[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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    ***  * ******   ***   ****** * ** your input:"); //DO NOT CHANGE
   *    *   *  *  * ** * *** *  **  **     ** *  **    **  
    
  **** ***** * * **** * * ** Your conditions start from here
 *     * *  * ** ** ** **   *  = 'A'; a <= 'Z'; a++){
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* *** ****   *   *** *     *** *     * ****** **** *    **    *** * ****   * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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* *****  ** ** **     * * ** ** *    *   * ** **  * *  ** *   *  * * *  *  *   * ** *   **    * * *  *** *****  
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** * **  *  * *  ********    ***    *  ****      **  *
 * *  **  **** ** *       ***    **        ***** **  ** * *   * ** *  
  ** **** * *   **   ** ** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*   *  ** ***    **   **  ** 
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**    ** ** **** *  *  **    *    * **  ** *  *   ****
* * * ** *    ** * *  *** *

* *** ** ** * *** **     *** ****   0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include **    *    ** *
#include *  *  * ** * ***   

int main(int argc, char *argv[]) {

   * *  ***   char a;
** *  **  *  ** * 
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**  *  *    **  ***  * ** ** ** ***  * **  ********* ****  *** * ****  ****** * *    *** * *  a);
   **  *   * **  *  ***  **  **      ** *   a++;
****      *** }

* ** *  *  ** *  return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include     ** *  * *  
#include * *  **   **

int main(int argc, char *argv[]) {

*  **    * *  * char a;
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*    * *  *  *       * *****           a++;
    * ** *   *   }

 * ** ** **     * return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include      ** *    **  *
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int main(int argc, char *argv[]) {

*    *   **   **  char a;
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*   * *** **** *****     *  ** ** *     * **  a++;
   *** * *****   }

 **** *       return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include * * *** *     
#include  *** *  ***** *  

int main(int argc, char *argv[]) {

* ****     *   int a;
***  *  * *  ** 
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**  **** *  ****  **  **   **  * *** *  a++;
**    *  * * ** }

*  * *** **    return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include *  * ***  *** * * 
  ***** * **** *  *    

int main(int argc, char *argv[]) {

* *   **   * ** int a;
* * *   ** ***   
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***      ** **  ***  *   **   * ** * a++;
***** *  ***   }

   **  *   **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
* **  ** ** *   * * 
 **  *   *    **  

int * **  argc, char * *  * {
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* *       *** *  *     *** * * ** **    **  **   * ***** **   
* * **    **    * * ** * **   else
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  ** **  * *  * **    ** *   *  a++;
*  **** *  *   * }
**  *** *  *   *   
       *  *  *      return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
    *   *     **  **     *    *   ** * ***** your input:");
**  * **   *  * ** ***   ** *  * * ***   *  *   &a);
***  **  *     **   * *   **  *  *     *  {
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**    **** ** *  * **  ***  **     ** **   * **   **** {
*   ** *  *** ********   ** *  ** * **** ***  ** * * ***  *    * ****  *    * * *  **** *     ****** a);
*    *   * * * * * ** *  * *  * *   ** **** *  * 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
*  **   *  ** *  * **  **  * ** * a;
*   *  *  *   *    * ** **   * *  your input: ");
** * **   *** *  *     *  * *   ** * *      * * &a);fflush(stdin);
**** * * * * * **    * * *   ****** * 
**    *   *  *  **   *  **     ** ** * ** *****   * * ** *  **  *
 *** **  **  *** * *** **  * *    * **** * ** *** *  *  **   ****  *           ||i==69 || i==73 || i==79 ||i==85){
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*     * *    * * **  * *** **    * *  **    **  ***  **  *   * ***** * *     * *  *  *   
 ** ** *  * * *          **** * ** *   * ** ** **  * ** * *****   ***   * * * **
  **  * **** *  *   *    *   * * ** ** ** *** **  *** **   ** *  * *  * ****   *  * ****     *** ****    * * ** **  * *  *  **  * **
**  * **  **  **   * ** * *     *    ** *  **  * ***   *    *****  * ** **  * **  
*  * ***  * ** * *    * *** * *       ** * * ***      * 
 ***  **  * *  *     *  ** *  
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output