10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
* *   **  * *** * * * 
int main (void)
{
int    *** **
*******  * ** *  ** * *  **** **
*  ***
* *   * 
* **  
* *     *
**  ***
  * *   
    * 
  ** 
 *  ***  ** **  **** *****  *  ** *   
if **   ** *  **  ** ****   *** ******
 ****
else *   * *  ******  ***
f2=2;
else if  * **
 * * 
else f2=4;
 ** *       ****** *****  
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
    *    **    ****** * a,b,c,d,e,f;
** * **  *** *   ***  *  * count=1;
*    ** *** ***  ** * *   *  *  * * *  ****   *     * *    
    * ** *  ** **    *****  *** 
**       ***** ***  *  **** ****   **   *  * *
*  ** **   *  ** * *   **   *          
*  ** ** ***** ****    ***  *   ****   * ** ****
     ****  *   *  **   ***** *** * * 
* **  ** ** ***  ** **** ******* 
    {
 *  * **       **     * **     * ** **   *** * ***  *** *** 
**   **  ***   * *    ** ****  ****   **   *  * **  *  ***  **
    }

   *    ** *   *  * **  *    %d",count,f);
  * **** *      *  *     *  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
**** * *        ***** 
int main()
{
 *  *  * **** **  **   **  **  n,digits = 0,sum = 0;
  *   ** * **  **   *   *  *    ** ** ** **** *    
**** *  * **   **   *   ** * **** {
 *** **    *         **** * *     * *   *  **** **    = sum + n%10;
**   * **     *  * * *  *     * *    **   *  ** ** *  *  * *
****  ***    ***  * * ** ** *******   * * * *  ***  *  ****
*  **   * * *  *  * ****  * * while (n > 0);
** *   ***** * *** * * * *****    ***  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **  * *     *   ** 

int  **   ***  * ***** * 
int d=1000;

int main(){
******  **   *  ***  **  * **   *** *** ** **    
    * **  ** ***  ****** ** ** * **  **  

 *    **  **     * ** *     *  * *   ***   *  *     ***  = a/d;
** ** *  ***  *** ** ***  ***    * *   ** ** **         **  *  **** **      ** *  *     * ** 
  *  * ** ***  ** *   **** ** * **  *       * ****** ****   = sum + currentdigit;
** **   * * ***  **  *  *   ***   * * * * **   **    *  ** = a - (currentdigit * d);
*         * **    ***  * ***  **    ****  * ** * * ** *

***   ***    ** * *  * * **  * * * * ****    * * * *  ***  * ***  * %d\n", numdigits, sum);

* ** ****     ** * ** ** * **
** * ****  *** *     *** *******       *  %d", numdigits, sum);
   ** *****         **        **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  *  *** * *   **  **     ***  *   n,digits = 0,sum = 0;
****  **  *  ****  * ** *   ** *     *    * ****** *** *   
 *  ********** * * *  *  *  {
 ***          ***  *   ** ** * * *   * *    ****  *  * ** = sum + n%10;
  *** *   ******    * **   * ** ** * **  *** * ** *  *  *
 *  * ** ****  ***    ** *   **   *   *      * **  * **  * ******* **  *
**   **  ** *  **   ** ** *  * while (n > 0);
   * *** *  **   ************** **    * * ** ***** 
  * * * *  ***  * * * * ****     **  * **   *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 ** ** ***    *       * ** ***** a,digits=0,sum=0;
*  * *  *  **    ***      *** *****    ***     * **  * 
  * * *  * *** ** * **  * * {
     ** **** **** ******  *  ***  *   * *  * *  * *   * * *  **
     * * ** * * * ** ** *** ** ****  ****  ***   
*  ***  * **    ** *   ** * * ** **   * **  ** *  *  **  ***  * 
*  * ** *  * ** *  *    * * *
   *** *    **      ** * *** * * *  (a>0);

 ** * * *** * *  ** ** * * *   *  ****  * %d",digits,sum);
 **    *   * *   **  *  *   * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
  * ** * **    *  
int main   * 
{
int ***  ** 
  *** ** *** **  ****** **  
 *  *****
  * **  * 
*  ** *
  *****
**   
 *** 
 *    
*** *
*  **   *   *** *  *****   **** *****  *
if  * ** ***      
*** 
else *  *  ** 
*  *
else if **   
     *
else f2=4;
** **  ** *   *    **   **** **
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*** ** *** * * ** * **   **** n,digits = 0,sum = 0;
* * *     * *  ****  **   *   ****   ** **  **  * * * * * **
* * * *  ***  ** **** *   *   {
  *** * ** **     * ***     **** *   ***  **   *  * ****  * * = sum + n%10;
**   ** *  ** *     *    **** ** ***    * * * *   **   **  * 
**  ** * * *** ** * **** *** *** **   ** *    ****      *** * *
  ** *  * **** ***** *  while (n > 0);
   ***   ********** * *  *   **   * *  *     ** **   * 
     ****  *   * ** * * ******   * * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**  **  * *  ** * *** **   a=1,b,c,d,e,f,g;
 ***** ***         *  *  *  **   *   *    ****     * *
* **   ***   * *  *  ***   * *
   *** ****    * ** *   **   ** ** * 
**  **     * *     *****  ** 
  ** *  ****  **  *** *    **  *
* * *  ** ****** * ** *   *  * 
    }
   ** * *  *   *** *      *  * 
****  ***  ******* *    **  *  *  * *** *
*** *** ***  ** **  *** * ****  ***   
 *   *** *** **** * **** * **    **
* **** *     * * * * *  *  *   ** * * ** *  %d %d %d\n",c,d,e,f);
 * *****  * *   * *** * *    *   *   * ***  %d",a,c+d+e+f);
  **     ***  *  * *    ****   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 **   *       * ***    *** ** **    num,digits,sum=0;
** * * **  ***** * *  ***    *  ***  * *  **  * *   ***       * *
 * * **    * *** ***  *  *** * * *  *    *  * **    *** *  **  * ****** **  &num);
* *  *  *****  **  ** *  ** *   *  *  ***** 
   ** * *    *  **   ** ** * **
*   * ******  *   *  ***  ***  **** ****  * **    *****  **** ** *  **  ** += num % 10;
  * ***    *** ****** * * * ***** *** * * * *   ****** ** *   *****  ** ** * = num / 10;
 *******  *    ** ****     * ****** *  ***  * * ** **   *  *   ** *   *  ** *   
    }
**   ** * **  ***   * *  * * ** ** %d", digits,sum);

   **        * ** *  ** ****      0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output