10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

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#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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int d=1000;

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 *  ***  **    **  *   *       0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
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******   ******   *  *  *  **    *  * * %d",digits,sum);
***  * ** **  *   *  *****  ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* ** ** ****  *   *   * **** **   n,digits = 0,sum = 0;
** * *** **  *  *      *   **  *   *  ***  * *   * *   ****
** **  * *    *  *    *     *  * * ** {
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* * ***      * * *****  while (n > 0);
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* **   **  *** **  ** * **    **  ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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** *  **** * *   *** **  ** *  ***   *** *  %d",a,c+d+e+f);
*******  * ***    *  * ** * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
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* * *****    *  * *  **    *  * *  * *** * * ** *  *     * ***  ****** ** **** * 
    }
* *********** *   * ***  *  * ****  **** %d", digits,sum);

**  *  *  ** *  * * *  * *  * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output