[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*     *  **  * *******  ** *  **  your input:"); //DO NOT CHANGE
* ****     * *  ********* * ** *      * *  ****   * *    *
    
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* *** ******   *   ***   **  **** **** ** ***   *    ***  *    ** *** * 
*   ** *   **  ***  * *   *  **  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include * * *  **  **
#include     ****   ** *

int main(int argc, char *argv[]) {

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**   *    *  *** **  **** ** *** **    *  * a++;
* ***** * *   * }

*     * *  *  return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include *  * ***    *
#include  **   *  * 

int main(int argc, char *argv[]) {

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* *    * *  **   **  * * *** * * * *   ** a++;
** **** * * *      }

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}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  *****  *  ** *
*          * * *****  **  

int main(int argc, char *argv[]) {

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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include * *** **  * * **
#include  *  *  *  *** **

int main(int argc, char *argv[]) {

* *          *   ** int a;
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*   *  ** * ***  ***** **  **  *   **  ** a++;
** *  **   ** }

  *       *  ** * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include ** ********  *
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int main(int argc, char *argv[]) {

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      *  *** *  }

  ** * *  **  *    return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int    * argc, char  *  **   {
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*         *    *  *      **   a++;
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***   ** ** * * 
*  ****      return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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 * ***   * **** * * *****  ****  **   *  *  ***  *     *
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
 * **  * * *** * * * * *        * a;
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****** *   *  **   **   ** ***** *     ** *** *  **  &a);fflush(stdin);
* *    ** ** **  * *   ***  ***  *
*  ** **  ** ** *   * * **  *   **  * ***    ***    * * **   * *********  *
* * *   *  *   *** *  ** *   * *   *   *  ****    **** ** *  **  ** * ** ** * * * ***   ||i==69 || i==73 || i==79 ||i==85){
 ** *  * **  * *    ** *  *  *   **** ** *     *    **   ** * * **  *   ***   * * *  ** *  * *       *    *   **  *
**   **  * ****  *  ***   * ***** ** * ***  *   *    ** *   *  * ** * *  
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*** **     * * * *  * * * **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output