10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
** * * * ***** * ****
int main (void)
{
int   * ****** 
*      *   **   **   * **
* *     
* * ***   
***** 
 ****  * 
  *  
* **  *
**   
*** *
**    **  **  * * * ** ** * * 
if   ** **  * **   ***   * **    *** *
  * 
else   *** ** **  ** ****
f2=2;
else if * **
*
else f2=4;
*    * *  **  *   *  *** * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 *  *  *** ****   * *** **   a,b,c,d,e,f;
    *     **  ** **    **   ***   count=1;
** * **** ** * ******   *  * ** * *  ** *   *   ***   ***
*        *    * ** ****  ** * ***  * *
 **  *  *** * ***** * ** * *    *       
*  *  **** *   *  *  ***  * ***   **  * * * ****
** ****   * **  **  **   * ***  *  ** **** **   * **
**  * *** *** *  **   **   *  
 **  ***   * ***  ****  * *  *  * *    * 
    {
 * * *  * *** *    *** *  *  * **  *  *  **** * * **
   ****     *  * *     **   ** * *   * **   ** ***  *  *      **** * *** 
    }

**       ****  * **  **      **** *  %d",count,f);
 *     ** *** ** *  ***  ****  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
* * ** *   *** * * **** 
int main()
{
  *** *       * ***** ** * * **  n,digits = 0,sum = 0;
* ** * ** **  * *  ***** ****    *    ***    ***
**  *  ** **    *** **** {
  *   *  ***    **  ***** **  ** * *     **    ***  ***  = sum + n%10;
**** * **  * * ** **   ** *  *        *  *** * * * *  *   
*    ** **  *   **** *  *  **  *     ** * ***   * **    *  * *  ***
 * *  *  ** ** *    *  **  **   while (n > 0);
  * *    ****     **  *** *  *  *       d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include      **** ** *  ** 

int *   *  * *****    * * ** 
int d=1000;

int main(){
***    *  ** *   *  *    * *  *** * *    *  ** *   
**** *  * *   * *  * * * * *   *    **  *  * 

  ***** ** *  ** ******** ** * *   ******    *** *   *  **   = a/d;
* ** *  * *  * *     *   * *   *   *  ***  ***    **   *** ***  * *  *  *** * *  * *   
  * **** * **   ****  **  *   * ** *  ** ** **    * = sum + currentdigit;
** *  ** *** **** *   **** ******* **  *   = a - (currentdigit * d);
     ******* *  * *   *** * *      ***  ** **  * *   * ***   

 *** **  * * ***  ** ***       * * * *    *  * * *   ** *      ***** %d\n", numdigits, sum);

*   *  ** * *** *  ******  *
****   ** *  *** ***** *  **** ***   %d", numdigits, sum);
  ***   **   * **    ********  ** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 * ** **** *     **    * * * ** * n,digits = 0,sum = 0;
 **   *  *      **   *  *     * **   **  * *****    *
  **  * *** **     * *     * {
 ** **    * *** *    *** *    ** *    * * **  **  * * ** = sum + n%10;
** **  * *        **  ** *   * ** ** *  *  **** ** *  *
   * * ***     **  *   **        * *  ***  *  * ***    ** *
    * **** *  **  ***   * * * while (n > 0);
***  **  *   **    ** *  *   ********   * **** 
* *   * *  ** **  ****  *  *** **  **** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 *  *  *    *****   ** * * * * a,digits=0,sum=0;
****** *  * *******   * *** **  *     *** * * *  *  ** ** 
 *    * *****  * *  ***    {
* ** *     * **  ***   ****  * * *   ** * * *   *****    **
  *  **  *   *   **   **   *** * ***   ** ** * **    *  
** *  * *  *  ***  * *  ****** ** *  *******    * ** ** ***  *
  ****** ****  ** *      * **
*   *** *       *  *  * ***** (a>0);

*  **      * **   ****  ** **   ***** %d",digits,sum);
** ***   ** ** *   ****** ** **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*****  * *   **  *
int main   
{
int  *  ***   *
 *** * **   ** *    *  **   * *
 *** *  
   * ***
 * **** 
 *    
      
  *  * * 
*  * * 
** **  ** 
   * *  *  * * *    ** *  * * *    * 
if   * * *  * 
** *
else * ***   
***
else if * *
 * *
else f2=4;
 ** *   **  * **  *   *  ** * *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
  **  **   ** **** **    **** n,digits = 0,sum = 0;
* * ***** ***  *  **** ***  *  * ** * *** *      *   *  ** 
 * * * *     ** **     * ** **  {
** **** **  *  *  *      * ***  ***   **** *****  *    **   = sum + n%10;
* *  *   ****  *   * * * * **  ***   *    ** **** * **  
   ** * * * *  *  * *  *** *   ***** *  * *    * * ****     ***
 *   *  *   ** *    *  ***    while (n > 0);
 ***** * *  *        *** **  *  *** *    ******   *
** *    * * * **** ***       **   **  * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  * *  * * ** **   * * *  * a=1,b,c,d,e,f,g;
***  *   * * ** ****  *  **** *** **** ** * **     * * 
     *    ** ** ****    * ***
 * *** *   ** *  * ****  **  *  * ** *  **** 
  *  **    *  ** **   *   * **
* * * **** *****  * *      **
      **  *   **      ***
    }
   *  *  **  *  **  * ** * * **** 
    * * ***** * *   *  ** **   ****  * 
 *  **    *  *   **   ***  * **  *    * * 
**** * **   ****  * * *   ** *
*** *** *** *    *** ** * ** **   *   * %d %d %d\n",c,d,e,f);
   ** ***  ** ** * ***** * * **** * * %d",a,c+d+e+f);
 **** * ** *  *    **  *  * * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*   ******  * * ******* ** * ** * *****  num,digits,sum=0;
 ****** ***  ****  *  ***  *****   **  **  * * ** ***  * * * * * * 
  ** * * ** ***** * *   *  * ***    * *  **   ** *   *     **    * **** ***    * *** ***  &num);
* **  *  * *** **** ** ** *   ***  *  
*** *** ** * *  * *     ***
* *** ***    ** *  * *** *      ****  *  * *   **       *  *****    *  *   += num % 10;
*  *****  * * *  *** ***   **** *  *****  *   **  ****   ****** ** *******  *  = num / 10;
** *  ***** * *      ******** **** * * * *  *  * ******* * ** *  *  ***  *
    }
* *** * ******    * **  * * * ** * **** %d", digits,sum);

***    *  ** * **********     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output