[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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* * * *     *  **  ******  **** * *****  *    * your input:"); //DO NOT CHANGE
  ***  ***** ***  * *******   ** *  * **** *** ***  *   
    
  * *  * **  *** ****** * ** Your conditions start from here
* *  *** *** * *  ***     ***  = 'A'; a <= 'Z'; a++){
**   * **  ***** ** * **   *  ** ** **    *         *  **** ** **      
  ****  *   * *****   ** **  *** ****    **  *      * ****  * ***** *** * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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   * **   ***   ***   *    * * * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  *** *  * * ** *** * *
#include **    ** * *  * 

int main(int argc, char *argv[]) {

*  *** * ** *   * char a;
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**   *** ** *** ** *  **  * ** **   ** ***  ** a++;
  *       *    * }

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}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  **    **** * *
#include  * ** *  *** 

int main(int argc, char *argv[]) {

* **    ** *  *  char a;
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*  *****       return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * ******      * 
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int main(int argc, char *argv[]) {

** * *  *  * * char a;
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 *    **     return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  **          * ***
#include *  * *  *  * *   

int main(int argc, char *argv[]) {

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 *** * * * *   * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include **   * * ****  
***  * *  ** *    ***

int main(int argc, char *argv[]) {

*   * *  ***   int a;
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* * *    ****   }

*  *  *   *  ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*  *   ** *      *
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int *  *  argc, char *   * {
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*      *   **** *  *  * * a++;
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**  ** ** * *  * 
*** *  **** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
 *  *     *    *  *   **  ** **  **    ** your input:");
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*** **** *    ** * * *  ** *  ***  *  ** ** *  *   ** ** 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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* * ** *   *  * * ** * **** **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output