * *  *  ** *    * ***
int d=1000;

int main(){
**   *** *** * * * * ***** **  *  ***** *  * *     ** *
  *** **** ****** **** * * **** *  *** * 

 *** *   *  **  **   * *** ** *   **  * *****    = a/d;
*  * ** **   *  *    * *** * * *   **  * *  ***   *    * ***** *  *   ********     * **
** *  *   **** ****** *** ** ** ****  *  *  *  ** **    * = sum + currentdigit;
****    **    ***   *  *  *  * ** *** *   ****    * = a - (currentdigit * d);
*    *    **** * * * * ***** *  **  **   * *** **  *   *

*** * **** * * ** *  *** * * * ****   *  ** *   *  **  ****     **  ** * %d\n", numdigits, sum);

   *    *  ***  ********* *
**    * **    *** ** * *******  *** *   *  %d", numdigits, sum);
        *       * ***     *  *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*    ** * ** *  *  * **  **  * *  n,digits = 0,sum = 0;
* *  *    *  ****** *  ** * *   ******* *** **   **  *  *
** ** ****** ***  ** * {
*     *   * *   *********    ***  ********   *   * *   = sum + n%10;
**      ** ***    * *** ***  *   *******   * **  *    * ** **   ****
  * ***   *      ** *****   *  ** * ***  *  * ********   **
 *** * ** * * *   **  * *   *   while (n > 0);
** **   *  ***** *****  *** **     * ******* *  **  
** ****   *       *  * * * * *    ******    d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*  *   *     **  ** **** *  *  a,digits=0,sum=0;
** ***** **   *** ******** *   * ***    ** * ***  
* * * * *  ** ***  ** *** {
*   *** * *  *  *   *   * **** * *  ** *      * *      **   * 
    ** * *** *  * * ****   ****  ** *  *   * *****   * **** ** * 
  * **  *    ***   **  * ******  * ** ****    *  ** * *
* **** * ** *** ******    * **
** * *   *  *** * *  **      *** (a>0);

  * ** *      **** ** * * *  **  ** * ***** *  %d",digits,sum);
      *******  **  ** **   **    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
**  *   *** ** * *  **
int main **  
{
int  *    ****
   * ******* *   * * * *** 
     ** 
 * **  *
** * * 
 **  
*** 
 **   *
 * *
**** *
 *  **  *  ***   ****  ***   *   
if   *** *  ***
***
else  ** *** *
  * 
else if    * 
  **
else f2=4;
***  **  ***  *   ** ** ** * *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*      *    * *   * **** *   *  n,digits = 0,sum = 0;
* *  * * **** ** **  **  *****       *  ***     *
 *  ****** *** * * * **  *  {
 *  **    *  *  **  *   * * *    *    **   * *     ***   = sum + n%10;
  ***  *  * * * **  *  ******    *    * *  **  ** **    **   
*  **  ***  *   ** *   **   *   * ** **   * *  *  *    *    *  *  **** 
* *   **  *   ** ***** *  *** while (n > 0);
  **  *  * ****     * ** *** * *** ** **  * **** *  ***
*  * *   * *   * *     ***   **** ***  *** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**** *** ** *   * ***   **  * a=1,b,c,d,e,f,g;
* ** ******  *     ** ** *** * *   * * *  *** **    ***
**  ** * ** *   **** * *   * ******
    *  ****   * *  * ***   **    * ** ****** ***
 ***** *** * **** * *  ***  *** 
   *     ** * *  * ** ****  ** *  
* * * ** * * ** *  * * *   **
    }
 * *   * ***  *  * **    *  **   * 
** *    ** ***    *  *   * ***     ******   
 * * ** *   *****  **** * *******
* * ****** ** *   ** * * ** 
  *   *   * *  ****       **    ****      %d %d %d\n",c,d,e,f);
 ** * * ****   *   ** ** **** *** ****  %d",a,c+d+e+f);
*        ***      * *    * * **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
**  ****   ** *  ** * *  *       ** num,digits,sum=0;
  *    *  *** * * *  **** * ***  **   *** **   **        * **** **    
** *      ** * * * *** ******   * ** **  **   * *******  **   * * **   *  *  &num);
 *      *  ** *  *   * *  *  ** ** *     *  *
* **  **  *   *    **   ** * 
    *  *  *  * **  *** * *********  *** *******  * *     * **  * *** * * += num % 10;
* *   ******* *   *  ***  ***         **   * ** **    *  ******    **   ** **  = num / 10;
**       *  *   *** *  **   * *   *  *** *** ** **   * **  *  ** * *   ***   *  ***
    }
**** ****  *** *  * **  *  ** *   *   * * %d", digits,sum);

    *  ***   *****   ***  *   *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output