10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
   **    **     *   
int main (void)
{
int *****  *    
**** *   ***** * **** * *   ** * **
 **    *
 *    
*  * *
 ** *   
** * *
**** *   
   
 *    ***
**** * *   * *   *     ** ** *   **
if *  ** * * *  ** * **  *** *    
   **
else *** **  * *    *     *
f2=2;
else if ***
***
else f2=4;
 * *     **     ***  *  *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 * ***   *   * *  ** ****   a,b,c,d,e,f;
 ***  ***  **    **  *    **** *   count=1;
*    ** ****      **  * * **      *   *  * *   *** 
*****   * * *** * **   **  * ****** 
**  *  ** * *  * *      **** *****    *
****  * ****  **  *** *     ** ****   * ** ** 
*   **   *  ***  ****   * ****** *        * *
  *  ** *   ****  * * *    * * 
* * ***    ** * * ** *** *** ***** ***    *
    {
* **** * ***  **   ** ** *  *** * ** ****** *  *** * * ****  
* **   ** **   **   * ****** *     *** **      *    *** * ****
    }

** *   *   ** **  ****** * ****** * *** %d",count,f);
   * **   ** * * *   * *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
  **  **  *  *** * *
int main()
{
* *  *** *    **  *  ** * n,digits = 0,sum = 0;
 *   ***    *   * **  ** **    *   * ** ** * **  * ** 
 *****  * ***** *  *   ** * *   {
***   * **** **  **   * *****     * **  * ****  **  * * = sum + n%10;
*** *  *   * * ***   *  *  *   *** *   ****  *****    **  * *    
***    ***   * * * * *    *** ** *** * **    *** *****  * *    
*  **** ****  *   *   **   while (n > 0);
***  * ****  * * * *   ***   **  *  ** *  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include * *  *  *   * * 

int * *** *  ** ***  ****   *
int d=1000;

int main(){
* ***** *  *  * *  *  *    * *    ***   **** ***  * **
*  ***** *  ****  * ** *  **  *  ** ** ** ** 

*    *     *    *  *  * *** * * **   ** *  **   ***      * *    = a/d;
  * ** ***** * *** *   **     ****  * * * ******  *     **  **  * *    * ** ***  *   *
**   ** ** ** **  *** ***   *  * *   *  ***    *     **  = sum + currentdigit;
*  **  * *  *  *  *  *  *    * *    * ** ** *** *   * *  = a - (currentdigit * d);
* ***  * ** * *   **  ** *   * ****** * **  *     **  ***    * *  

* * *   * *  * **  *** ** ** **   *     ***  * *****  *   ***   %d\n", numdigits, sum);

*****     * **      * *  
**    ** **** **   * * ***** * ** **** %d", numdigits, sum);
***  *   *  ** * **** **  *  * **    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 * * ****     *  *  n,digits = 0,sum = 0;
*******   ** * *** *** **   * *  * * **  * ***      **  ** 
*** ***** ***  *    ** **   *  {
    *  * ***  *    ********* ***   * ***  * *****    * = sum + n%10;
    **  *  * * ***   * *  *   *** *  * * *  ******* *** *
** ********  **    * *  * *    * *   ** *  **   *   **  ** 
  * **    *   * * *** *** while (n > 0);
 * *  ******  **  *   *  *****   **  *  *** * *  * * ** 
   ** *  ** ****    *  **   *** *    *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 **  **  * **  **    **  a,digits=0,sum=0;
* ** ** *   *  *** *   *    *  ** *   * ** *   * *** ** 
* **     * ** *  *       * ** {
 *  * * *   ****  * *   * * *  *   *** ****  *           * * *    
 * ****  * ***** **      ****  * * *  *** * **       ***       
****  **  *  ***      ** ** *  *  *    *  ***   *  *   **  
   * **    *  *****  *    *
***  * * ** * *** ***   * * *   (a>0);

 ** * *  **  ** *** *** *     *  **** * *** *  %d",digits,sum);
  ********** *  **  * *          0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 ***  *    ***    *  *
int main  *
{
int **        ** *
  ** *** ***  * * **     
*** *
**  * * 
*  * **
 *   ** 
**** *
**** 
*     *
 ** 
* ***       *   *  ** * **     * *  *  **
if ** **    ***
**   *
else * * ** **
 **
else if  * 
**
else f2=4;
  *   ** * **   ** ** * *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
    * ***   **     ****   ***** * *  n,digits = 0,sum = 0;
      *** * **   * * **   *  * *  *  **** * ***    
***  ** *** *  *   * * ** *     {
******** * **    **   *   * ** *** * *    *   *              = sum + n%10;
 ***   *** ***  ** *  *    **   **     *     *   * *** * *  * 
 *** ** ** * * **   **   ** *  **   * * * ** *  **** *** **
  *** *  ** *** *  *    *  while (n > 0);
** *  ** * *** *** * * **** ** *  **    *** ****   * 
* **   *  **   ** ***  ** * *  * ****  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
****  * * ****   *      **         a=1,b,c,d,e,f,g;
    *   *****  **  * ** **    **  *   **  **** *  *  **  * 
 *  *   * *   **********  ***
*  **** *****   **     ** *  *   *
* *  * * *** ** *** * * * * **
 *  ** *  *  *   *   *  ***
  *  *    ***** * **** * *** * *  * *  
    }
  *****   *    * **  **   *  
 **  ***** *  **  *  *  *   ** * ** * 
**  *        ** * *********** ***
   * ****  **  *   ***  **  * 
* ***** **   **   ****  ** **   **   **    ** %d %d %d\n",c,d,e,f);
 * ** **   * **       **      * %d",a,c+d+e+f);
** *** *****  * *****   ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 ** ***** ** *   **** *  * ** num,digits,sum=0;
 * *  *     ****** *** ***  **    *    ****  *    * *** ** *    *
 *     **    *  ***** ******   ** * **  ******   ***** *   *  * *   * ** ***  *  &num);
 ** * * **  **   ** ** ** * * *  ****** ****
 *  * * * *   *  *******     
*   *** **  ***  *********   ***    ***  *   **  ***  *      * **** *  **   * **** * += num % 10;
**  *  *****  *       * ****  **** *  * ** ** * * ***    *   * ** * ***  * * * = num / 10;
**      *  *    * * ****   **    *  *    * **   *  * *** ** ** *   ** *   *   *   *
    }
  * *  * ***  ***   *   * *** *** * *   *  %d", digits,sum);

***   * **** *   * * **** **    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output