[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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* *  * **    * * * ** **   * * * ** ****      your input:"); //DO NOT CHANGE
*****   ** *  * ***    *   * *  * ** * ****  ***** ***   *  *
    
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*** **  *  ***   ** * ****  * ** = 'A'; a <= 'Z'; a++){
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 * *** * * * *** * **  * ** *** *  ***  *  ** *** * **** ***   *  *  * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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*     ****    * *   **  **     *  *** * ** * *   * *    *** ***  **   * *  ** *** *  *** *     *     *** 
  * *     *** * *  * *** *  *** *   ** * * *********  **    **   *    * * **  ****  * *****    * **   **  ***  
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 * **  ****** *  *    *   **     ***  ***   **** 
*     ***  **  ****  ** *  ** *  ** ** * * *    **  * ** ******** * 
 * ** **** **  * *    * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* ** *  * *    *  * *    *** **  0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include    * *  * *  *  * 
#include *  **  ***  * *

int main(int argc, char *argv[]) {

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  ****   *** ** ** }

* ******  ** *   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include *   ****      
#include   *  *** *  * ** 

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include     *  *   *   * 
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int main(int argc, char *argv[]) {

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* ***  * *  * }

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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include * *   **      **
#include  *** **  *  *

int main(int argc, char *argv[]) {

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*       *  *  }

*     *  *   *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include * *   * *  * *
**** *  * **   ****       

int main(int argc, char *argv[]) {

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**** *    * * *    ** * * ***** ***      a++;
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**  **  *** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int   *   argc, char    * * {
*  *  **  **   ** char a;
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** * * ** **  
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}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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    **  ** ** * ** *   ** * ** ***  *   *     ***** ** *  *       ****** * ** **   * ** *   ||i==69 || i==73 || i==79 ||i==85){
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* *     ** ***** * * *  *     ** * **  *   ** *  ** **    *         ***  ** ****** 
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   ***         ** *  * *** *   ** 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output