10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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  * *  **   * ** *** **  *    *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
** * **********  
int main()
{
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***   * * *  ***   ****  * {
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 * * **   **      *    **  *  * ** ***** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include      ** * * ** 

int  **    **     *** *   *
int d=1000;

int main(){
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** * * **  * * * * * *****  * *    *** *  *******   *  ** **  * *     * *** %d\n", numdigits, sum);

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*** ** ** ** *  * **  *  **   ** *  * %d", numdigits, sum);
** *    *** ***   * *  **** **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  *    ****  * * ***    *  **    n,digits = 0,sum = 0;
** * *** * *** *  * * *    ** *   *  * *********  * ** **
*  **  ** **  *** *  * * ** {
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 ***********  *** * * * * while (n > 0);
   **   * * *  **** ******** *   **  *    **** ** * **
**    * * ****  *   **  * ********* * ** *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
** *  * * * * * ***  * * a,digits=0,sum=0;
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***  * * *   **    * ***  (a>0);

    ***** **  **** ** **  * * %d",digits,sum);
* **  * *     ** *      *  ** *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
   *   ***  ** *   
int main  *   
{
int   *** * * **
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**** * * * *  *      **  *  * *   n,digits = 0,sum = 0;
  ****   ******  *****  *   * * *** * * *     ***   **
*    ***  * * *  *   *  *** *  {
** *       *    ***  ** ***        * * **   * ** ** *  * = sum + n%10;
 * ****  * *   *     **    **   **  * ******   *** * 
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 ***  ******* **      * ** ** while (n > 0);
 *    ****** * **** *   * ******** * ** **  *  *
  *** * ***     * **  ********   ****   * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 ** * ** *  * ** * *   * * * a=1,b,c,d,e,f,g;
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    }
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    ***            * **  * *  ***  * %d %d %d\n",c,d,e,f);
* ***     * *** *** * ****   **  *   %d",a,c+d+e+f);
 *   ** *  **       * *** ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 ****** **** ***** ***  * *** num,digits,sum=0;
 * ** *  *  ***  *  ***     ***   ***    * * * * **   *  *** **  **  
*** ** ***   **     ** ** ** ** **   *         **** ***   ** ** *      *  ****      &num);
 ** ***  *  ** * **** *  *  * **** * ***  
   **  **  ****  * ***       ****
  * ** *     ** ****** *    *  * *  ***  ******  *    * *  ** *  * ** * ***   += num % 10;
** *  ***    *   *** *  **     * ** * *    ** ** * ***   *      **   *     * ** * = num / 10;
* **     * *  * *** *   *** *  **   *  *  **   *** * ** * *  *      *    ** * * ***     * * ***
    }
  *  *     ** * *  * * *  ** * *  **** %d", digits,sum);

* * *    *** * *****  * * *** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output