10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
** *  *** ** *  ***   ****
int main (void)
{
int  ******   *  
 **   ****     *  ** **  ***  
    **
*   ****
*    * 
*   ** 
*  
  * **
 ***
 *   * 
*       *** * ***** **    *  *   * *
if * * *** ****  * **   *   ***  *    
**  
else ** * * ** ****      
f2=2;
else if * * 
* 
else f2=4;
* **  ***      * **** *  **
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 ***    *  * * ** * **   *  **  a,b,c,d,e,f;
* ** ** * *  *** **  * *  count=1;
*  *  * ****  * *** *  *  ***   ** * **** **** * **   *
*  *** **    *****    ** 
**  **** *        *  ***     * * * *  
* *** *   ***    **  *** *** *** * ****  **  
* * *****  * **    *   ** ** **         * ***
******* **    **      ****** *  *
*** ***       **** *   *     ** *  * *  
    {
 * *  * **  **    ** **     ** ** ********* * ***  ***   **** * *
   *    *  *  ***  *   **   *  ** ** *  * * ** *  *
    }

 *****      ** * ** ** ****    ** *   %d",count,f);
 *  * *** *  *   * *  **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*  * ** **  * *** *
int main()
{
  *  **  *** * *     ***  *  n,digits = 0,sum = 0;
*  ** * * ** ***** * *  *   *** * * *   *****  ***  *
   ******* **   ** **   {
       * ** *   * *****   ** **  *** ***** **     ****** = sum + n%10;
** *  *   *    **** **       * ***  ** ****  ****      ***  
  * * * ** **** **   ******  ***   *   **  ****** **  * * *
**  * * * *  **   *   **  *** while (n > 0);
** *  * *  ****    *    ********* ****** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include  **         ***

int **** *  ** ** * *  
int d=1000;

int main(){
  * *****   *** *    *   **   *   *  * * ***  ** * *
*  **** ***  * **  *** **  ***  * *** **

   ***    *   ** *  ***     **  ***** ****  ** *  ** ** * = a/d;
 ****   **  **  ***** * *** ** **  **  *     ***    ** * *  *       **** **  *** *   *** **
***   * * **  * ******  ** * * * ** * * *   **** * *  ***   = sum + currentdigit;
* **    * *   ** **  * ** * ***   *     **   ** = a - (currentdigit * d);
   * *** ** *  **  ** ** *  *** * *   ** **   *   * *  

  *** * *    *    **    *  *   *  ***   **  *     ****  **  ****   ** *   %d\n", numdigits, sum);

 * **  * ** * * **** ****** 
** *   **  **** **   *     *** *   ****** %d", numdigits, sum);
  **   *   *  ** * **** *  * *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*   * *   * **   **  **   ***** n,digits = 0,sum = 0;
*** * **   * * *  ** **  *   * * *   *
    *  *** *  * *  *   ***   {
 **  * ***  **  ****     **  * ** *** **  ******* ***    * = sum + n%10;
*** * **  **  * * *** *  **   * *****       ** *   **  *** ***
*  ******* *    **** ******  * * ****   * **   **  ** 
 *****  * **  * ** ** ** * while (n > 0);
  *******   ** *  **    ***    ***  *** * **   * ** *
  *  **  ***  *   **    *** ***** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
**   * * **   *****  a,digits=0,sum=0;
*   *          *  ***    *  ***  ** *** *  ***  ******  *
  *******   *  *  * ** **** *  {
*  **** ** ** * *  ** ** ***  *     **      * * **  ** **  
 ***      ******** *    ******  * *    *  *  *    ***** *    
    **** **** * ** *   **** * *  * * * * * ** * **  * * 
 *** *  **** ***   **** ***   **  
** *** ****     *   * *  *** *     (a>0);

*  * *** *  ******     ** *  *****   * * * ** %d",digits,sum);
  *   * *    *** *  * **  ***    * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 *    * ** * *  * *
int main ** 
{
int  ** *   *
***       ** * *      ** * ** 
*    
    ** *
*****   *
   *  *
* ***
  *  ***
    
      *
  *    *  ** * ** **** * * * * 
if  **** * * *
* ** 
else **** ***
 *  
else if  ***
*    
else f2=4;
**  ***   * *  *    **      ** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 *        ********    *    n,digits = 0,sum = 0;
* *** ** *  *   **   * * **** ** *   **  ** * ****   * 
*  * * *****  **  * *   *** *   {
 **     *   *    **  * ***** * *** * * **   *   *   * *   = sum + n%10;
*  *** **** **  ***** *  *  **** * ** **** * *** *    ****    
** **   *  **        *** **** ***  * * ** ** *** **   *   **  * 
*   *** *  *** ***** * **   while (n > 0);
**     *  ***** *****   ***   **** *    *** ** **    *  
     ******* * **   *  * ****** * * ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 **** *  ** * * ** **  *  **   * a=1,b,c,d,e,f,g;
*** * *   ** ****  * * ** * ** ***  * ***  *   * ********   *   ******
  *  * * *   ***         *  *** *
 *** *   ** ***  * *****  *  ** * *  * 
  *** ** ** ** ***   ***** * 
 ***  ** * *** *** *  * * ** *
** **   * ** **  ** * *   * **  
    }
 *** ** * * *  * ****** * *  *
 * * *** ** * *      *********  *
  *** *****     ** * *** * ** ***  ***
*  * **  *  *   ******  * *  * *  *
*   *  ** **  **   * *    * *       *  %d %d %d\n",c,d,e,f);
*  * ** ** * ** **   *   **** **  *  ** %d",a,c+d+e+f);
**     *  * * * *  *  *  *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
     * ***      *  ** **  *    num,digits,sum=0;
***           *  *  * * ** ***  * **** **   ** ******     * *  *
 *****************    **  * **  * *   * *  * **  **** ** * *  *   ***  **  * &num);
  *    **********  *       *** ** ***   *
* *       ** *    *  ** 
**** *    **  ** **   **     ****   * * ** ****  **  * ********* *   ** *   += num % 10;
 **** ****  *****   * **** * *    * **   ** * ***  * ** * ***  ** **    *   **** = num / 10;
   **   *  *  **  **  **** * * **  * * ** *  *   **    * **  **** **  **  
    }
 ** *    * ***** ** * **  *  * ** * * * * *** %d", digits,sum);

 *   * * *  ** ** *****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output