10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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int main (void)
{
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f2=2;
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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  ****  *  * *  **    ** ** ** ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
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int main()
{
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* **  ***       ***    ***  * while (n > 0);
** * *   **  *  *** ** ***  *   ** *  * **** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  ** *   *    * * 

int  ** * * *  *   * *** * 
int d=1000;

int main(){
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***** *****    **   *  ** **     * *  ***  **   * **  = a - (currentdigit * d);
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* *   *  * *  ** *   ***  **** * **   * * * * ** *     ** *** ***  %d\n", numdigits, sum);

*     **  **** *  *** *** 
**** *  *** ** ** **  ** *  * *    **  %d", numdigits, sum);
** *      ****  ****   * **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 **** * ****  * *   * * * **  n,digits = 0,sum = 0;
 ***** *   *** *  **  *   *** **  ** *** *  ** **   **
*******  *  ***  **  ** *  *    {
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* * * *  * *     ** **  * *  ******* ** *   *
**  * * *    **   **  * *** ***  * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
** **   *** *  *       *** ***   *  a,digits=0,sum=0;
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**        **** *  *  ***  ** *    (a>0);

* **      *** *  * ** *   **   **  %d",digits,sum);
**  **  * **       ** **** *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
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int main  *  *
{
int *       ***
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else f2=4;
* ****  ****      **** *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
  *  * * ***  *  **  * * *   ** n,digits = 0,sum = 0;
*  * **   ** *   ** *    *    ****   *     *   * *
*** * * **   ***   ** *  *** {
*    *** ** *    *  *  ** * * **** *  *** * *  ** ** = sum + n%10;
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    *   **      ** * **   **   *** *  *** ** **  * *    * ***      *
 ** ** ***     * * *    while (n > 0);
 *   * * * *  ** **** **  * ***** *  *   *    *   *  ** 
* *** * * * **  *  * *      *****  ***** *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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    }
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**   ***  *    *   *     *  ****  * ** %d",a,c+d+e+f);
* ***   *******  * *  **  * ** * * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 * *      **   ** ** *   ** * ****   * num,digits,sum=0;
  *   ** *  **    *       * **   *   ** **   *    *  ****
 *  *  ***  *  ** ** ***** **     * * *   ** * ****  *   ** ***** * **** * *** &num);
  *** * **   ** ***  * ****     ******
 ** * * *  * *  ** ** * ** *
 * ** ***    * * *  ** *   **    **** ** *  *  *  **** ** ***  * **  ** * **** * += num % 10;
  *  ****    *  **  *  * ** ****      **  *     *  *   *    * *   *    *  **  *   *** = num / 10;
**** * *  ** ****  **  **  **** **** **  * **   **  ***** * * ****  **  *   ** 
    }
      * *****  *****  ***  ***  *  * %d", digits,sum);

**     **     * ** ** * * **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output