10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
   *   * ** ** *** *
int main (void)
{
int  ***   *
 * **** ** * *   * ***  *****  *
    
** ** 
     *
* *  
*  * 
*****  *
 *
***  *  
 * ** * ** *    **    *    *      ** 
if * ** *      **  ****  
** 
else *    *  ***  *  ** 
f2=2;
else if   * 
* 
else f2=4;
 *  **  ** *   *** *  ** * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
* * ****      *  ** *    a,b,c,d,e,f;
 *** *   *   *** *  * *  **  count=1;
    **    ** ***  *    *** **   * ** *   *     **  **  *
*  **   *  *    * ** * * * **
 * ** * * * *   *   *     ******** **   *
 ****  *    *    **    ** ** *     * **   * 
* * * *    ** * ** **  ** *  ***  *** * *  *  *
 ****   * ****  * * * *
 *   *** *  **  * ******   ****
    {
  ******** **** * ****  ***  **** *** *   *   ********  
*****   *   ** **  * * *  * * * * * ** **     **   *
    }

 * *  ** **   ** **  * * **  *  *  **    %d",count,f);
**   * *  *** * ** * * ***** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 ** * ****    **
int main()
{
* * * *   *    * *   ** ** ** n,digits = 0,sum = 0;
 **   * *** *  *  *** *   ** ** * **   *   ***   *
****** *  * *      ***  *  {
* ** ** * **    **  * ******* * **  *  *  ****   ***  *   = sum + n%10;
  *  ** **  * ** **  ** **  * *** *   *** **   *** ** * *
  **      ***  * **   * **  ***    ** *** ***** **  ****   *  
* * ** * *** **   ** * ** * while (n > 0);
   *  ****     * ***   * *  **  *** * ** * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include   **** *   *     *

int ***     *     * ***   *  
int d=1000;

int main(){
* ********** ****  **    * *** *** * * * **   ***
 *    * **   ***  * ** **  **** ** *    * 

 *** *  ********** ** ** * * * * ***** **   ***  **  ** * = a/d;
  * **  * *  * ***** * *  * * ** *  ***  * * * **  *  **    ***** ******* **** *  ******      *   *
* *     * *  ****      *****   * *  * ** ***  **** **    = sum + currentdigit;
   *  ***  ** *    **  **   * ** *          **** **** = a - (currentdigit * d);
 *  ***** **    *   **** * * **       ******** * *** *** ***

   **    **   * **** *    *  ***** **  *****    * ***  * **   *     *******  %d\n", numdigits, sum);

 ****  ** ** * **  * *      
    ** ******    * **  *   ** %d", numdigits, sum);
  * ******* **** **    **  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
** * *   **      **   * n,digits = 0,sum = 0;
    * *** * *  *** *   * ** *** ** * ****  * * **  * *  *
**    *   ***  ** *  *** * {
 *  * *     ***  **  *      * **     ****   * *****   * ** * = sum + n%10;
*  ** *     *  **  ***** ***** *****  *  * ** *    *****       * 
*   *  *     *  ***  ** *   **** ** * * *** ** * *     **
     ** ****   * **    ***** while (n > 0);
 ** * **  *  * *** **   ** * **** **      ******* * **  
  *    * *** ***** * ** **    * ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
    ** *** ** * * * **  **  *  a,digits=0,sum=0;
***     *    ** * * * **  *****      *    * ***     * * * 
*    *  * *  ** **   *    *   * {
 ********** * *******  **      **   * * **  * *   *  *   * *
 *   *    * *  *    *   * **   ***   *   * *** ** ***** *
 * *  * ***     ***  ** ** ****        **  **** ** ** *   *  * * 
****  *    *  *       *** *  *
   * *  ***  ****  * **   **  (a>0);

  ** *  * **  *  ** *   ***  *  ****  * %d",digits,sum);
*  * * * * *   *** *     * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*  **     ***  **    
int main * * 
{
int  * **  * 
*** * *     * ** ****** * *** **
     ***
* ** *
  *
***  ****
*   **
 **** * 
 *  **
** *  
 * * *   ** **  *   **      ****
if  *  * *  ****
*   
else    *  *  
  ***
else if ***
**
else f2=4;
 **  ****    **    **** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**   *         *  ** *  ***  n,digits = 0,sum = 0;
*  *  **   **    **********  **   ****   **  *
 * ** ***** ** *    **   ** {
*** *   ****  *   ** *   *** * *** * **** * *  ****  = sum + n%10;
* *** ** * *** *  *   *   *    ********* *    * *    **   *  
  ** *   * *    ***  **   **** * * *     *   * * * *         *  
*  ******* *  *****  * *  while (n > 0);
*  *** **** *** * *      * *     ** * *  *** * *******
* *  *     ** *    *    *  ** ***  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
   **   ****   ****  **   **** a=1,b,c,d,e,f,g;
 * ** **     *  ***** **  * ****** ** * ** *    *** *****
*  **  ** * * **** * *   **   
*** ******      ***   *  * ** **  **  ** * 
      ** * *** ***   * ** * *
 * ***   ***** *   **     **  **  *
* ** * *  * *  ** *** ****   **   
    }
*** * * *         ***  ** *      *
* *  * *** ***   *   ******   * *
**   **  *  ** **     *** ***  ** * 
  * *   * *** *  *  ** *   ** *  *
*    ********* ** ***     * * ***  * *   * %d %d %d\n",c,d,e,f);
      *  ***  * *   * ** *   **** **  ** %d",a,c+d+e+f);
*         **  ***  *  **** **   ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
** * * * ***  *** *  *** *     num,digits,sum=0;
   *   * * ***  ** *** ** * *  *** * *   *** *   *   ** **  *   * *
***   *   ** * **  ***     *  * * *** *** *  *  *  ***** * **** ***  *   &num);
 **      *   * *** ****** *         * *   
** **** ** * *  * *  * *
** *  **   * ** **   *  ***  ** *   * ****    * **** *** *** * * *   ******   * += num % 10;
   **** * **  ***  **         *** *     ** * * **   *   * ****  *** = num / 10;
 * * *   ** ** ** ***  ** * *   *  ** ***  *** * *  **   **** **   * *  *   ** **
    }
*****  **  *  ** **** * * **** * ***  *** %d", digits,sum);

  *   **   ** ****   * *** *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output