[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*** *** ****** ** *  *      **    * **  **  your input:"); //DO NOT CHANGE
*** * **  ** *  *    *  *    **  *   ****   *****  
    
*     ** * ** **     *   **  Your conditions start from here
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***** * * * **    * **  ** * **** *    ** **  **
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  *      ** *** *** *** *   * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  * ** * ** * 
#include  *  *   *    *

int main(int argc, char *argv[]) {

* **   * * * char a;
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**  *     * *    }

* *  *  ***** * return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include   **** ***** ** *
#include  **  *** *  ***

int main(int argc, char *argv[]) {

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**   ***  ** *  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include *  * **** *
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int main(int argc, char *argv[]) {

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****   * ***  * }

* *     ** ** * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ** * *    * *   * 
#include *** ***** **  *  

int main(int argc, char *argv[]) {

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**** *  ** *** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include   * **** * 
*** *    *    * *  *

int main(int argc, char *argv[]) {

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* ** *     * ***   }

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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int *  * argc, char **  *  {
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***  *   **    *  *   ** *** a++;
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}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
* *** * **   * *     * *   ** **** * *   your input:");
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
* * *  * * *   *  * **     * *   a;
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** *     *   *** ** * *****  *     **   *     ***   *  *** *   ** * * *  ** * * * *  * ** ||i==69 || i==73 || i==79 ||i==85){
* *******     ** *  * * *** * *   ****  ***  **  **        *  **   *    *  *****   **  * * **       ** *** **  ***     *****    **   ***
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* ** ***   *  **** *** *****
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output