10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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f2=2;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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* *      *    *          0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
* **   *  * *  *   **** * n,digits = 0,sum = 0;
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include ***   *** * **

int ********         ***  *****
int d=1000;

int main(){
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 * *     **    * *  *** ***** **  ***   ** %d", numdigits, sum);
 **   ***  * *    ***  ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
* *  *  ***  ****    *    n,digits = 0,sum = 0;
 *****  ***  **  * ***     **  * *  *  * *  *    * *
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*   **    * * ** ** ******* **  ***  **  * *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*  **  *  **  **** **  ***       a,digits=0,sum=0;
**  *****    * ****  *** ***  * ****  * ** *  *** 
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* * **  * **  *     **      * *  (a>0);

*  *   *  **   *    * ** *  ** *      *  * %d",digits,sum);
  * **  *  *  *****     *******   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main ** 
{
int *        
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else f2=4;
****  *****    * * *****  * * 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 ** *** *  *     * * *  ****  n,digits = 0,sum = 0;
*** * *  ***  ** * *    ** * *** ***** *** * * *  *      **
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 ***    ** **  ****  ******* **** *  *   ** *****  **  *
  **  * **    ***  **  * while (n > 0);
   * ** * *   *** * *  *  *  ** *   ***    *  *  * *  **
 *  * * *   *  * ** ******   *****  *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  *  *  * ******* ** *******   *    a=1,b,c,d,e,f,g;
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*    **  ** *    *   *     *    ** *  ** * * %d %d %d\n",c,d,e,f);
** *  * ** * **         ** **** * **  * %d",a,c+d+e+f);
**  ** * * **** * * * ** **  *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  *    *    **   *  *    **      num,digits,sum=0;
   * ****   **   **   ** **    * ***  *      * ****      *  ** * 
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**** * * ** * ** **  * ** **   **   ***  **  *  ** ** *      *** ** **     ** += num % 10;
***  *   *** * *** ***    ** **  *    **   ** *   * *****  *  *    *****     = num / 10;
*** **** *** **  ****  *   *  *** **  *   * **     *** * **   **  * * **  *    *
    }
*   **    *  ** *    * ** * ***   ** %d", digits,sum);

  *  *  **  *  * *  *  *     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output