[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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  * *  * ****** **  ****  **    *  **  *  *    **** *  **   ** 
    
    ****** **  **  ** ** * Your conditions start from here
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*           *** * ** ** *  ***    ****** *    * **  *** *  ***
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*    **    **  **** ****     ***** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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** *  **  * * *  **  * ***      0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  * *****  *** ***
#include       *** ** **    

int main(int argc, char *argv[]) {

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******   ** * ***   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  ** **  * *** *
#include    ** ** * *  **

int main(int argc, char *argv[]) {

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***    * *     return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include *** **  *      
**  *   *  ***  *  * *** 

int main(int argc, char *argv[]) {

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*** **  * * ** **      * * ** ***  *** ** ** *   a++;
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    *   * *        return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  **  **** * ***
#include  *  *     *

int main(int argc, char *argv[]) {

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  **   * *  * *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  * ** ** * *
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int main(int argc, char *argv[]) {

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*   ** *** *    * ****   *   *   **    *** a++;
   **   * * *  }

** ***  ** **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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* **   * *   ***** * ** 

int  *  *  argc, char  **  {
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* ** ** * * * **   *    *  **   **     **  *  *  **     *   *** 
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* *         ***    }
   *      *  * 
 *     ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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* **  * * **  **   *  ** *  ** *  *** *  * *     *  *
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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**  * *** *** *  **     *** * *   *   * *** *** ** **** *  * * *  * * *  ********
**    ** ***  * *  ****  *****   *    * * * ** ****   *  *** ****       * * * ***    *  *
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*         *     ***  * ****  **   ** *** * *  ****  **   * *  *  * ***   * **** * *
* **   *  **     **      ** ***  **  ***  * * **     *
****  ***    ** *   ***   * 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output