10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
 * *  * * **  * * ** ***
int main (void)
{
int *    ***   
*** * **    **  *  **** **
   ***
  ** *
 ** ** *
* ** ** 
 * ** 
 *** * 
 ** *
** * **
 ***   ******  * * **  **** * *  *  **
if **  * ** **     *  **  ******
* *  
else  * **  * *   ** *  
f2=2;
else if  
** * 
else f2=4;
* *  ** *** *  **   *** *** ** **
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
* ** * * * * * **  ****   a,b,c,d,e,f;
*  * *******     *  *****  * *** count=1;
  **   ***  ***     *****  ***   * **  **    *  
* ** ** *  ***   ** ** *   **** **  
***  **  *  ******  * ** *******   **    ** 
** *********** **    * *  *   **   * ***  ***** 
 *   **  ** * ***** *     **  * * * ***  ***  *
** ***   ***    ** * *** *    *  *  
   ** *  *             * * ***    ***  *
    {
    * ****** ****  *  *  ** ***** **   ***  *     *  **  
* **** **** ** ** * * *** *  *    ****  * * *       ***
    }

*****  *  * *    *  **** *  **  * ** *** **  %d",count,f);
***     *      * ** *  *  *  * *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 *   **** **    *    *  * 
int main()
{
* *    **   ** *  * *** *  * * n,digits = 0,sum = 0;
*  **   * *  **  * * * * *****  * **     * *  ***   *    
 * *  **  *** * ***   **** * **    {
  *  * *  *    *** *   ****** *** *     **  *  * * **  = sum + n%10;
 **    *  ** * ***** * *   ** *    * **** **    ** * *    **   
*** * *** ** **** *  * ***   **   * *  * *  * * * ** *    ** 
 *  * * *  *   ****** while (n > 0);
**      * ****    * *** **   * *  * ** * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include   * * ******** * **

int *  * ******  ***   *** * 
int d=1000;

int main(){
   *  *  * * *  * * **** ****  *** * * *    *** **** * *
** ******* ****       * ** *******  * ** **  

*   * ** * * * **    ***          ***  ********* *   * *     = a/d;
  *  *** * * * * ****  ***    ***  * *    ***    * * *** **    * ** *****    * *  ***  * **    
 **  *  *******     * * ******  * *** *** * ***** ** ** * = sum + currentdigit;
* *    *  *  * **   *******      ** ******* * ** ** **** = a - (currentdigit * d);
**     *** ****  *   ********** **** **  * *  * ** **    **   ** 

   *   * *      ** * ** *  *  ****  ** **     *    ** ******* *** ** %d\n", numdigits, sum);

     ** *****  ******* * ** *** *
**  ** * **   * *   *****   **   **        %d", numdigits, sum);
  *      **  *  ***  * *** * ***  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**     * * * * *  * *   *** *  n,digits = 0,sum = 0;
 *  *******    ** *****  * * ***   ****  *     *    *
 **      *** ***  *****    * *    {
* *****  *** **   * **      **   ** * ***  ***    = sum + n%10;
**    *   *  **  ****   * *  *   **  * **  * ** * **  *  * *
* ** ** ** *   **  ** ** ***  *    *    **  * *   ***  *      
  *  ** * ***    ***   *   while (n > 0);
* * ****    *     * ***** ** ***  ********    **  *  *
***  **  ***   ******** * ** *    ***** ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  * *   * *  ****  *  ** * ** ** a,digits=0,sum=0;
* ******    ****  *  *   *  * **  ***  *  ** *  * ** **   
* *  **** **   **          {
*** **   * *   * * **  *  **      * *  *  * * **      ** * * 
*  *    * ** *    ***   *  **    ** ** *  *  **** ***   
*  * ** **     *   *   * * *     ** ** *  ****** * *       ** 
* * * ** ** *** *** * ****  
*  * *  ** *   ** **  * * ** *** (a>0);

   ***  *** **   **  *  ** **  ** *** %d",digits,sum);
  *  *** * * **  * *  *** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
***  * ** ** * *  ** 
int main  *  
{
int  ****** *** 
 *    *   **  * ***  ** *   *
 * **   
**  **  *
** * *
**   ** 
** ****
  ***
*  *
****** 
 *** * * * *     * *** * ** *
if ***  **** * * 
**  
else * ** *
*** 
else if *  
*****
else f2=4;
**     *      *  *** *  **
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* ** * **  *   *** * *  *  * n,digits = 0,sum = 0;
*  ***   *  ***** * * ** **  ********   **  * * *   **
    *  *** ** *   *    ****     {
***   *****    ** *  *    ***      **** ***** *****  ** *    = sum + n%10;
*  *  *      * * ** *    *  ***  * *****  *   *****   * * ** * *   
*   *  * * * *******   *** **  **    *   *    *    ** *  *
******  **  **    * * ***  ** * while (n > 0);
**  *    * *******  ***   *  *    * **  *      *    *       * 
******* ** * *  **      **   ** * **   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  **    **   *   ***   ** ****   a=1,b,c,d,e,f,g;
***** *       ** **** * * *  ** *   *  **   ** *** 
*          * * *  * **    *   
 * *  **     ***** *  * ***  **  **** ***
******** *    *    *** *** 
**        *   *   * * *  **  ** 
  * **  *      * *** **  *  *  *
    }
  ** ****** * *        **    *  
  ** * *  **  **    *  ** *  **  *  ****
*** ** *     ** *   *** *  ***  ***** *
 *** * *  **         *****  
** ***    * **         * **   * *  ***** %d %d %d\n",c,d,e,f);
****** *  ** ** *   *    ** ** **** %d",a,c+d+e+f);
   *     **  ***  ******         0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*    ***   * **     ** * *** *  * num,digits,sum=0;
**  **   *  ** *   ***   * * ** ******   *** **   **  ****   **   
*   * **    **** * **** *      ****    *****  *  ***   *** * *    * ***** **   *** &num);
 * *   * ******* * * *  *  ****  **
*** *   * *  * *  **** * *** 
   * * *  * * *****  **    *  * *    * * ****             *   ***      **  += num % 10;
* *   ** ***   ** ****   * *** ******* *     *   * * ***** * * *  **  * *   **  = num / 10;
*      *  **  *  ****  *** * ** ** *  **   **   *  **  **  *    ** *   *** *  **
    }
*    *  **  * **** ** *    *    * * * %d", digits,sum);

** * * **  ***   * **  **  *    * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output