[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*** ** ***** * * *   **** * * ****  * * **** your input:"); //DO NOT CHANGE
  *  * *   ** *   * **  ******  * ***  **    * *   *
    
 * *  *******         * **  * * Your conditions start from here
*  * *  * ***  * *         **  *   = 'A'; a <= 'Z'; a++){
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* **** ****  *  * *  ****   *  * * * ** * **   *   *  ***    ** *  * * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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    ****     ***  * ** * * *     *** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* ***        ** *  * ** *  * 
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** * **   *   *  *** ** * * *  * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include *  ** *  *   *  * ***
#include * ***  * *** *  

int main(int argc, char *argv[]) {

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   ** *  *  *   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include    *** * ** *** 
#include  *** ****  *** * 

int main(int argc, char *argv[]) {

*  **  ** **   char a;
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** * **    * * ** }

* *  ** * * *  *  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * *  *  ***    
* * *  ** ****  ** ****

int main(int argc, char *argv[]) {

*   * **  *   * char a;
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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ***  **** ** 
#include  ***  * **   * *

int main(int argc, char *argv[]) {

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* ** ***  *** *   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include   *     * * *    
* ** ** **  **** **  *   

int main(int argc, char *argv[]) {

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*  **     ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int  *** argc, char ** **  {
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* * ** *** *     *  ***  *   a++;
  ***  * ** *  * }
  ** **   **  * 
* *   ** ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
**  *** **   **   ***  ** ** *       *  * * your input:");
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  *** *   *  *  **    **  *        ** *** * *** *    ** 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
      * * *** *** * *   * **  a;
*   * *  * *  ** *  * * * **     * * * your input: ");
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*  *  ***      *****  * *** *  * ***   *  **** * * ****  ** * * ****** ***** * *     ** ||i==69 || i==73 || i==79 ||i==85){
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  *   **   **** **    *  **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output