10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
**     * *********  *
int main (void)
{
int   * ****  
  *  *  *** *       * *
***** *** 
*    * 
** *  
***  * *
 ****
 * * **
***** 
**    **
 *** *  * *  * * * ***** ****  ** ** * *
if ***  * ******* *  ******  * * ***  *     
* *
else **  * * * *     *** 
f2=2;
else if *  *
*  
else f2=4;
** * *  ** ** * *  *     *  
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
*  ** * **     ****     ** * *  * a,b,c,d,e,f;
*  *   *****  * ** * * **** * count=1;
   ***   ***** *   *  **  **  * **   **  **    ** *  *  *
***     * *****       * ** * **
   *** *****  ** *   *  ******* * * ***
* * * *     *   ** *   ****  ** ****  ** **
*** *         *  *   ** ****   **  *    **** ** *
** *  * **  *    **     ***  *  * 
  *   *  ** *****  * ***** ** *    * 
    {
  * ** *  ****    ** ***** *   ***** * * *****   ***  **  ** 
**       ** ****** *** **   ** ****  **   ****  *  * *  * 
    }

  ** ****** *  * * ** ***   *** *** * %d",count,f);
  *  * * * ** *****   * ** *  *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 * **  ** ***  * * 
int main()
{
** ** ** * *** ***  **  **  *  n,digits = 0,sum = 0;
***  *** * * * *  ******  **** ***    * ** * *  **  **  **  
     *** ** *    *  *   *** {
* * ** ****** ****  ** ***   **  ********** **** *** **   = sum + n%10;
    **  ****  ***   **  *****    * **       **** *   *** *    
*    ****** **** **** *  ** *** ***   * * *   *   *** *
      ***** * *  * *** ** *   * * while (n > 0);
** * ***    *  *  **** * ***** **  *   * ***  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include ** **    **   *  

int  **     * *   * *    **
int d=1000;

int main(){
 *** *  ** ***  * *  * ******     *  ** * * *   * *   *  **  *
 * *   ** ***  ****  **  ***  * ***  ** ** **

**     * ***  ** ***   *  *   * * **   *  ** **    * *  **    *****   = a/d;
***   *     * * **** ** ***  * **** * *  *            *   * **  *   **** * *   ******** ** *     ** 
 * ** *   *  * ***** **** **   *   ** ****  * ****  * = sum + currentdigit;
 **  *  *    ****   ***  ** * ** *****  ***  **   *    = a - (currentdigit * d);
 * **** *  **** ***  **  ***  *  ** *  * *** *  *     * * 

*   **** ** *  * ** * *     * *   *** **  *   ** *   *  * **  *   *** %d\n", numdigits, sum);

    **  * * ** **   ***
  ***    *   * * *  ***    * **  *** *  %d", numdigits, sum);
    *****  * **   *  *****    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 ** *    * *  ***          ** n,digits = 0,sum = 0;
***** *****   *   * ***  ***   *  *   *    *  *
****  *  *     * * * **    {
  *  * *****    * *  ** ****   ** ** *  *    *  * *****  = sum + n%10;
**     ** **  * *  ** *  ** ** **  ***** ** ** * **** * ****
* *  *  * ** ** **  *      * ** *  *** **    *       ****** 
  * ***  ***         * *     while (n > 0);
   * *  *   *** *   * **  *       * **  * *
    *** **   ** ***  *     * ***  **      d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  ** * **** *  ** **** ***  * * a,digits=0,sum=0;
* **  **   ** ** * *** * * * *  *    *   ** * 
* *** ** *        * ** *** *   * {
*  * ** * *  *    * *     * *   *  ***    **  * *     *  * ***  
     *   ***    *    * ** **  * *      **        ** *   * 
*  *******  **** **    * *** ***    *****  * **   ** * 
*** *** * **** * ****   *    
* * * **    **** *       **  (a>0);

*  * *   * *  *  **  ** ** ** *       * %d",digits,sum);
*  *** **   ***** ** *   **      0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*       ****  **  *
int main ** 
{
int  ****** *
  ** * *  *** *     *   ** 
 * *    
*****   * 
*** * 
    **  
** * **
**  
*  
*    *
* ***  *  *  * *  ** ** **  *** 
if  ***  * 
* * 
else  *** * **
 **** 
else if * * 
 **  
else f2=4;
**    *      * **** ****   * *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 * **    *  ****  **** *     n,digits = 0,sum = 0;
****   * * *   * ** * * * * *   ******** * ** *** * * * * *
 ** ***** **  **  *  * {
  * * *  **    ***  **** ***    *  * *   * ** ** *  **  = sum + n%10;
  * ***  * **   *** * **  **  *   *** ** *  *      *  
     * **      *  ** * *  **   *  **  *  ** *    **  *** **  ***  *
**     **   ***    *  ***** **  while (n > 0);
    **   **  ** **** ****  * ******     ** *** * ** 
* *   ***      * ***    **   * *  * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*   *   * ********* ** ***** *  ** * a=1,b,c,d,e,f,g;
   **  ***** **** *  * *   * * *   ** * * **   *  * **    
 *  ****    *   ** ****   **  *
*** *    *  ** **  * **  * *   * 
* ** *  *  **  * *    ***** 
* ** ** * ***** * * * * * * *   
*** *** *      * ***  ****     
    }
 * **   *  ** * **   *** *  *
     *** ***** ****  *   ***  ***
 * *  ****   *    *  **  * ** * *    *****
*  **  **  *   * ** **  ** *    *
   * * ** **** **** *   ***   *  * * *   %d %d %d\n",c,d,e,f);
****        * *    **   *** ******  *** %d",a,c+d+e+f);
**   ****  **** *   ** **  ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
   * *** * *  ** *  * ** * *  ** num,digits,sum=0;
***  ** **  ******  **  *   *****  ***    **** * ***   **  ** 
  * ********  * * * ** * *   * ** *  *  *      * * **  * *** **  * * ***  * &num);
*** **   ***** *  *  **  ****  *   * * *  * * 
   **    *  *  *     ****
*** ***  ***   * *  * ** ** * **** ** **  ** * ** **  * * *  *********  * *   += num % 10;
* ** ******   * **** * ***  * *  * *** * **  *   * *  **** ***  **  * * ** *  = num / 10;
* * *  **             **  * ***** *    **   *    ** ** ****    * ***   * **** *
    }
** *   ** *****  **   *  ***** *   ** ** %d", digits,sum);

**  * **** **   ** * *       *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output