10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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f2=2;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
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int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
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int  **  ***** * *  * ***
int d=1000;

int main(){
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* *** ***** *** **      * *
 ****  *** *  ***** * ****   * **   * * **  %d", numdigits, sum);
    ** *     **   * * *** ** * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 *   *  *   *** *      **     * ** n,digits = 0,sum = 0;
 *** ***     *  *      ** ** **    * ***  ** ** ** * ** 
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*   **  ***    ** * *****    while (n > 0);
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*  *     *****       *****   * *  **  ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 * ** *** ***  ** ******  ** *  * a,digits=0,sum=0;
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*  *  * *** * ** *** *  ****  ***  (a>0);

 *  *   *  ***   *        ***    *  %d",digits,sum);
*** * **** ************* **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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* *  ** **    *** * * 
int main     *
{
int *  ** ***
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
      *  **  **  *********   *  *   n,digits = 0,sum = 0;
***  ***    ** ****  **** * *  * * ** * ** ** *****   **
**** ****   **   **  ** *   *   {
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* * * * * **   *     ***   ****   ** * * * * **** *   ****   *
* * ****  ** *** * *** **    *  while (n > 0);
 *****  ****  **  *  * ** ** * *** * **  *** **      
 * ***  * ***  **** ** *** *** *  *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 * *  *** * ** * ***         * a=1,b,c,d,e,f,g;
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**   *   **   ****   *  ***  * *****  * * *  ** %d",a,c+d+e+f);
 ** ***   **  *  **   **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*** **   * ** **  *  ** *  *  ** ** num,digits,sum=0;
*   **     *  *  **   *  *   ***** *  *  **  *****   ** **    * ***** * 
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*   ** *    **   * ***     **  **   * * *  *     ** *    * *** * = num / 10;
** *  ** *   *      * ** **** ** * ** ** * *  * *     ** ** **   ** * *   ** ***  * 
    }
 *  ** *  * *   **  *      ****   ** ** %d", digits,sum);

***** * ***     * *  *      * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output