10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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** ** **   * ****  *  * **  *  **   * **  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include  **   *   ***** * 

int ** *  *   *   *    * *
int d=1000;

int main(){
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*** **  * * ****  *  ** * **     *  **   ** **** * **  * **  ** *  *  %d\n", numdigits, sum);

******      * ***   *  * *** 
****  *   *** ** ***  *  *    * *** **   %d", numdigits, sum);
**   *    *   * *** ***  **  *  *****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*  * ***  *  **** * *   **** * n,digits = 0,sum = 0;
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*   *******   **      * **  **   *    **   * *  ** * 
*   *  *  * * ****  * *  ***          ** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
** *   ***   *** *****  *   **** a,digits=0,sum=0;
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*  *  *    *     **  ****  **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main   
{
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else f2=4;
*   * ***** *         * ** * 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**  * * **  ***   **** * *  *** * n,digits = 0,sum = 0;
**   **** **     ** *   * *** * **  * * *  * **** *  **
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 * ***   *** * **  ** * **  *      ** *** * * **  = sum + n%10;
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*** ** **** **  *** * ***   * *    * * * **  * **
** *   **** *   **  ** ** * while (n > 0);
 ** ****  ** *  *  * *****   * **   ** *  * ** **   * **
*     ***     *   ** ***  * * ***   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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*    *** ** ***** *    ** ***    * ** * %d %d %d\n",c,d,e,f);
  * *****    **  *******  *  *******  %d",a,c+d+e+f);
   *  * *    ***     ** *  ** **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* *  * **    *******  *** **  ****** * num,digits,sum=0;
 * ***** **** ** * * **    *** *  *  *** ****  ***   *   * * ***  *  *
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**      ***   ***  *  ****** *   ****    *  * 
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**  * *  ***   *     **      ***** ** **  * * **  ** ** *  * * *** *   ** = num / 10;
  * ** *     ***  * **  ***  *** *** * **  * *   *  ** *  ** ****     * * ** *
    }
*** *  ***** ********** **** * **  **** %d", digits,sum);

** *** * *   ** ** ** *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output