[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*   *  ***** ****** * ** *** * * ***    your input:"); //DO NOT CHANGE
 * ** *  **     *   ** * **  ** *  **** *  ** *   
    
 * *     *   ***  *   ** * **  Your conditions start from here
* **  *** ** **  *  **  ** = 'A'; a <= 'Z'; a++){
***   **   **   *  ***  *   *  **   * *****  ** *     ** *   * * ** 
** **   * * **   * ** *    *  **  ** ******  *  **  ** ** * *       * * * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
**  ***  *** * **   *    *   **** * **     ** * *** **  *   **  * ** *      * * * * *      ****  * **  * *  * * *  *
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   ** ***   *  ****  *** * ***  *** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* *  *   **  ** * ****  ** * * ****   ** * **** ****** * **
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*    **** * *** ***  * * **    * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include    * * * * *  
#include * * * * *  ***  

int main(int argc, char *argv[]) {

 *  **   * * * ** char a;
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  *** * *  **   **   *   * *  * * ** a++;
 * *    ** **  }

* * *     ***  return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include *  *** *****     
#include  **  *  ** *  **

int main(int argc, char *argv[]) {

   *     *   char a;
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  *    * *  **   return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  ** *    ***
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int main(int argc, char *argv[]) {

**     *** * char a;
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* **  *  *    ****  }

 *****  *        return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ****** *  * *
#include   *   * * * 

int main(int argc, char *argv[]) {

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 *  **   **    *** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include **   *  *   ***
 **   ** **  *  *  *   **

int main(int argc, char *argv[]) {

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* *  *       * * * *   ** ***** * **   * *     a++;
**** * *   }

 **  **       *   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*** ** * * * * * ** ** 
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int    *  argc, char  *   {
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   ***** ** *     *** ***  ** * ** a++;
* **     ******* }
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   **** ** ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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** *  *     ** ** *  * * *  *      *  **  * **   *  **   &a);
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  * *    *  *    *** **     *  **** * * * ****  *   *
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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***** * ***  * ****   ** * *** **** *  *      *   **  ** *  * *   **   *  * *    *   *
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*   ******     ** *** * *
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output