10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
*    *  ***  *******  
int main (void)
{
int *** ** *  *
   *   * *  *   *     **  * ***  
* ** *
  *     
     
 *****  
*  * 
*   *** 
** *
** * * * 
   *** ******** *  *  *    * ** * 
if **** ** *** *   *  * ** * **   * 
*** *
else * * **   *** ** *
f2=2;
else if   ***
   ** 
else f2=4;
* ***    **  ****    * * ***
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
** *   * ***    *   ** *       a,b,c,d,e,f;
  * ****  ** * * ** *   ** count=1;
***     ** *      **  **   *  * *  * *** ***  **
 *** *  **  *   *    **   ** * 
*** *  *  **    *  *  *    **** *     
  ** *  ****** ***        ******  ***    
*  *** **  *** **  *   ***** * *  ** ** ******  **** 
  *   *  * **   ** **   * **    * 
    **   ***       * **** * *   * ** *  * 
    {
  * **** *** ** *** *  * *      ***** *  *  **    **** **  
   *** **** **  **   *   ** * ** * **    * **  * * * *** *
    }

*  ** * *    **** ** *** * ** * * * * %d",count,f);
   *** *  ** ***  * *  ** *    *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 * **      *  ***  * *  
int main()
{
 ****  ** *****  * ** *** ** n,digits = 0,sum = 0;
**      **     **  * *    *** ***** ** ** **  *  * *
*** * * *** *  *  *    ***  **  * {
* * * *** **    * *   *  * *** ** * ** * * *** ** *** **    = sum + n%10;
*** * * * *   * *   *  ***     * *   ** * *  **** * **
****** *  *** ***   ***   ***  ***   **     **    **   **   *  *
  *** **** **  ** ** *  * * * while (n > 0);
***     *      * * ******   * **** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include ** *   *  ***

int  ***** *   ** *    ** *****
int d=1000;

int main(){
* **  * * **      *    ** *  * ******  *****      * ****   
 **     *** * **  ** ** *  **** *  * *  ** * 

  *  ******    ****  ***  ************  **** * ********       = a/d;
  * **  ***   ** ** ** * **      * *      * *  ** ** *  *       ** ***** *      ***** *  **     *
  ******** *  *     * *   *****   * **  *** * * *   * *     * = sum + currentdigit;
 ** *****  ***   * *   ***   **     **  *  * *  ******  *  = a - (currentdigit * d);
 ****  **     **  **     * **  *    **** *   * *** 

    ****  *  *  * *****  *  *    **  *  ** *    ** ** * *  * *** * * * %d\n", numdigits, sum);

 *  * * *    **    **** **  
   **  ***   *    **** *  * *  **** %d", numdigits, sum);
*** * **** * **     ** *  *   *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*   **  **** *****   **  * ** * n,digits = 0,sum = 0;
*     *****    *     ***  ** *     *  *   *      
* ** ** *** ***        * ** {
 * **  *        * *      *   ** * * ** **  **    **     = sum + n%10;
** *    *    ***   **  *  **  * * *   ***** *   **  *   * 
*  ***  * * * * *  *** *   * **    **  ***  *** **   *** ** 
   *        ***  **  ** ***** * while (n > 0);
* *  **  ***** ** *      *   *** **  *  *  ** ***  
***** *** ***   ** ***  **   **    d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
    **  ** ***** * *  *        a,digits=0,sum=0;
***      ***  **     * ** **    **  * *****  *  *  * *
 *    ** *** ** *    ****   ** * {
  ***    **  ****        ** ** *  * *** ** **** * ** ********
* *** *****  *     *  * *      ***  ** ** *** *  ** **  * * * *
 * * *  * ****    *   *   * *** **  *** * ********   ***
 *  *  **** ***   *  ****  *
 * *    * *     ***  * *  ** (a>0);

**     **  * **** *   * *  *    ** **   %d",digits,sum);
**** **  ** **  ***  **  *   *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
***      *    *   ***
int main * **
{
int * **** ** **
    *  *****  **   * *  
  *** * *
 ***** 
* **
*  *** 
*** * 
*** *  
** * *
** *  
** * ** * **** * ** * *     **
if * * **    * 
 *
else   * ** 
  **
else if   *
* 
else f2=4;
  ** * **   ***   *   * *   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*  ** **** *  *   * * ** ***  n,digits = 0,sum = 0;
 ** *  **   **    ******* **   ** **    *  ** * * *   *
** **  ** * *** * ****  {
  *** ***  **   *  *   ***** * *      ***  ****       * * = sum + n%10;
*  ** * ******  ***  * *****        *   *** *****  * 
 *     * *  ** *   ***  **  *  **  *  * ****   * *** * * 
 ***  * ******* * * *  ** ** while (n > 0);
******   *  *  * *       **   ***  *****  * *  *  *********
**** *** * ***     ***     *  *    *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  * * ****   **  ** * *   **  a=1,b,c,d,e,f,g;
  * * ** * * ****  ***  *   *****  ** *****    *  ** ** ****** * 
** * *** ** **   * ***   ** ** **
****   * * *   *       *    *     * ** *   *
 *  *  *   ***** * * *    **
****  * * **  *** *   ***** *   
 *  * ** **     ***   *  *  *  
    }
 **  * *  *  *  ***  * ** ***
  **   **** *** * * *   ** * *  *** ***
  ***  *** *  * * *  * * **   **** *
   *  ***  ** **  ***  * 
* ***   **    *   **  *  **  **  *    *   %d %d %d\n",c,d,e,f);
  * ** *   **  **  *   *** * ***  **  **  ** %d",a,c+d+e+f);
* *   * * **  *    * *  ** * * *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
    ****  ******  ** *  * *  **     *   num,digits,sum=0;
     ***  * ** *     *   *  *  ****  * ** ** *** *****   **  * * 
***   *****  * ***   ***   **   * * *  ** ** *** *    **  **   *    &num);
***   *      **** ***     ****   *  * ***** 
 * **   ****   * ****  *   * 
**  *  * ****  *  ***** ****  *  * ***     * *  ***  * *** *   * **** **  += num % 10;
 ** * **** ***  * *    **   *   *  *** * *  **** ****  *    ******  ***   *** = num / 10;
 ******  * **  ** *** *  ** *   **  ** ***** * * **  ** *** **  * * *** *    *  *  
    }
***  ******** **   *   **   * *  *     %d", digits,sum);

* **  *****   ** *  ***  * **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output