10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
** **  **  * **** * **
int main (void)
{
int  **   * 
 ** *   * *        *   * 
 *  ***
* ***  *
 * *   
*   * *
* * 
*  ****
  * **
**   *
* ***   *   ***  *  * *  * *     **
if ** * * *****    * **     * *  
 * **
else ***  **   ** ****  *
f2=2;
else if  
    
else f2=4;
*   **** ****    * * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
* ****      *  * * **    a,b,c,d,e,f;
*** **   *  *   * *** *** **** ** count=1;
*   **  *   ****     *********   * **** **    * *** 
 *  * ***** **** *  * * **       **   
 * ***    *  **  ** *    ***** **   
 * ***  ****  * * * *   **** *****     **     
 ******  *   *  *  ***     *  ** ****  
* *  *  * **  *    * * **   ***** 
 * **  *  * **    *** *  * **      * *
    {
 ***   *   * **** ***** * ****   ****** *  *   *   *  * 
*  * *****       *** *   *  ** **      *** * *   *  ** *  
    }

 **** * * * *** ****** **** ***  **  *    %d",count,f);
    *  *  ** *******  * **** *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*  **  **   * *****  *
int main()
{
   **** *    **  **** *  *   * n,digits = 0,sum = 0;
*** ** ***  **  ***  *   **   ** ** **  * ******* **  ** 
*    *  *********** *       {
***     ***    ** **  * **  *   ***** ***** ** * * = sum + n%10;
*** * * * ***** * * * * *****    * ** * *  * *  *** **** ****  
* *** **   ***  **  ** *   **  **  * * *** **   ****  **
 ***  ** **  **  ** *  ***  while (n > 0);
**** *  **** ** * ** *  * ***** * ** ** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **** ** ***** * 

int  * * **    *   **      **
int d=1000;

int main(){
  *  * * **        * * ** * *** * * *******  * ** *  ** *
 **  ********     * **  ** *  * * ** *

**  * **** *** * * ** ***  ****** *  **   *** *** *   ***** * = a/d;
 *   * ** *** ** ***  *  *** *     * * *  *  *  ** ** * * *  *** ** **  * *  * *  **   *  *
**    ** *     *  * **** **  ***    * **   *      * * * = sum + currentdigit;
***** *   * ** *  * * * *   * *** **** ** * ** *  ****  ** = a - (currentdigit * d);
   * ***   **   **  ***   **** ** * *  *** **   * * * **    *   

*** *** * ****     ***  *** ** *        * * *    *  * ** * *****  **  ** %d\n", numdigits, sum);

*** ***   ** *** *  *  
********    ** **   ****   *   ***   %d", numdigits, sum);
******* *  **** * * *** * * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 ***   *    *     *** *  *     *   n,digits = 0,sum = 0;
 *** *    *      * **    ***   * * *      * **** *  
****** ** *  ***  **** *    {
* ** * * *     * *  * * ** *  **    * *   *     ** * **** ***   = sum + n%10;
**    * *    * ** *  ****** *  *  *    *   *  *  
    *    * * *  *  ******* * **** * * * *   **   * **  
*  ** **  ****  ***        * * while (n > 0);
 ***  * **  * * ****** *    *  **   *** *  **  *   * *  ** 
 * *    ****   ****    *   **** ****   ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
******* *    *   * *    **  * **   a,digits=0,sum=0;
*  ***    *  * *   *      *  ***  * * *    *   ****  **
    ** *    * * * **  * **  {
      **    *  *** * * **  **   ** ****   ****  ***** *  **** * 
**** * ** *  *    ***   *  ********  *** * * ** *  ****
 **  *    **  **   ***   * **   * * ** * * *  * * * **    *
****** *   ** *** *   *  * * 
  *   *  ** *** * * *    * *** * (a>0);

  *   *  ***** ** **  *   * * ** *  ** *  *  %d",digits,sum);
*  * *** *  ** *  * * **  *   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 *     **** *  *   *  
int main *   *
{
int **  *  **  *
   *   *** ** * *****  ** *   
** *  
  **   
* ** * 
 * ** *
* * 
** * **
* **
    *
* ** *  * ** *  *** *  *   ** *   *
if *  * **  ** *
 *  
else ** * *    
*
else if   
   
else f2=4;
*** * *    *** * **** *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 *  *   **     * ** ** ***  * *  n,digits = 0,sum = 0;
*** ** * * **  *  **   ** *  *     *** ** **    * *** 
    *   ** *   *     ****    * {
 ******* **   *    * ** ***   *  ***** * *** *  * *   *   = sum + n%10;
 ***    **      ** *    *    *  **** ** ******* ** *  ** * * *   
* **   *  * * *    **** ***   ** * **** * * ******   ** ***
 **  *   **     * **  ***   * *   while (n > 0);
   *** **** *  **      *  * ** ***  ** *     **  ***  
***     *   *** *    ** * **  **   * * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
    *****  *  *** **   * **   a=1,b,c,d,e,f,g;
 **  **  *  * *    ** *** ******* * **    ** * * * 
* *  ***   *** ** *     * *
*   *   ** * **    *****  *****    * *
***  *  ****  * *  *  *  * 
 * **  *   * ***    *  **  *** 
  *  ****** *    ** * *     **
    }
   **  *  ***  *** *    * *****   
* *  * *    **       **  * * * * 
 **    ****   *******   **  *  * * * 
**** * **** * **** *   ******  *
  *  ** *  * **    **  **  **  %d %d %d\n",c,d,e,f);
* * *  ** *** *   * * **   *******  ** ** ** %d",a,c+d+e+f);
 ***  *  ** *     ***     * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*   *** **   *  ********   ** * *  num,digits,sum=0;
*  ** ** **   * * *   *** **  **    ** * * *** ******  ***     *      * 
  ** *       *  *  **  *  ***** **  * ** * * *    ***  **       ***    *  *  *  &num);
 * ****** **** ** **   **  **** * ** * ***
* **  *** *   **   ***  *
*  * * *  *   ** *  *  **** * * *    ** * * ** ** ** * **    ** ***  **   ** * * += num % 10;
 ** ** **     **** * *** **    *    **   **  ****  **           * ** = num / 10;
***  *****   ***  *  *      ** *     **  ** **  *  *     **** **  *  **  ** * 
    }
* * **** **    *  * * **** ****  * **** * %d", digits,sum);

      *** *  *    *  ****** **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output