[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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**  * * ****  * *  *   *  *  *   ** * your input:"); //DO NOT CHANGE
** * *** *** *   ** ** ****** * ** * *  ** ***    * * **** **
    
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***    ** * * *  ****    ***** ** **  **  *  * * *     **  *** **
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**** ***    **  * *******  * **  *  *****  *   **     * *    ** **
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}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include    * *      **** 
#include  ***  **    * ** 

int main(int argc, char *argv[]) {

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**     *    **   }

**** ** * **  ** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include    ***** * *** *
#include * ****** ********

int main(int argc, char *argv[]) {

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*   **** **  ** * ********* *  *** *  **** a++;
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}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include ****  *********
*  *** ***  * **** ** 

int main(int argc, char *argv[]) {

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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include * * **  *    ** 
#include   *   *      ** **

int main(int argc, char *argv[]) {

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*   * ****  * ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  *     *    * 
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int main(int argc, char *argv[]) {

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  *  * **   *  * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int    * ** argc, char    {
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***** *   * * }
*  * * ***    * 
*** ***  *      return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
*   ** *** *** **** **  * ** ** ** *  ***     your input:");
**  *    *** *****   *    ** **  * * *** **    *  ** &a);
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*   ****  *    ***** * * **   **** *   * **   *  ** *   
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
 ** * ** * * * *   *** * * ***** a;
*    **  ***     * **  * * *    ** *  * your input: ");
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**  ** *    ***  *     *  * ***********
*  **  *  * * ******* *  ******  *   *  *** ** ***   *  *** ** *****
** ** **     **    ** *  *       *  ***    ***  * *** *  * ** ****  *  **  *** ** *  *  * ||i==69 || i==73 || i==79 ||i==85){
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*      ****** *    * **** *      * ***** ** **   * *** *   ******* *  
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* ****   * *****   *   **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output