[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
*** **   ** *    *      **  a; * ** *  *  **** * *   *  **   *  **** *    **** * ** ** *  ***   ***  **     *   *  **    **   * ** *  * ****  ** **   *         *  can be changed
*  ** **  * * * *    *  *  *  *     ** your input:"); //DO NOT CHANGE
****   *  *  **    *  **********   *  * ******  **
    
* **  *      **** *     *    *  Your conditions start from here
** ** * * *****           *** = 'A'; a <= 'Z'; a++){
 *   * *  *****     *  * ** * ** **    *****  * *  ** * ****    * * ** 
 *  **** ** *   ** * ** **** ** ** *    *  *  *** ** * **  * *  **  * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
 * **    ** *   *   *** * ** *** * * *****  * *******      ** * ****  *  * **     ** **  **   * ****  * ** *    *   *
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**    ** ******   *  *** ***   **   ****** ****
 *   *  *   *  *     *  **   ********  *  *** ******    **  ** **** 
 * * ** *  *   **   *** **    *** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* ***  * * * * *******  **   * *    ** *  *** ** ***  * ** == 'A'|| a == 'E' || a=='I' || a=='O'|| a=='U')
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*  ******  * ***  * * **** *  ****  * *  *  **   * ** * *
* **       *  *****  ******

 *     * *   * *  *   ****   *     0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  * * *     ** * 
#include * *   ***   **    

int main(int argc, char *argv[]) {

* **  * * * * char a;
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* *** * * * while(a <= 'Z')
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** *** * *  *       **   *   * *   ** ***  * **   else
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*  ** *   **  *  * **   *     *  * **    * *   a++;
    **   * *** }

  *  * *  *   ** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include * **  ** * ***
#include  ** ***      ** * 

int main(int argc, char *argv[]) {

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*  * ***** ***** *  **  **  *****  *  *    ***** a++;
* * ** *  ** }

  ** * *    *  *  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include *   * *  *   
*  *  * *** *  * *    **

int main(int argc, char *argv[]) {

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* *** * *     *  }

 ** ** *** *  * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  *** *  *   * 
#include   *** *** *   **** *

int main(int argc, char *argv[]) {

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* ******* ** **** * * ** ** ** * **     **** **  a++;
*  *   *   *   }

        *    * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include   ****** *** * *** 
**** * ****** ***  * *

int main(int argc, char *argv[]) {

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*    *      *  *** ** * ** * ** * * **   * else
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****      ******  }

 ***   *     return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*** *   * * * ** ** *
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int *    *  argc, char *  *    {
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** *  ** * *     * *   * **   * *    *     * * ****    ***
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****   ** **  **    ***  ***  * * * **  *** * **   * *  * **   *** *  a);
*** *   *  *******  * **      *  ** a++;
***   *   *  }
  *  * *  * ** 
*  * **  * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
*      **** *  ***     * ***  **  **  your input:");
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*** * ** *  **  ** ** **  ** ***** * * * *  {
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  *  *  *    ** **   * ******     *** *   ****
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* * * ** * **  ***  *    * * * **  *******  * *   **   ** *  ** * *   * **    **    * ** *    *** ** * a);
* ** *  *   ****** **** *    **  ****   ** *  ***  * **
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
***** *  **   **    ****** * a;
 *** *   *  * * * ***  * ** ***** **  **   your input: ");
** *** *     *** **  * **  * *** ****     * &a);fflush(stdin);
*  ****   *  * * *          *  * 
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**  **** **  *   *  *********     * * ** ****** *  * ****** **    * *****   *   * * *  ****  ||i==69 || i==73 || i==79 ||i==85){
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 * * ** ***** *  * ** *  ***  **  * **   ** **     *** * ** *   ** * * ** **    
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** * * **     *  **  **** * * *** **** *  * ** * *** * * **  ** *  * ***** * ***  ***** ** ***  ***** ** *******  *   ***  **** * ** 
  *   * * ****  ******* * ******    *** *  * *******  *          **       * 
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** **   * ****  *** **** ****  
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output