10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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{
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f2=2;
else if * ***
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
* *** ****  ***** ***     ** ** a,b,c,d,e,f;
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    }

**** * **    ****  * * ** **   * *** %d",count,f);
          *  * *    **    * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
* ***  *    * *  * *    **
int main()
{
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* **** *** * * ***    * * **  *  ** **      * * * 
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*  *** **** *  ** ** * **** *  ** while (n > 0);
  *** *  ** * ** **  ** ***  **** ***  * ****  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include ***** ** * ** 

int   *    ** ****** *****       
int d=1000;

int main(){
** *      **  ** ***      *    ** **    **  ***   *
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**  * ** * ** **   *  *****  **  *   **** ** * = a - (currentdigit * d);
* *      *****  ***  * **  * *** * *    *  **** *  * 

*  *  * * *** ***   ** ** *  * *     **  * * *   *** ** **  **  *  %d\n", numdigits, sum);

**   *  * *     *   **   
  **** *  * *   *     *   *       ** * ** * %d", numdigits, sum);
 *  * *   *  * ***   *       * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**  *   * * ***** *** **  **  n,digits = 0,sum = 0;
*  *  ** * * ***  ** **      **  * *  *   ** **  ****  * * *  *
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  **  *   ** *** * * * *  **   *  * ***    * * * *   = sum + n%10;
****** *   *   ** ***** **   **** **** * * * **** * ******  
   **  **     ** *** ***      **********      ** * ** **     *
 *  *  * * ****** **     ** ***  while (n > 0);
** *     ** * * *** *** * **   ***   *  * *** ****    *** **
* ***   ****** *  **  * *  * **  *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
   ** * * *  * ** * *  ** * * a,digits=0,sum=0;
******** * ******   *** *** **  * *** **      *  * ******
  *   * *****   **  ****** *   *   ** {
* *  * **  *  *  * **  *    *   * *   **** ** *    ** ** *
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   **    **           *   * * * * **   ********  **** * 
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* ** **  ** * * * **  *  *  *     * (a>0);

    *  * *  ** ** *   *   ** **  * *  %d",digits,sum);
**** * **  ***    * **** ****** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
* *     *** ** *  ** ** 
int main * *** 
{
int  *    **  * 
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else if  **  
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else f2=4;
** ** * *  *  *   *** *   *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* ** ***  **  ** ** * ******  ***  n,digits = 0,sum = 0;
 * *   **** ****  **       *  * **   * *   *  *   * * *  
* ** **** *** * *    *** *  * * {
* * **   *** ** ******  *  ** * *   ** *** *    *  = sum + n%10;
***  *  ** * **  ***      * * ** *** **   ** **  **  **
 *  *      *** **  *       *   *** ***  **** ** **       
  **    *** **  *    *    * while (n > 0);
 **  *     ***   **     ***  * * * *       * **
 *    ** **     **   ****   * ** **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*** *   ***   *  * *  * *** a=1,b,c,d,e,f,g;
* ** * *     *    * *** ** ***   *  ** * ** * 
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    }
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**  **** * *** ** * * **** *     *   *       %d %d %d\n",c,d,e,f);
 * ** *  * * **  **** *       ***  *** * *  %d",a,c+d+e+f);
   ** * * ** * * *  **  * **** ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*** **     *** * ****** *   **   num,digits,sum=0;
 **  **** *   ** **   * * ** * * *    ***    *  * * ** *   * **   *  *
*  *  ***   *      *** **  **  ** *   * * * * *** *  **     ***   *** * *    * &num);
   ** **** **** *  *** *    **** ** ***
** *  ***** **   * *  
 *  ** ** **   * ***  * **      *        **   *** ****** *  * *   ** **   *  ***    ** ** += num % 10;
  *   ** *****  **  * *   *  * ** *    *  **   *   * **   *****  *   **      ***** = num / 10;
*   ***  *  ** ***  ** ****  ******* ** * *   *   *     * * ** **    **      
    }
** ***  * * *  * *      *   ** **      * * %d", digits,sum);

*       ** *  **** * * ****    ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output