[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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* * ****  **  *   * ** ***   *  ** *** * ***** * your input:"); //DO NOT CHANGE
 *   ** ** ** * *  ***   ** * **   ** ****  * *  *    
    
  ** *   * ****  ***    ** **** Your conditions start from here
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****  **  * *  ** **** * *      *  ****    *** **  ****   *** 
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   * ***   *  ******* *   * * ** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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****    **  ** * ** * * ******* * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include * ***   * *     *
#include  **     * **  * *

int main(int argc, char *argv[]) {

   ***     * * * char a;
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*** * *  *        * ****  ***  * *      * *** a++;
** * **   ** *  *   }

  ** * * * * *  return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include   * *  *****  **
#include   *    **   ***  

int main(int argc, char *argv[]) {

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* * *  *    ***   }

*  * ** ***    return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * **   * *  
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int main(int argc, char *argv[]) {

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* * *    ** *  }

*  *   **  * **** ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ** * * ********   *
#include * *  * *  ** *

int main(int argc, char *argv[]) {

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* *      **  *  }

* ****  * * ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include    **  ***  ***
***     ** * ** * **  ***

int main(int argc, char *argv[]) {

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** *  **     ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*    *  *   *  **   
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int *** * argc, char    * {
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****** *** * ** *  ** *  *   *  ** a++;
     * *    * ** }
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** ***    **   return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
    **  * *    *** * ***  **  **  your input:");
*   * * **   ** *  ****     *  *    ** * ******   *   &a);
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*** **  *** **** *****  ****   *   **  ** * **  *   **   *
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*** *  *     *  *  **   * * *  ***   *      * ***  *  * **  
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
*  * * ****  *     * *   ***   a;
*** * *  ** *      **      ***  * * * * * your input: ");
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* * *  * *** ** ** *     *  * ***   **  ** *   *   * * ** *
*    *        **   ****** * 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output