10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
 * * ** **  *    *
int main (void)
{
int ***  *  **
*   * * ** *  **  **** **   *
  *** 
*** * *   
 ***  
***  **
 *   *
 **  *  *
*  
** * *
* * * ***** *** *   * * ***    ** *** 
if  **   **   * *  ** **  ******** * *
***
else * * ** ** *     ***
f2=2;
else if  ** 
** 
else f2=4;
 **  ** * *    * *** ***  *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
***    ****  *** *  ******    a,b,c,d,e,f;
  ** **** * * * * *  ** * **   count=1;
    ** **  * ****     *  *** *****  ***   ***    *  **    
 **  ** ** * *    *    *   *  * 
  * ***** * * * *** **  * * * * *  
   *   **    **   * * * *   * ***  * ** *  *    
*** ***  ***     ****      *** **  ******* * ****
  * *    *    *   *   *   **       **  * 
*  * * *   * **  * ****   *  *   *** * 
    {
*  *  * **  *  *        ****  *  *   * *  *     ****  ***     *
* *    *     *** ** **   * **  * *  ****  *  **  * **  * **  *  
    }

** ******  *   **  *    ***** ** *   ** %d",count,f);
    * * *********  ** * **     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*   * **     * *** *  * 
int main()
{
 ** *  *  ****   ***  * *** ** *   n,digits = 0,sum = 0;
   **   *   *  **  **  *  * *   ** *  *** *     * *****
* **  * * ** ****** * *  *  * * {
* * * *    *    *    *     *     * **  *     ***     *  *  *  = sum + n%10;
  * * * ***  * **   * **  ** **** ** **  *****  *   *   *
 **** *  **  * *** **** *  *****  *****  **  *** *  * *   ** * 
*  *   *    **  **  *   * while (n > 0);
 * * * * * **  * * ***** * ** **** ** ***  * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include    **   ** ** **

int  *** *** * ****** ****
int d=1000;

int main(){
    * *  * * * *   **    *  * *********  *** * *** 
** *   *** **** * ***  * **   ** ****  * *  ***

* **** ****    **  ** ***     **   ******  *  * **  *  ***** ** = a/d;
  *  *  ******  ** * ****** ** **  *  ******   * *    *     *    **   *  *   *  ****   ** **
* * *  **  *  ***  * ***  *** ** **** ******  ****  * *    = sum + currentdigit;
  *     *    * * *** * *** *  *  *      * **   ** ***  *  = a - (currentdigit * d);
  *  ** * * ***   *  **  ** **      *          ** *  ****** * **

**** ** * **      *  * *   ***   ** ****** ***  * * ***** *** *   **** %d\n", numdigits, sum);

  * *  ***  *** * *      **
**  ***  *   * **  * *****  * * * ***  %d", numdigits, sum);
*   *  *   * ***  ** * * *   *** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
** **  * * **  ** *  **  ** n,digits = 0,sum = 0;
 ** ******  *** * **  *   **     **** ****     * ***** 
   * ****   *** **    ***    {
**   * *  ***   ***  ****  * *   **    * * ****  *****   = sum + n%10;
*   *   ** *     * ** *  *****  **  *     *  *** ** ***
  *  * **  ***** ** ***** ** ***      *   *  * ****   *    *  
** *  * * **   ** **  ***   *   while (n > 0);
 * **  *  **** * ******    ****  *  ** *    *    ** **
*  * * ** *  *  * **  ******    *  *   *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  ** * * * *   * ** * ***  *    *  a,digits=0,sum=0;
  *** ** **   ***    ** * *  **   ** **  ***** ***  ***** *
* ***   * ******* *     **  * {
 **  **  ***  *  *   ***** * *** *   ** ******* ****  *   *  **  **
 **    *****   ** ** * * * *  ****  **   *** * ****   **  *
 *   * *  **  *   *****  ** *** **    ***   * *  ** ****  * 
  **       ** ***     **** 
** *** *  *  **** *     ***  * (a>0);

* * *** *********  ***  * ** *   *** * *   %d",digits,sum);
 ****  ** *  **   *** *****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
* ***   * **   *  * 
int main   
{
int *  *  **
  *** * *  * ** * * * ****  * 
 *   * 
** * ******
**   *
  **  * **
* ****
****
 *** 
* *   *
 **** **   *  ** * *  *** *** * *  *
if *  *  
 ** *
else ***    
** 
else if *   
*   
else f2=4;
*   ** *  **   * *    * *  *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 * * *  ** *   *  * * **  n,digits = 0,sum = 0;
* *********  *     **  * *** * ***   **     **   * **    *  
 *   * **** ******** * * * {
*   * *******  **** **** * **  * ***  *    * ** *** = sum + n%10;
***   ** * ** * * * *    *      *  * *  *****  ** * ***   
* **  ** * ******* **    *  ***  *** ***  *   *   *   
 ** **   ** ***     ** ** *   while (n > 0);
 * ** ** *  ***** *  *  **  *  ***  *  * ** *
******   * **   **  **** ***   ** * * **** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
* *   ****  *  *   ** *  * ****   a=1,b,c,d,e,f,g;
****  *  * **  * * **   * *  **   *  *      ** ** ****** *
* * *** ** * *  ****   *   ****
 ***  ***  *  *******  **  * ** *** *   ** 
*  *** * ** * ***   
***  ***  ***** *     *** * ***
*** *  **   ** ** *  **  * **** 
    }
   *** **   * ***  **    ** * *     *  *
****  * * ***    **  ***** *   * *  *
 * *  *** *  * *    *** *** * **  
    *  * *** *** * ***
* ** * ****   * *****    *   **    *    %d %d %d\n",c,d,e,f);
  **  **  * *  ****     *   **** **  * %d",a,c+d+e+f);
 ** * *  ***   *    *****  ****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  **** *   *  * *  ****  ****  *   num,digits,sum=0;
*      *       *     *   **** ***    * *  **    **** *    **  *  
  ***     **    *  * *    * ** * ****     *  * ** ***   ** * * ***** &num);
* **  ****  * **  **   **  * **     *   * **
* ***      ***  * *  **   *** *
** **   ****  *** **** * *  * * ** * *  *   * ** * *********** ** ** ** * *  += num % 10;
  *  * *****  *  *** * * **    * *  * *   ****  *  ******* *  ** * ** ** ****  = num / 10;
 *  ** * ****** * *  ******** *   * *** **    * *  *  ***   *     **  ** *** *
    }
  * ** *    ** **    *    ** *  ** %d", digits,sum);

**   * * * ***  ** *******     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output