[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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   *  **   * * *  **** Your conditions start from here
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*   * *      **  * *  ***  * *    * **  **   *   **** **
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***     ** * **     ********  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include   * *  ***  ** *
#include * * * ****   ** *

int main(int argc, char *argv[]) {

* ***** * ** **** char a;
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 *******     ** * return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include   *     *  **  *  
#include * * ** * * ** 

int main(int argc, char *argv[]) {

**   *  **   **  char a;
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** *   ** ** }

* **  *  ****   return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include *  ** ** ** * * 
*   *  ***         ***

int main(int argc, char *argv[]) {

**     * *  **  char a;
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  **  *   *  * }

 * ****     *  * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include   ******    *   
#include ****    *  * *

int main(int argc, char *argv[]) {

* **      *  int a;
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** **  ** *     }

  *****    *** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include * *   **** * **
** *   **  *  * * ****  *

int main(int argc, char *argv[]) {

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* **** *  *   ** }

   **     * *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
***    ** *  *  ** *
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int  **  argc, char * ** {
*   **      ** * char a;
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*** *   *** * ** * **     * *   **** ** ** *   ***    *** *   *** *   *  
*   * **   * ** * *  **   *  ****  else
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*    *    *** *      *  ***       a++;
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   ** * ** * 
** ***  *  ** * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
**    **   *    *       ****      **  * your input:");
   ******    ** *  * ** * * * ****  * * * &a);
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****  * ** ***** **  *   ** ** ** *   ** ***       ** * 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
   *** * *** *** *** a;
** * ****** * *         ** *   * ** ** your input: ");
* *    **   **  *    *** ****  * * ***  **  ***  *  &a);fflush(stdin);
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*** ***   **  ** ** *** ***   * *    * * **  * **    ****  ** **      * * ** * *    ***
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}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output