10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
 *  *  **** ***    *
int main (void)
{
int *** ***  *  
 *   **     *****  * *  
*  * ***
** *  
****** 
 *    
* **
 ** * *
** * 
  ** *
*  **    *  *** ***  ** *  * ** **   **  *
if *  * *  ***  **   **** ** *  ** * 
    
else   ******  * **   *
f2=2;
else if  * 
* **
else f2=4;
**  ** *    * ***** ***** 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
** *  * *  **      ***** * * ** *** a,b,c,d,e,f;
 *  *   *****  **** **  * * *  count=1;
**    *  ******* ** * ***  **    **  *  ***      *  *  
**  ** * **  *****    ** ** **  
  * *  **    **  ** *  **  * ***  * *
  **  **** * ******   ** * * *  * **  
* * ***  ***  * *  **   ** *   ** * * * **   * * *  
   * * * *  **    *  ***   * **  *
*   ***** *  * ** ** * *  * *     * ***   *
    {
 * *   ** *****  *   * *** **  ****    * ***   * * * ***   * 
  *  *****     *   *   ** **  *  **** *  ***** * **** 
    }

  ***     * *      **** ***     *   ***     %d",count,f);
*   * ***** **    *      *  **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
  ****  * ** * ***  
int main()
{
* ** *** * *  *  *  ****** *  n,digits = 0,sum = 0;
 *  *  *****    * ** *  *  *   *   * *** **  *  *   * **
* * *  ****   * * *    ** {
* ** * ** * **  *   *  *  ** ***   **   *     **  **  * ***  = sum + n%10;
    * *  ** *    *    ***  ** *    * ****** * * *  *  ******
 **         *** *** **   * *    **    *** **  *  ****** *  * ***
* **  * **   *  *** *  ** **  * while (n > 0);
 *   **  **   * ** *** *** * * *          *** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include * * * ** *     *

int     ***** ***  
int d=1000;

int main(){
  *  * ******  *  *   * *     *****  ****  ** *   ****
 *****   *** *  *  *  * ***     * * ***  * *

 *  **   ***     **       ** *      * ** ** **    ******** ** = a/d;
******    ***   *  *    ***  **  *** *  ** * ** * *    ** * **  * ** * * * * ** *  *  *  * **       *
** *** * **  ** ****  ** * ***      * *   **** *  *   ** = sum + currentdigit;
*      **** ***** *******  ****  * ** ** *   ** = a - (currentdigit * d);
**    *    ** ****   * *** *   ***    *   * *    ******  **** 

 ** * * ** *****    **   **** **      *****  *** ** *   *  * * *  *** ** %d\n", numdigits, sum);

* * ***  *   *  *** *  * * *    
        ***   ** *  * ** * *      *  * **  * %d", numdigits, sum);
*    *  **  *   **** *   **  *   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**** *     * *  *** ****** *  * * n,digits = 0,sum = 0;
  ***  **** *** **   ** *      ***** ****  ** *     *****  
*** ****  **   **    *  ** *  {
* ***  * **  *  * ***  ******    * * * *   **  **  * = sum + n%10;
 *  *       ** **  * **  *    ***    *   ** *   
   ***   ********* *    **  * * *** *  **    * **  *** * * 
   ** **   ***   ** *  ******  while (n > 0);
 * ******  ** *****   **  * *    ******* ***  *** 
       ****   * *** * *    ** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 ****  ** *  ** ** ***   ** **  a,digits=0,sum=0;
**       *** *  **  ***         *  ** *****  *** *  ** 
**  * *****     ***** *   {
  * **  ** * ***  ** ***  *      *  ** * *  * ** **       *
* ***  ****  * *  *   * ** **** *  * ***** **  * ****    
    *  *  ****  *   *  *   **   *** *   * * *  *  ** *  
 * * * *  ** *** **  **   *
*********    *** * ** *****  (a>0);

* ** * * * *****     ****     ** %d",digits,sum);
***  ***  ** * *  *  **   *** * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
       *    *** * *
int main **  
{
int * * *    * 
**    * *** * * ** *   ****
*  
 **   *
**  * ** 
  * *  *
    * 
* *    
** * 
 **    **
* *****        * **  **** **** * 
if *      *
 *  
else *** ** ** 
 * ***
else if *  
 **
else f2=4;
**** ** * ***     *  *    ** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*** *    ****  **     **   *    n,digits = 0,sum = 0;
 ** *     * **   **** * * *** *  ***    ****    ***  *
    * **  *** **  ** **  ****  {
** * *    * ***   *  * * *    * **   *** * *********     = sum + n%10;
 *** ** * *** *  *  ********** * *  *  **  *  *** * * **** * 
  * ****  * *    *  ***      *******     * ** **  ***   ***  
** **** *     **  ** **  **    while (n > 0);
***** *  * ****** *  *  * ** *** *  *   *    ******* *  **  
*   *  *****   * **  **  * *  **** ** ** ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 **  ** *****       **  * * ** a=1,b,c,d,e,f,g;
* **  ****** *  *  *    * * *    ** ** *****    ** **   *
 *  * * ***  *  *** ** * * * ** *****
   *    **   **  **   *   *    ** *     ** *
     * ***    ***** *** ***
 *   * ***   ******  *   **   
  ****  *      **  ** * ** ** 
    }
  *  ** *  *  ** ** ****** *** **  
  *********    * *****    * *   ** * *  
 *   ****   *   ****** ** *   **
  **   ***   * * ***** *  
   *   **  **** * * ******* *  *  *  ***  ***   %d %d %d\n",c,d,e,f);
*   * ** *   **** **   ***   *       %d",a,c+d+e+f);
* * *  *** *   *  ****    ** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* * * * * ***      **  * **** * * ** num,digits,sum=0;
 ****   * **  *      * *   *  **** *** *  *   *  * ** ******* * * **** * 
*  **  **  * * *   * **   *  *** * *****       *    *     **  * * ****   ***   &num);
 *** ***** *  * *    * **  *** **   *
* * **   * **  ** * ** *  ***
  **  ***   * *  ** * *      **   *    **   * * *   *****   ** **  ** *  ** *  **** += num % 10;
** ** ** **   *    ** *   * * ******  ** ** ****     ****   *******  *  *** = num / 10;
*** **  ***** * *  ***** * ***  * ***   **** **  * * ** **            **   
    }
 *** ***  ******** * ******   *       *   %d", digits,sum);

* **      **** *  ****  ***** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output